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Ta có: +) \({({2^2})^3} = {2^2}{.2^2}{.2^2} = {2^{2 + 2 + 2}} = {2^6}\)
+) \({\left[ {{{( - 3)}^2}} \right]^2} = {( - 3)^2}.{( - 3)^2} = {( - 3)^{2 + 2}} = {( - 3)^4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 6:
a: \(2^{27}=8^9\)
\(3^{18}=9^9\)
b: Vì \(8^9< 9^9\)
nên \(2^{27}< 3^{18}\)
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1=1^2 ;125=5^3 ;-125=-5^3; 27=27^1; -27= -27^1
2: 5^2 25^1
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a) 2.2.2.2 = \({2^4}\). Cơ số 2, số mũ 4
b) 5.5.5 = \({5^3}\). Cơ số 5, số mũ 3
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\(\left(0,0625\right)^2=\left(0,5^4\right)^2\)
\(=0,5^{4\cdot2}\)
\(=0,5^8\)
\(\left(0,0625\right)^2=\left[\left(0,5\right)^4\right]^2=\left(0,5\right)^8\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(\dfrac{1}{27}\right)^5\) = \(\left(\dfrac{1}{3^3}\right)^5\) = \(\left(\dfrac{1}{3}\right)^{15}\)
\(\left(\dfrac{1}{27}\right)^5=\left[\left(\dfrac{1}{3}\right)^3\right]^5=\dfrac{1}{3}^{3.5}=\dfrac{1}{3}^{15}\)
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\(25^6\cdot8^4\)
\(=\left(5^2\right)^6\cdot\left(2^3\right)^4\)
\(=5^{2\cdot6}\cdot2^{3\cdot4}\)
\(=5^{12}\cdot2^{12}\)
\(=\left(5\cdot2\right)^{12}\)
\(=10^{12}\)
\(25^6.8^4\)
\(=\left(5^2\right)^6.\left(2^3\right)^4\)
\(=5^{2.6}.2^{3.4}\)
\(=5^{12}.2^{12}\)
\(=\left(5.2\right)^{12}\)
\(=10^{12}\)