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\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)
\(1\frac{1}{2};1\frac{1}{3};1\frac{1}{4};1\frac{1}{5};1\frac{1}{6};1\frac{1}{7};1\frac{1}{8}\)\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)
Vì \(\frac{1}{2}>\frac{1}{3}>\frac{1}{4}>\frac{1}{5}>\frac{1}{6}>\frac{1}{7}>\frac{1}{8}\)
=> \(1\frac{1}{2}>1\frac{1}{3}>1\frac{1}{4}>1\frac{1}{5}>1\frac{1}{6}>1\frac{1}{7}>1\frac{1}{8}\)
Hay \(\frac{3}{2}>\frac{4}{3}>\frac{5}{4}>\frac{6}{5}>\frac{7}{6}>\frac{8}{7}>\frac{9}{8}\)
\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)
\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)
\(\frac{4}{5};\frac{5}{6};\frac{7}{8};\frac{6}{5}\)
Đúng 100%
Đúng 100%
Đúng 100%
a) 1/2
b) 18/17; 17/16; 16/15; 15/14; 14/13; 13/12; 10/9
Nhớ k cho mk nha
a)1/2
b)Vì 18/17 <17/16 <16/15<15/14< 14/13< 13/12< 10/9
Nên, ta có:
18/17; 17/16; 16/15; 15/14; 14/13; 13/12; 10/9.
1.1/2 ; 2/3 ; 3/4 ; 4/5 ; 5/6 .
2. 3/2 ; 13/12 ; 7/8 ; 15/22 .
3. 4/7
4. 5/4
Ta có : \(\dfrac{4}{5}< 1\) ; \(\dfrac{4}{7}< 1\) \((\) vì có cùng tử số mà mẫu số lớn hơn thì bé hơn \()\)
\(\dfrac{2}{1}=2;\dfrac{6}{2}=3;\dfrac{9}{8}>1;\dfrac{8}{5}>1\)
\(\Rightarrow\) thứ tự từ bé đến lớn:\(\dfrac{4}{7};\dfrac{4}{5};\dfrac{9}{8};\dfrac{8}{5};\dfrac{2}{1};\dfrac{6}{2}\)
\(#Vy\)
\(\dfrac{1}{2}< \dfrac{1+1}{2+1}=\dfrac{2}{3}\)
\(\dfrac{2}{3}< \dfrac{2+1}{3+1}=\dfrac{3}{4}\)
\(\dfrac{3}{4}< \dfrac{3+1}{4+1}=\dfrac{4}{5}\)
\(\dfrac{4}{5}< \dfrac{4+1}{5+1}=\dfrac{5}{6}\)
\(\dfrac{5}{6}< \dfrac{5+1}{6+1}=\dfrac{6}{7}\)
\(\)Vậy \(\dfrac{1}{2}< \dfrac{2}{3}< \dfrac{3}{4}< \dfrac{4}{5}< \dfrac{5}{6}< \dfrac{6}{7}\)
\(\frac{3}{4}< \frac{3}{2}< \frac{5}{3}< \frac{5}{2}< \frac{6}{1}< \frac{29}{4}\)
a, 5/7 < 5/6 < 7/6 < 6/5
b, 1/2 < 5/8 < 3/4 <1
\(\dfrac{5}{7}\); \(\dfrac{5}{6}\); \(\dfrac{7}{6}\); \(\dfrac{6}{5}\)
\(\dfrac{1}{2}\) ; \(\dfrac{5}{8}\); \(\dfrac{3}{4}\); 1