Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
5x^2+10xy+5y^2
=5.(x2+2xy+y2)
=5.(x+y)2
x^3-6x^2+9x
=x.(x2-6x+9)
=x.(x-3)2
xy+y^2-x-y
=y.(x+y)-(x+y)
=(x+y)(y-1)
\(-9x^2+6x+y^2-1\)
\(=-\left(9x^2-6x+1-y^2\right)\)
\(=-\left(3x-1-y\right)\left(3x-1+y\right)\)
\(A=9x^2+3yx+6x+y+1\)
\(\Rightarrow A=\left(9x^2+3x\right)+\left(3xy+y\right)+\left(3x+1\right)\)
\(\Rightarrow A=3x\left(3x+1\right)+y\left(3x+1\right)+\left(3x+1\right)\)
\(\Rightarrow A=\left(3x+y+1\right)\left(3x+1\right)\)
x^3-9x^2+6x+16
=x^3+x^2-10x^2-10x+16x+16
=(x^3+x^2)-(10x^2+10x)+(16x+16)
=x^2(x+1)-10x(x+1)+16(x+1)
=(x+1)(x^2-10x+16)
=(x+1)(x^2-2x-8x+16)
=(x+1)[(x^2-2x)-(8x-16)]
=(x+1)[x(x-2)-8(x-2)]
=(x+1)(x-2)(x-8)
TL:
\(A=9x^2-y^2+6x+1\)
\(=\left(3x-1\right)^2-y^2\)
\(=\left(3x-1+y\right)\left(3x-1-y\right)\)
\(9x^2-6x+1\)
\(=\left(3x\right)^2-2.3x.1+1^2\)
\(=\left(3x-1\right)^2\)
\(3x^2-6x+9x^2=12x^2-6x=6x\left(2x-1\right)\)
\(x^2-y^2+6x+9\)
\(=\left(x^2+6x+9\right)-y^2\)
\(=\left(x+3\right)^2-y^2\)
\(=\left(x-y+3\right)\left(x+y+3\right)\)
\(y^2-9x^2+6x-1\)
\(=y^2-\left(3x-1\right)^2\)
\(=\left(y-3x+1\right)\left(y+3x-1\right)\)