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\(2^x+2^{x+3}=576\Leftrightarrow2^x\left(1+2^3\right)=576\Rightarrow2^x.9=576\Rightarrow2^x=576:9=64\Rightarrow2^x=2^6\)
=> x = 6
Vậy x = 6
2x + 2x+3 = 576
2x + 2x.23 = 576
2x(1 + 23) = 576
2x.9 = 576
2x = 576 : 9
2x = 64
2x = 26
=>x = 6
5.2x+1 = 80
2x+1 = 80 : 5
2x+1 = 16
2x+1 = 24
=>x+1 = 4
x = 4 - 1
x = 3
200 - (254 : x + 3) : 2 = 262
200 - (254 : x + 3) = 262 . 2
200 - (254 : x + 3) = 524
254 : x + 3 = 200 - 524
254 : x + 3 = -324
254 : x = -327
x = 254 : (-327)
x = \(-\frac{254}{327}\)
Trả lời:
\(a,3^{x-1}+5.3^{x-1}=162\)
\(\Rightarrow3^{x-1}.\left(1+5\right)=162\)
\(\Rightarrow3^{x-1}.6=162\)
\(\Rightarrow3^{x-1}=27\)
\(\Rightarrow3^{x-1}=3^3\)
\(\Rightarrow x-1=3\)
\(\Rightarrow x=4\)
Vậy x = 4
\(b,2^{x+5}+2^{x+2}=576\)
\(\Leftrightarrow2^{\left(x+2\right)+3}+2^{x+2}=576\)
\(\Rightarrow2^{x+2}.\left(2^3+1\right)=576\)
\(\Rightarrow2^{x+2}.9=576\)
\(\Rightarrow2^{x+2}=64\)
\(\Rightarrow2^{x+2}=2^6\)
\(\Rightarrow x+2=6\)
\(\Rightarrow x=4\)
Vậy x = 4
c, x = 6
Tìm x € N :
a) 2^x + 2^x+3 = 576
<=> 2^x . 1 + 2^x . 2^3 = 576
<=> 2^x . 1 + 2^x . 8 = 576
<=> 2^x . ( 1 + 8 ) = 576
<=> 2^x . 9 = 576
<=> 2^x = 576 : 9
<=> 2^x = 64
<=> 2^x = 2^6
=> x = 64
Vậy x = 64
b) ( 9 - x )^3 - 6 = 210
<=> ( 9 - x )^3 = 210 + 6
<=> ( 9 - x )^3 = 216
<=> ( 9 - x )^3 = 6^3
=> 9 - x = 6
<=> x = 9 - 6
<=> x = 3
Vậy x = 3
ta có :
\(\left(x+5\right)^2\in\left\{13^2,18^2,24^2,27^2\right\}\)
nên \(x+5\in\left\{-27,-24,-18,-13,13,18,24,27\:\right\}\)
hay \(x\in\left\{-32.-29.-23.-18,8,13,19,22\right\}\)
1. a) \(45x-37=53\)
\(45x=90\)
\(x=2\)
vay \(x=2\)
b) \(\frac{x}{9}+500=600\)
\(\frac{x}{9}=100\)
\(\frac{x}{9}=\frac{900}{9}\)
\(\Rightarrow x=900\)
vay \(x=900\)
c) \(576-x=139\)
\(x=576-139\)
\(x=437\)
vay \(x=437\)
d) \(\left(48+x\right)-27=79\)
\(48+x=79+27\)
\(48+x=106\)
\(x=58\)
vay \(x=58\)
2. \(2^5.2^7.2^9=2^{5+7+9}=2^{21}\)
\(3^9.3^2.3=3^{9+2+1}=3^{12}\)
\(10^9:10^7=10^{10-7}=10^3\)
3). \(2.2.2.2.2.2=2^6\)
\(2.3.2.2.3.3.3=2^3.3^4\)
\(10.9.10.10.10.9.9=10^4.9^3\)
1 a) x= 720
b ) x=chín trăm
c)x= 437
d)x=58
bài2 a)= 221 b)312 c ) =102
bài 3 a)=26 b)=22 nhân 34 c )= 103 nhân chín mũ 3
\(2^{3+x}+2^x=576\)
\(\Rightarrow2^x\cdot2^3+2^x=576\)
\(\Rightarrow2^x\cdot\left(2^3+1\right)=576\)
\(\Rightarrow2^x\cdot\left(8+1\right)=576\)
\(\Rightarrow2^x\cdot9=576\)
\(\Rightarrow2^x=576:9\)
\(\Rightarrow2^x=64\)
\(\Rightarrow2^x=2^6\)
\(\Rightarrow x=6\)
Vậy $x=6$.
\(2^{3+x}+2^x=576.\)
\(2^3.2^x+2^x.1=576\)
\(2^x.\left(2^3+1\right)=576\)
\(2^x.9=576\)
\(2^x=576:9\)
\(2^x=64\)
\(2^x=2^6\)
\(\Rightarrow x=6\)