Câu hỏi của Hoàng Phan Thanh Thanh

Question

93/17: x+ [-4/17]: x+ 22/7: 52/3 = 4/11

Nguyễn Huy Phúc · Accepted Answer

$\dfrac{93}{17}:x+\left[\dfrac{-4}{17}\right]:x+\dfrac{22}{7}:\dfrac{52}{3}=\dfrac{4}{11}$$=>\left(\dfrac{93}{17}+\dfrac{-4}{17}\right):x+\dfrac{11}{26}=\dfrac{4}{11}$$=>\dfrac{89}{17}:x+\dfrac{11}{26}=\dfrac{4}{11}$$=>\dfrac{89}{17}:x=\dfrac{4}{11}-\dfrac{11}{26}$$=>\dfrac{89}{17}:x=\dfrac{-17}{286}$$=>x=\dfrac{89}{17}:\dfrac{-17}{286}$$=>x=\dfrac{-25454}{289}=-88\dfrac{22}{289}$ Câu trả lời: $\dfrac{93}{17}:x+\left[\dfrac{-4}{17}\right]:x+\dfrac{22}{7}:\dfrac{52}{3}=\dfrac{4}{11}$$=>\left(\dfrac{93}{17}+\dfrac{-4}{17}\right):x+\dfrac{11}{26}=\dfrac{4}{11}$$=>\dfrac{89}{17}:x+\dfrac{11}{26}=\dfrac{4}{11}$$=>\dfrac{89}{17}:x=\dfrac{4}{11}-\dfrac{11}{26}$$=>\dfrac{89}{17}:x=\dfrac{-17}{286}$$=>x=\dfrac{89}{17}:\dfrac{-17}{286}$$=>x=\dfrac{-25454}{289}=-88\dfrac{22}{289}$

ILoveMath · Answer

$\dfrac{93}{17}:x-\dfrac{4}{17}:x+\dfrac{22}{7}:\dfrac{52}{3}=\dfrac{4}{11}$$\Rightarrow\left(\dfrac{93}{17}-\dfrac{4}{17}\right):x+\dfrac{33}{182}=\dfrac{4}{11}$$\Rightarrow\dfrac{89}{17}:x=\dfrac{365}{2002}$$\Rightarrow x=\dfrac{178178}{6205}$Câu trả lời: $\dfrac{93}{17}:x-\dfrac{4}{17}:x+\dfrac{22}{7}:\dfrac{52}{3}=\dfrac{4}{11}$$\Rightarrow\left(\dfrac{93}{17}-\dfrac{4}{17}\right):x+\dfrac{33}{182}=\dfrac{4}{11}$$\Rightarrow\dfrac{89}{17}:x=\dfrac{365}{2002}$$\Rightarrow x=\dfrac{178178}{6205}$

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