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Trả lời :
A = 1 . 2 + 2 . 3 + 3 . 4 + ... + 30 . 31
=> 3A = 1 . 2 . 3 + 2 . 3 . 3 + 3 . 4 . 3 + ... + 30 . 31 . 3
=> 3A = 1 . 2 . 3 + 2 . 3 . (4 - 1) + 3 . 4 . (5 - 2) + ... + 30 . 31 . (32 - 29)
=> 3A = 1 . 2 . 3 + 2 . 3 . 4 - 1 . 2 . 3 + 3 . 4 . 5 - 2 . 3 . 4 + ... + 30 . 31 . 32 - 29 . 30 . 31
=> 3A = 30 . 31 . 32
=> 3A = 29760
=> A = 9920
a) \(A=1.2+2.3+3.4+.........+30.31\)
\(\Rightarrow3A=1.2.3+2.3.3+3.4.3+........+30.31.3\)
\(=1.2.3+2.3.\left(4-1\right)+3.4.\left(5-2\right)+.....+30.31.\left(32-29\right)\)
\(=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+......+30.31.32-29.30.31\)
\(=30.31.32\)
\(\Rightarrow A=\frac{30.31.32}{3}=9920\)
b) \(B=1+\left(1+2\right)+\left(1+2+3\right)+........+\left(1+2+...........+20\right)\)
\(=\frac{1.2}{2}+\frac{2.3}{2}+\frac{3.4}{2}+.......+\frac{20.21}{2}\)
\(=\frac{1.2+2.3+3.4+.......+20.21}{2}\)
Làm tương tự như phần a ta được:
\(1.2+2.3+3.4+.......+20.21=\frac{20.21.22}{3}=3080\)
\(\Rightarrow B=\frac{3080}{2}=1540\)
Câu 1:
Đặt S = 1.2+2.3+3.4+...+30.31
3 S = 1.2.3+2.3.3+3.4.3+...+30.31.3
3 S = 1.2.(3-0) + 2.3.(4-1) + 3.4.(5-2) + ...+ 30.31.(32-29)
3S = 1.2.3 + 2.3.4-2.3 + 3.4.5-2.3.4 + ...+ 30.31.32-29.30.31
3S= 30.31.32
S= 30.31.32/3
Đặt S=1.2+2.3+3.4+...+30.31
Ta có:
3S=1.2.3+2.3.3+3.4.3+...+30.31.3
3S=1.2.3+2.3.(4-1)+3.4.(5-2)+.....+30.31.(32-29)
3S=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+....+30.31.32-29.30.31
3S=30.31.32=30.31.32/3=9920
Nhớ
1. ta có :
\(3^2+4^2=5^{x-1}\)
\(25=5^{x-1}\)
\(5^2=5^{x-1}\)
=> x = 3
Ta có : S = 1.2 + 2.3 + 3.4 + ..... + 99.100
=> 3S = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ..... + 99.100.101
=> 3S = 99.100.101
=> S = 99.100.101/3
=> S = 333300
Xin lỗi, mk chỉ biết bài 3:
Nhân cả 2 vế với 3 ta có:
3S = 1.2.3 +2.3.3 +3.4.3 +......+ 30.31.3
3S= 1.2.3 +2.3.( 4 - 1 ) +3.4. ( 5 - 2 ) +....+ 30.31. ( 32 - 29 )
3S= 1.2.3 + 2.3.4 - 2.3.1 + 3.4.5 - 3.4.2 +.....+ 30.31.32 - 30.31.29
3S= 30.31.32
S = 30.31.32 : 3
S = 9920
Vậy S = 9920
S = 1 + 2 + 2² + 2³ + 2⁴ + ... + 2¹⁰⁰
2S = 2 + 2² + 2³ + 2⁴ + ... + 2¹⁰¹
S = 2S - S
= (2 + 2² + 2³ + ... + 2¹⁰¹) - (1 + 2 + 2² + ... + 2¹⁰⁰)
= 2¹⁰¹ - 1
------------
S = 1.2 + 2.3 + 3.4 + ... + 99.100 + 100.101
3S = 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + ... + 99.100.(101 - 98) + 100.101.(102 - 99)
= 1.2.3 - 1.2.3 + 2
3.4 - 2.3.4 + 3.4.5 - ... - 98.99.100 + 99.100.101 - 99.100.101 + 100.101.102
= 100.101.102
S = 100 . 101 . 102 : 3
= 343400
------------
Q = 1² + 2² + 3² + ... + 100² + 101²
= 101.102.(2.101 + 1) : 6
= 348551
a ta co ;
13 -12 +11+10-9+8-7-6+5-4+3+2-1
=13-(12-11-10+9) +(8-7-6+5) -(4-3-2+1)
= 13 -0+0 -0
=13