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104 \(\times\) 125
= 13 \(\times\) 8 \(\times\) 125
= 13 \(\times\) (8 \(\times\) 125)
= 13 \(\times\) 1000
= 13 000
b, 22 \(\times\) 45
= 2 \(\times\) 11 \(\times\) 5 \(\times\) 9
= (2 \(\times\) 5) \(\times\) (11 \(\times\) 9)
= 10 \(\times\) 99
= 990
c, 50 \(\times\) 12
= 50 \(\times\) 2 \(\times\) 6
= 100 \(\times\) 6
= 600
d, 250 \(\times\) 16
= 250 \(\times\) 4 \(\times\) 4
= 1000 \(\times\) 4
= 4000
125+125+250+250+125+125
={ 125 + 125 + 125 + 125} + {250+250}
= 500 + 500
= 1000
a) 8,8 : 2,5 + 7,6 : 2,5 - 6,4 : 2,5
= (8,8 + 7,6 - 6,4) : 2,5
= 10 : 2,5
= 4
\(a.\)
\(8.8:2.5+7.6:2.5-6.4:2.5\)
\(=\left(8.8+7.6-6.4\right):2.5\)
\(=10:2.5\)
\(=4\)
\(b.\)
\(0.25\times1200+125\times1.5\times2-250\times2.6\)
\(=250\times1.2+250\times1.5-250\times2.6\)
\(=250\times\left(1.2+1.5-2.6\right)\)
\(=250\times0.1=25\)
\(c.\)
\(\left(32\times11-3200\times0.1-32\right):\left(81.6\times27.3-17.3\times81.6\right)\)
\(=\left[32\times\left(11-10-1\right)\right]:\left[81.6\times\left(27.3-17.3\right)\right]\)
\(=0\)
( 1+3+5+7+…+2003+2005) x (125 125 x 127 – 127 127 x 125)
= ( 1+3+5+7+…+2003+2005) x (125 x 1001 x 127 – 127 x 1001x 125)
= ( 1+3+5+7+…+2003+2005) x 0 = 0
Bài 1:
a) 43+45+47+...+565 [có (565-43)/2+1= 262 số hạng)
= [(565+43)*262]/2
= 79648
b) 21+24+27+...+318 [có (318-21)/3+1= 100 số hạng]
= [(318+21)*100]/2
= 16950
101 \(\times\) 9,4 - 9,4 + 25 \(\times\) \(\dfrac{2,4}{250\%}\) \(\times\) 125% \(\times\) 32
= 9,4 \(\times\) ( 101 - 1) + 25 \(\times\) \(\dfrac{2,4}{2,5}\) \(\times\) 125% \(\times\) 8 \(\times\) 4
= 9,4 \(\times\)100 + 25 \(\times\) \(\dfrac{24}{25}\) \(\times\) 10 \(\times\) 4
= 94 \(\times\)10 + 24 \(\times\) 4 \(\times\) 10
= 10 \(\times\) ( 94 + 96)
= 10 \(\times\) 190
= 1900
( 125 x 2 - 250 ) x 45
= ( 250 - 250 ) x 45
= 0 x 45
= 0
(125x2-250)x45
= ( 250 - 250 ) x 45
= 0 x 45
= 0