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a, x2 - 2x - 15 = x2 - 5x + 3x -15 = x.(x-5) + 3.(x-5) = (x+3).(x-5)
b, 2x3 - x2 - 6x = x.(2x2 -x -6) = x.( 2x2 + 3x - 4x -6)
=x. [ x.(2x+3) - 2.(2x+3) ] = x.(x-2).(2x+3)
c, 2x - 2y - x2 + 2xy - y2 = 2.(x-y) - ( x2 - 2xy + y2 ) = 2.(x-y) - (x-y)2 = (x - y).( 2 -x +y )
- 9y3x – 36y2x= 9xy(y2–4) =9xy(y–4)(y+4)
- 64-y^2 – x^2 – 2xy = 64– (x^2 + 2xy + y^2) = 82 – (x+y)2 = (8 – x –y)(8+x+y)
- x^2 + x – 30= x^2 + x – 25 – 5 = (x2 – 25)(x – 5)= (x-5)(x+5)(x-5)= (x-5)^2 (x+5)
a) x3-2x2-x+2
=x(x2-1)+2(-x2+1)
=x(x2-1)-2(x2-1)
=(x2-1)(x-2)
b)
x2+6x-y2+9
=x2+6x+9-y2
=(x+3)2-y2
=(x+3-y)(x+3+y)
a)\(\left(x-y\right)^2-2\left(x-y\right)+1=\left(x-y-1\right)^2\)
b)\(x^2-2y-1-2x+1-y^2=\left(x^2-2x+1\right)-\left(y^2+2y+1\right)\)
\(=\left(x-1\right)^2-\left(y+1\right)^2\)
\(=\left[\left(x-1\right)-\left(y+1\right)\right]\left[\left(x-1\right)+\left(y+1\right)\right]\)
\(=\left(x-y-2\right)\left(x+y\right)\)
c)\(x^2-y^2-2x-1=x^2-\left(y^2+2x+1\right)\)
\(=x^2-\left(y+1\right)^2\)
\(=\left(x^2-y-1\right)\left(x^2+y+1\right)\)
A. Ta có: (x - y)2 - 2(x - y)+1 = (x - y)2 - 2.(x - y).1 +12 = ( x - y - 1)2
B. Ta có: x2 - 2y -1 - 2x +1 -y2 = (x2 - y2) - (2x - 2y) -1+1 = (x - y)(x + y) - 2(x - y) = (x - y)(x + y - 2)
C. Ta có: x2 - y2 -2y -1 = x2 -(y2 - 2y -1) = x2 - ( y2 +2y1 + 1) = x2 - (y+1)2 = (x - y - 1)(x + y +1)
k cho mình nha bạn hihj!!! ~3~
a) \(2x-2y-x^2+2xy-y^2\)
\(=2\left(x-y\right)-\left(x^2-2xy+y^2\right)\)
\(=2\left(x-y\right)-\left(x-y\right)^2\)
\(=\left(x-y\right)\left(2-x+y\right)\)
b) \(9x^2+6xy+y^2-25\)
\(=\left(3x\right)^2+6xy+y^2-25\)
\(=\left(3x+y\right)^2-5^2\)
\(=\left(3x+y+5\right)\left(3x+y-5\right)\)
\(x^2+y^2-2x-2y+2xy-3\)
\(=x^2+y^2+1-2x-2y+2xy-4\)
\(=\left(x+y-1\right)^2-2^2\)
\(=\left(x+y-3\right).\left(x+y+1\right)\)
\(=x^2+y^2+1-2x-2y+2xy-4\)
\(=\left(x+y-1\right)^2-2^2\)
\(=\left(x+y-3\right).\left(x+y+1\right)\)
1/ x(y+2) -2(y+2)=(y+2)(x-2)
2/ 2(x-y) - (x-y)2 = (x-y)(2-x+y)
\(X^2-2XY+Y^2+2X-2Y\)
\(\Leftrightarrow\left(X^2-2XY+Y^2\right)+\left(2X-2Y\right)\)
\(\Leftrightarrow\left(X-Y\right)^2+2\left(X-Y\right)\)
\(\Leftrightarrow\left(X-Y\right)\left(X-Y+2\right)\)
Tk mình nhé.
\(X^2\) là mũ 2 à bạn?