(x-5)2-36=0
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
3 tháng 10 2023
1, \(x^2\) - 9 = 0
(\(x\) - 3)(\(x\) + 3) = 0
\(\left[{}\begin{matrix}x-3=0\\x+3=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)
vậy \(x\) \(\in\) {-3; 3}
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
3 tháng 10 2023
5, 4\(x^2\) - 36 = 0
4.(\(x^2\) - 9) = 0
\(x^2\) - 9 = 0
(\(x\) - 3)(\(x\) + 3) = 0
\(\left[{}\begin{matrix}x-3=0\\x+3=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)
Vậy \(x\) \(\in\) {-3; 3}
TM
19 tháng 8 2021
1. \(4x^2-49=0\)
\(\Leftrightarrow\left(2x+7\right)\left(2x-7\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}2x+7=0\Leftrightarrow x=-\dfrac{7}{2}\\2x-7=0\Leftrightarrow x=\dfrac{7}{2}\end{matrix}\right.\)
Vậy: \(x=-\dfrac{7}{2}\) hoặc \(x=\dfrac{7}{2}\)
===========
2. \(x^2+36=12x\)
\(\Leftrightarrow x^2-12x+36=0\)
\(\Leftrightarrow\left(x-6\right)^2=0\)
\(\Leftrightarrow x=6\)
Vậy: \(x=6\)
===========
3. \(10\left(x-5\right)-8x\left(5-x\right)=0\)
\(\Leftrightarrow10\left(x-5\right)+8x\left(x-5\right)=0\)
\(\Leftrightarrow\left(x-5\right)\left(10+8x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-5=0\Leftrightarrow x=5\\10+8x=0\Leftrightarrow x=-\dfrac{5}{4}\end{matrix}\right.\)
Vậy: \(x=5\) hoặc \(x=-\dfrac{5}{4}\)
19 tháng 8 2021
1: Ta có: \(4x^2-49=0\)
\(\Leftrightarrow\left(2x-7\right)\left(2x+7\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{7}{2}\\x=-\dfrac{7}{2}\end{matrix}\right.\)
2: Ta có: \(x^2+36=12x\)
\(\Leftrightarrow x^2-12x+36=0\)
\(\Leftrightarrow\left(x-6\right)^2=0\)
\(\Leftrightarrow x-6=0\)
hay x=6
TT
1
4 tháng 11 2021
1) \(\left(5+x\right)^2-36=0\)
\(\Rightarrow\left(5+x-6\right)\left(5+x+6\right)=0\Rightarrow\left(x-1\right)\left(x+11\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=1\\x=-11\end{matrix}\right.\)
2) \(\Rightarrow\left(7x-11\right)^3=1000=10^3\)
\(\Rightarrow7x-11=10\Rightarrow7x=21\Rightarrow x=3\)
4 tháng 11 2021
\(\left(5x\right)^2-36=0\Rightarrow\left(5x\right)^2=36\)
\(\Rightarrow\left[{}\begin{matrix}5x=6\\5x=-6\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{6}{5}\\x=-\dfrac{6}{5}\end{matrix}\right.\)
29 tháng 12 2021
\(\left(5+x\right)^2-36=0\\ \Rightarrow\left(5+x\right)^2=36\\ \Rightarrow\left[{}\begin{matrix}5+x=6\\5+x=-6\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\x=-11\end{matrix}\right.\)
10 tháng 12 2021
\(a,\Leftrightarrow2x^2+10x-2x^2=12\Leftrightarrow x=\dfrac{12}{10}=\dfrac{6}{5}\\ b,\Leftrightarrow\left(5-2x-4\right)\left(5-2x+4\right)=0\\ \Leftrightarrow\left(1-2x\right)\left(9-2x\right)=0\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=\dfrac{9}{2}\end{matrix}\right.\\ c,\Leftrightarrow3x^2-3x^2+6x=36\Leftrightarrow x=6\\ d,\Leftrightarrow2\left(x+5\right)-x\left(x+5\right)=0\\ \Leftrightarrow\left(2-x\right)\left(x+5\right)=0\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-5\end{matrix}\right.\\ e,\Leftrightarrow4x^2-4x+1-4x^2+196=0\\ \Leftrightarrow-4x=-197\Leftrightarrow x=\dfrac{197}{4}\)
\(f,\Leftrightarrow x^2+8x+16-x^2+1=16\Leftrightarrow8x=-1\Leftrightarrow x=-\dfrac{1}{8}\\ g,Sửa:\left(3x+1\right)^2-\left(x+1\right)^2=0\\ \Leftrightarrow\left(3x+1-x-1\right)\left(3x+1+x+1\right)=0\\ \Leftrightarrow2x\left(4x+2\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-\dfrac{1}{2}\end{matrix}\right.\\ h,\Leftrightarrow x^2+8x-x-8=0\\ \Leftrightarrow\left(x+8\right)\left(x-1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-8\end{matrix}\right.\\ i,\Leftrightarrow2x^2-13x+15=0\\ \Leftrightarrow2x^2+2x-15x-15=0\\ \Leftrightarrow\left(x+1\right)\left(2x-15\right)=0\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=\dfrac{15}{2}\end{matrix}\right.\)
DB
4
C
28 tháng 12 2023
a)16. x2 = 64
x2 = 64 : 16
x2 = 4
x2 = 22
⇒ x = 2
b) (5.x - 2) - 64 = -36
(5.x - 2) = -36 + 64
5.x - 2 = 28
5.x = 28 + 2
5.x = 30
x = 30 : 5
x = 6
c) (2x - 10).(5 - x) = 0
TH1: 2x - 10 = 0
2x = 0 + 10
2x = 10
x = 10 : 2
x = 5
TH2: 5 - x = 0
x = 5 - 0
x = 5
⇒ Vậy x = 5.
