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\(a,=\left(x^2y+3\right)^2\\ b,=\left(2x+y\right)^2\\ c,=\left(5y^2-1\right)^2\)
a) \(x^2+2x+1=\left(x+1\right)^2\)
b) \(x^2+8x+16=\left(x+4\right)^2\)
c) \(x^2+6x+9=\left(x+3\right)^2\)
d) \(4x^2+4x+1=\left(2x+1\right)^2\)
e) \(36+x^2-12x=x^2-12x+36=\left(x-6\right)^2\)
f) \(4x^2+12x+9=\left(2x+3\right)^2\)
g) \(x^4+81+18x^2=x^4+18x^2+81=\left(x^2+9\right)^2\)
h) \(9x^2+30xy+25y^2=\left(3x+5y\right)^2\)
a, \(x^2\) + 2\(x\) + 1 = (\(x\) + 1)2
b, \(x^2\) + 8\(x\) + 16 = (\(x\) + 4)2
c, \(x^2\) + 6\(x\) + 9 = (\(x\) + 3)2
d, 4\(x^2\) + 4\(x\) + 1 = (2\(x\) + 1)2
a) Ta có: \(5x\left(x-9\right)-x+9\)
\(=5x\left(x-9\right)-\left(x-9\right)\)
\(=\left(x-9\right)\left(5x-1\right)\)
b) Ta có: \(6x^2+7x-3\)
\(=6x^2+9x-2x-3\)
\(=3x\left(2x-3\right)-\left(2x-3\right)\)
\(=\left(2x-3\right)\left(3x-1\right)\)
d) Ta có: \(x^2-10xy+25y^2\)
\(=x^2-2\cdot x\cdot5y+\left(5y\right)^2\)
\(=\left(x-5y\right)^2\)
c: \(x^2-4x^2y^2+y^2+2xy\)
\(=\left(x+y\right)^2-\left(2xy\right)^2\)
\(=\left(x+y+2xy\right)\left(x+y-2xy\right)\)
d: \(7x^2-14xy^2+7y^4\)
\(=7\left(x^2-2xy^2+y^4\right)\)
\(=7\left(x-y^2\right)^2\)
\(\text{a) }-x^2+10x-25\\ =-\left(x^2-10x+25\right)\\ =-\left(x-5\right)^2\)
\(\text{b) }-x^2-6x-9\\ =-\left(x^2+6x+9\right)\\ =-\left(x+3\right)^2\)
\(\text{c) }-4x^2+20xy-25y^2\\ =-\left(4x^2-20xy+25y^2\right)\\ =-\left(2x-5y\right)^2\)
\(d\text{) }!!!\)
a
\(xy+3x-7y-21\\ =\left(xy+3x\right)-\left(7y+21\right)\\ =x\left(y+3\right)-7\left(y+3\right)\\ =\left(y+3\right)\left(x-7\right)\)
b
\(2xy-15-6x+5y\\ =\left(2xy-6x\right)-\left(15-5y\right)\\ =2x\left(y-3\right)-5\left(3-y\right)\\ =2x\left(y-3\right)+5\left(y-3\right)\\ =\left(y-3\right)\left(2x+5\right)\)
c Đề phải là \(\left(2x^2y+2xy^2-x-y\right)\) mới phân tích được: )
\(=2xy\left(x+y\right)-\left(x+y\right)\\ =\left(x+y\right)\left(2xy-1\right)\)
d
\(7x^3y-3xyz-21x^2+9z\\ =\left(7x^3y-21x^2\right)-\left(3xyz-9z\right)\\ =7x^2\left(xy-3\right)-3z\left(xy-3\right)\\ =\left(xy-3\right)\left(7x^2-3z\right)\)
e
\(4x^2-2x-y^2-y\\ =\left(2x\right)^2-y^2-\left(2x+y\right)\\ =\left(2x-y\right)\left(2x+y\right)-\left(2x+y\right)\\ =\left(2x+y\right)\left(2x-y-1\right)\)
f
\(9x^2-25y^2-6x+10y\\ =\left(3x\right)^2-\left(5y\right)^2-\left(6x-10y\right)\\ =\left(3x-5y\right)\left(3x+5y\right)-2\left(3x-5y\right)\\ =\left(3x-5y\right)\left(3x+5y-2\right)\)
a: =x(y+3)-7(y+3)
=(y+3)(x-7)
b: \(=2xy-6x+5y-15\)
=2x(y-3)+5(y-3)
=(y-3)(2x+5)
c: \(=2xy\left(x+y\right)-\left(x+y\right)=\left(x+y\right)\left(2xy-1\right)\)
d: \(=xy\left(7x^2-3z\right)-3\left(7x^2-3z\right)\)
=(7x^2-3z)(xy-3)
e: =4x^2-y^2-2x-y
=(2x-y)(2x+y)-(2x+y)
=(2x+y)(2x-y-1)
f: =(3x-5y)(3x+5y)-2(3x-5y)
=(3x-5y)(3x+5y-2)
\(M=12xz-5xy=x\left(12z-5y\right)\)
\(N=64^2-49=64^2-7^2=\left(64-7\right)\left(64+7\right)\)
\(P=25y^2-16z^2=\left(5y\right)^2-\left(4z\right)^2=\left(5y-4z\right)\left(5y+4z\right)\)
\(Q=4-25y^2=2^2-\left(5y\right)^2=\left(2-5y\right)\left(2+5y\right)\)
\(R=25x^2-10x+1=\left(5x-1\right)^2\)
\(O=16-8y+y^2=\left(4-y\right)^2\)
\(X=1-6x+9x^2=\left(1-3x\right)^2\)
Sửa đề
x² - 25y² - 6x + 9
= (x² - 6x + 9) - 25y²
= (x - 3)² - (5y)²
= (x - 3 - 5y)(x - 3 + 5y)
= (x - 5y - 3)(x + 5y - 3)