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\(x^3+6x^2+9x=x\left(x^2+6x+9\right)=x\left(x+3\right)^2\)
\(x^3+6x^2+9x\)
\(=x\left(x^2+6x+9\right)\)
\(=x\left(x+3\right)^2\)
x^3-9x^2+6x+16
=x^3+x^2-10x^2-10x+16x+16
=(x^3+x^2)-(10x^2+10x)+(16x+16)
=x^2(x+1)-10x(x+1)+16(x+1)
=(x+1)(x^2-10x+16)
=(x+1)(x^2-2x-8x+16)
=(x+1)[(x^2-2x)-(8x-16)]
=(x+1)[x(x-2)-8(x-2)]
=(x+1)(x-2)(x-8)
1)
\(=\left(x-7\right)^2-4a^2\)
\(=\left(x-7+2a\right)\left(x-7-2a\right)\)
2)
\(=\left(3x+1\right)^2-5^2\)
\(=\left(3x+1+5\right)\left(3x+1-5\right)\)
\(=\left(3x+6\right)\left(3x-4\right)\)
\(=3\left(x+2\right)\left(3x-4\right)\)
1)x^2-14x+49-4a^2
=x^2-2x7+7^2-4a^2
=\(\left(x-7\right)^2-4a^2\)
=\(\left(x-7\right)^2-\left(2a\right)^2\)
=\(\left(\left(x-7\right)-\left(2a\right)\right).\left(\left(x-7\right)+\left(2a\right)\right)\)
=\(\left(x-7-2a\right).\left(x-7+2a\right)\)
b)
\(9x^2+6x+1-25\\ =\left(3x\right)^2-5^2+6x+1\\ =\left(\left(3x\right)-5\right).\left(\left(3x\right)+5\right)+6x+1\)
\(=\left(3x-5\right).\left(3x+5\right)+6x+1\)
a: \(2x^2+9x-35\)
\(=2x^2+14x-5x-35\)
\(=\left(x+7\right)\left(2x-5\right)\)
b: \(-6x^2+x+12\)
\(=-6x^2+9x-8x+12\)
\(=-3x\left(2x-3\right)-4\left(2x-3\right)\)
\(=\left(2x-3\right)\left(-3x-4\right)\)
Ta có
\(x^3-6x^2+x^2y+9x-3y\\ =\left(x^3-6x^2+9x\right)+\left(x^2y-3y\right)\\ =x\left(x^2-3\right)^2+y\left(x^2-3\right)\)
=(x^2-3)(x+y)
\(9x^2-6x+1\)
\(=\left(3x\right)^2-2.3x.1+1^2\)
\(=\left(3x-1\right)^2\)
9x2 - 6x +1= (3x-1)2