NM
29 tháng 9 2023
\(a,96-3\left(x+8\right)=42\\ \Rightarrow3\left(x+8\right)=54\\ \Rightarrow x+8=18\\ \Rightarrow x=10.\\ b,15.5\left(x-25\right)-225=0\\ \Rightarrow75\left(x-25\right)-225=0\\ \Rightarrow75\left(x-25\right)=225\\ \Rightarrow x-25=3\\ \Rightarrow x=28.\\ c,250:x+15=25\\ \Rightarrow250:x=10\\ \Rightarrow x=25\\ d,36:\left(x-5\right)=2^2\\ \Rightarrow36:\left(x-5\right)=4\\ \Rightarrow x-5=9\\ \Rightarrow x=14.\\ e,\left[3.\left(70-x\right)+5\right]:2=46\\ \Rightarrow3.\left(70-x\right)+5=92\\ \Rightarrow3\left(70-x\right)=87\\ \Rightarrow70-x=29\\ \Rightarrow x=41.\)
TA
1 tháng 8 2017
a) \(5\left(x+3\right)-6x-2x^2=0\) \(\Leftrightarrow5.\left(x+3\right)-2x.\left(x+3\right)=0\)
\(\Leftrightarrow\left(x+3\right)\left(5-2x\right)=0\Leftrightarrow\hept{\begin{cases}x+3=0\\5-2x=0\end{cases}\Leftrightarrow\hept{\begin{cases}x=-3\\2x=5\end{cases}\Leftrightarrow}\hept{\begin{cases}x=-3\\x=\frac{5}{2}\end{cases}}}\)
b) \(6x.\left(x^2-2\right)-\left(2-x^2\right)=0\) \(\Leftrightarrow6x.\left(x^2-2\right)+\left(x^2-2\right)=0\)
\(\Leftrightarrow\left(x^2-2\right)\left(6x+1\right)=0\Leftrightarrow\hept{\begin{cases}x^2-2=0\\6x+1=0\end{cases}\Leftrightarrow\hept{\begin{cases}x^2=2\\6x=-1\end{cases}\Leftrightarrow}\hept{\begin{cases}x=\sqrt{2}\\x=\frac{-1}{6}\end{cases}}}\)
c) \(4x.\left(x-2017\right)-x+2017=0\) \(\Leftrightarrow4x.\left(x-2017\right)-\left(x-2017\right)=0\)
\(\Leftrightarrow\left(x-2017\right).\left(4x-1\right)=0\) \(\Leftrightarrow\hept{\begin{cases}x-2017=0\\4x-1=0\end{cases}\Leftrightarrow\hept{\begin{cases}x=2017\\4x=1\end{cases}\Leftrightarrow}\hept{\begin{cases}x=2017\\x=\frac{1}{4}\end{cases}}}\)
d) \(12x=x^2+36\) \(\Leftrightarrow x^2-12x+36=0\) \(\Leftrightarrow\left(x-6\right)^2=0\) \(\Rightarrow x-6=0\) \(\Leftrightarrow x=6\)
(x-5)2=36
<=>\(\orbr{\begin{cases}x-5=6\\x-5=-6\end{cases}}\)<=> \(\orbr{\begin{cases}x=11\\x=-1\end{cases}}\)
Vậy:...
\(\left(x-5\right)^2-36=0\)
\(\left(x-5\right)^2=0+36\)
\(\left(x-5\right)^2=36\)
\(\left(x-5\right)^2=\pm6^2\)
\(\Rightarrow x-5=6\text{ hoặc }x-5=-6\)
\(x=6+5\) \(x=-6+5\)
\(x=11\) \(x=-1\)
Vậy x = 11; x = -1