Câu hỏi của minh châu

Question

cíuu mình vs ạ

Gấuu · Accepted Answer

a) $=x^3-8$

b) $=\left(2x\right)^3+1=8x^3+1$

c) $=1-\left(\dfrac{x}{2}\right)^3=1-\dfrac{x^3}{8}$

d) $=y^3-\left(\dfrac{x}{y}\right)^3$

a) $M=x^3+27$

b) $N=1-\left(3x\right)^3=1-27x^3$

c) $P=x^3-\left(\dfrac{1}{2}\right)^3=x^3-\dfrac{1}{8}$

d) $Q=\left(2x\right)^3+\left(3y\right)^3=8x^3+27y^3$

Câu trả lời:

a) $=x^3-8$

b) $=\left(2x\right)^3+1=8x^3+1$

c) $=1-\left(\dfrac{x}{2}\right)^3=1-\dfrac{x^3}{8}$

d) $=y^3-\left(\dfrac{x}{y}\right)^3$

a) $M=x^3+27$

b) $N=1-\left(3x\right)^3=1-27x^3$

c) $P=x^3-\left(\dfrac{1}{2}\right)^3=x^3-\dfrac{1}{8}$

d) $Q=\left(2x\right)^3+\left(3y\right)^3=8x^3+27y^3$

Nguyễn Lê Phước Thịnh · Answer

a: (x-2)(x^2+2x+4)=x^3-2^3=x^3-8

b; (2x+1)(4x^2-2x+1)

=(2x)^3+1^3

=8x^3+1

c: (1-x/2)(1+x/2+x^2/4)

=1-(x/2)^3

=1-1/8x^3

d: (y-x/y)(y^2+x+x^2/y^2)

=y^3-(x/y)^3

=y^3-x^3/y^3

a: (x+3)(x^2-3x+9)

=x^3+3^3

=x^3+27

b: (1-3x)(1+3x+9x^2)

=1^3-(3x)^3

=1-27x^3

c: (x-1/2)(x^2+1/2x+1/4)

=x^3-(1/2)^3

=x^3-1/8

d: (2x+3y)(4x^2-6xy+9y^2)

=(2x)^3+(3y)^3

=8x^3+27y^3