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a) \(36-12x+x^2\) \(=6^2-2.6.x+x^2\)
\(=\left(6-x\right)^2\)
b) \(4x^2+12x+9=\left(2x\right)^2+2.2x.3+3^2\)
\(=\left(2x+3\right)^2\)
c) \(-25x^6-y^8+10x^3y^4=-\left[25x^6-10x^3y^4+y^8\right]\)
\(=-\left[\left(5x^3\right)^2-2.5x^3.y^4+\left(y^4\right)^2\right]\)
\(=-\left(5x^3-y^4\right)^2\)
d) \(\dfrac{1}{4}x^2-5xy+25y^2=\left(\dfrac{1}{2}x\right)^2-2.\dfrac{1}{2}x.5y+\left(5y\right)^2\)
\(=\left(\dfrac{1}{2}x-5y\right)^2\)
Học tốt~~~
a. \(36-12x+x^2=6^2-2.6.x+x^2=\left(6-x\right)^2\)
b. \(4x^2+12x+9=\left(2x\right)^2+2.2x.3+3^2=\left(2x+3\right)^2\)
c: \(=-\left(25x^6-10x^3y^4+y^8\right)\)
\(=-\left(5x^3-y^4\right)^2\)
d: \(=\left(\dfrac{1}{2}x\right)^2-2\cdot\dfrac{1}{2}x\cdot5y+\left(5y\right)^2=\left(\dfrac{1}{2}x-5y\right)^2\)
\(M=12xz-5xy=x\left(12z-5y\right)\)
\(N=64^2-49=64^2-7^2=\left(64-7\right)\left(64+7\right)\)
\(P=25y^2-16z^2=\left(5y\right)^2-\left(4z\right)^2=\left(5y-4z\right)\left(5y+4z\right)\)
\(Q=4-25y^2=2^2-\left(5y\right)^2=\left(2-5y\right)\left(2+5y\right)\)
\(R=25x^2-10x+1=\left(5x-1\right)^2\)
\(O=16-8y+y^2=\left(4-y\right)^2\)
\(X=1-6x+9x^2=\left(1-3x\right)^2\)
c: \(x^2-4x^2y^2+y^2+2xy\)
\(=\left(x+y\right)^2-\left(2xy\right)^2\)
\(=\left(x+y+2xy\right)\left(x+y-2xy\right)\)
d: \(7x^2-14xy^2+7y^4\)
\(=7\left(x^2-2xy^2+y^4\right)\)
\(=7\left(x-y^2\right)^2\)
\(a,4x^2+28x+49=\left(2x\right)^2+2.2x.7+7^2=\left(2x+7\right)^2\\ b,16y^2-8y+1=\left(4y\right)^2-2.4y.1+1^2=\left(4y-1\right)^2=\left(1-4y\right)^2\\ 4a^2+20ab+25b^2=\left(2a\right)^2+2.2a.5b+\left(5b\right)^2=\left(2a+5b\right)^2\\ d,9x^2-6xy+y^2=\left(3x\right)^2-2.3x.y+y^2=\left(3x-y\right)^2=\left(y-3x\right)^2\)
\(=81-\left(2a-5b\right)^2=\left(9-2a+5b\right)\left(9+2a-5b\right)\)
a)7x2 + 6x - 13
= 7x2 - 7x + 13x - 13
= (7x2 - 7x) + (13x - 13)
= 7x(x - 1) + 13(x - 1)
= (7x + 13)(x - 1)
b) 15(x - y) - 25x + 25y
= 15(x - y) - (25x - 25y)
= 15(x - y) - 25(x - y)
= (15 - 25)(x - y)
= -10(x - y)
c) 36 - 4a2 + 20ab - 25b2
= 36 - (4a2 - 20ab + 25b2)
= 62 - (2a - 5b)2
= (6 - 2a + 5b)(6 + 2a - 5b)
= (5b - 2a + 6)(2a - 5b + 6)
nhớ tik mik nha. Ak có j ko hiểu thì cứ bình luận ở dưới mik giải cho
a, \(7x^2+6x-13\)
=\(7x^2-7x+13x-13\)
=\(\left(7x^2-7x\right)+\left(13x-13\right)\)
=\(7x\left(x-1\right)+13\left(x-1\right)\)
=\(\left(x-1\right)\left(7x+13\right)\)