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Giải:
\(9-3\times\left(x-9\right)=6\)
\(3\times\left(x-9\right)=9-6\)
\(3\times\left(x-9\right)=3\)
\(x-9=3:3\)
\(x-9=1\)
\(x=1+9\)
\(x=10\)
\(4+6\times\left(x+1\right)=70\)
\(6\times\left(x+1\right)=70-4\)
\(6\times\left(x+1\right)=66\)
\(x+1=66:6\)
\(x+1=11\)
\(x=11-1\)
\(x=10\)
\(\dfrac{x}{13}+\dfrac{15}{26}=\dfrac{46}{52}\)
\(\dfrac{x}{13}=\dfrac{23}{26}-\dfrac{15}{26}\)
\(\dfrac{x}{13}=\dfrac{4}{13}\)
\(\Rightarrow x=4\)
\(\dfrac{11}{14}-\dfrac{3}{x}=\dfrac{5}{14}\)
\(\dfrac{3}{x}=\dfrac{11}{14}-\dfrac{5}{14}\)
\(\dfrac{3}{x}=\dfrac{3}{7}\)
\(\Rightarrow x=7\)
\(5\times\left(3+7\times x\right)=40\)
\(3+7\times x=40:5\)
\(3+7\times x=8\)
\(7\times x=8-3\)
\(7\times x=5\)
\(x=5:7\)
\(x=\dfrac{5}{7}\)
\(x\times6+12:3=120\)
\(x\times6+4=120\)
\(x\times6=120-4\)
\(x\times6=116\)
\(x=116:6\)
\(x=\dfrac{58}{3}\)
\(x\times3,7+x\times6,3=120\)
\(x\times\left(3,7+6,3\right)=120\)
\(x\times10=120\)
\(x=120:10\)
\(x=12\)
\(\left(15\times24-x\right):0,25=100:\dfrac{1}{4}\)
\(\left(360-x\right):0,25=400\)
\(360-x=400.0,25\)
\(360-x=100\)
\(x=360-100\)
\(x=260\)
\(71+65\times4=\dfrac{x+140}{x}+260\)
\(\left(x+140\right):x+260=71+260\)
\(x:x+140:x+260=331\)
\(1+140:x+260=331\)
\(140:x=331-1-260\)
\(140:x=70\)
\(x=140:70\)
\(x=2\)
\(\left(x+1\right)+\left(x+4\right)+\left(x+7\right)+...+\left(x+28\right)=155\)
\(10\times x+\left(1+4+7+...+28\right)=155\)
Số số hạng \(\left(1+4+7+...+28\right)\) :
\(\left(28-1\right):3+1=10\)
Tổng dãy \(\left(1+4+7+...+28\right)\) :
\(\left(1+28\right).10:2=145\)
\(\Rightarrow10\times x+145=155\)
\(10\times x=155-145\)
\(10\times x=10\)
\(x=10:10\)
\(x=1\)
Đều theo cách lớp 5 nha em!
\(C=\dfrac{2}{5}+\dfrac{2}{45}+...+\dfrac{2}{6885}\)
\(=\dfrac{1}{2}\left(\dfrac{4}{1\cdot5}+\dfrac{4}{5\cdot9}+\dfrac{4}{9\cdot13}+...+\dfrac{4}{81\cdot85}\right)\)
\(=\dfrac{1}{2}\left(1-\dfrac{1}{85}\right)\)
\(=\dfrac{1}{2}\cdot\dfrac{84}{85}=\dfrac{42}{85}\)
(y - \(\dfrac{1}{2}\)) : \(\left(\dfrac{1}{2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+...+\dfrac{1}{9.10}\right)\)= \(\dfrac{1}{3}\)
(y\(-\dfrac{1}{2}\)): \(\left(\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+...+\dfrac{1}{9}-\dfrac{1}{10}\right)\)= \(\dfrac{1}{3}\)
\(\left(y-\dfrac{1}{2}\right):\left(\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{10}\right)=\dfrac{1}{3}\)
\(\left(y-\dfrac{1}{2}\right):\dfrac{3}{10}=\dfrac{1}{3}\)
\(\left(y-\dfrac{1}{2}\right)=\dfrac{1}{10}\)
y = \(\dfrac{3}{5}\)
Mới thế đã hai năm trôi qua,câu trả lời từ mọi người vẫn KO XUẤT HIỆN.
Ko biết sau này câu trả lời có xuất hiện hay ko...
` a/`
` 3 1/5 : 2 1/3 : y = 12/7 `
` 48/35 : y = 12/7 `
` y = 48/35 : 12/7 `
` y = 48/35 xx 7/12 `
` y = 4/5`
Vậy ` y = 4/5`
`b/`
` 3 : y xx 3 1/2 = 2/3 xx 3/4 `
` 3 : y xx 7/2 = 1/2`
` 3 : y = 1/2 : 7/2 `
` 3 : y = 1/2 xx 2/7 `
` 3 : y = 1/7 `
` y = 3 : 1/7 `
` y = 3 xx 7`
` y = 21 `
Vậy ` y = 21 `
`c/`
` 3 2/3 - y + 1 3/4 = 2`
` 11/3 - y + 7/4 = 2 `
` 11/3 -y = 2 - 7/4`
` 11/3 - y = 1/4 `
` y = 11/3 - 1/4 `
` y = 41/12 `
Vậy ` y = 41/12`
x \(\dfrac{1}{3}\)*\(\dfrac{25}{12}\)=\(\dfrac{73}{12}\)
x \(\dfrac{1}{3}\)=\(\dfrac{73}{12}:\dfrac{25}{12}\)
x \(\dfrac{1}{3}\)=\(\dfrac{73}{25}\)
x=\(\dfrac{73}{25}:\dfrac{1}{3}\)
x=\(\dfrac{219}{25}\)
1/24 x 72/23 +1/46=7/46
9/11 +1/12 :11/24=1
4/5-1/5x5/9=29/63
giải
đường chéo T1 là
(180+24):2=102(m2)
đường chéo T2 là
180-102=78(m2)
diệnt ích mảnh đất là
\(\dfrac{102x78}{2}=3978\left(m^2\right)\)
\(\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{24}=\dfrac{8}{24}+\dfrac{4}{24}+\dfrac{2}{24}+\dfrac{1}{24}\\ =\dfrac{5}{8}\)
\(\dfrac{1}{3}\) + \(\dfrac{1}{6}\) + \(\dfrac{1}{12}\)+ \(\dfrac{1}{24}\) = \(\dfrac{8}{24}\) + \(\dfrac{4}{24}\)+ \(\dfrac{2}{24}\)+ \(\dfrac{1}{24}\) = \(\dfrac{15}{24}\) = \(\dfrac{5}{8}\)