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\(\dfrac{93}{17}:x+\left[\dfrac{-4}{17}\right]:x+\dfrac{22}{7}:\dfrac{52}{3}=\dfrac{4}{11}\)
\(=>\left(\dfrac{93}{17}+\dfrac{-4}{17}\right):x+\dfrac{11}{26}=\dfrac{4}{11}\)
\(=>\dfrac{89}{17}:x+\dfrac{11}{26}=\dfrac{4}{11}\)
\(=>\dfrac{89}{17}:x=\dfrac{4}{11}-\dfrac{11}{26}\)
\(=>\dfrac{89}{17}:x=\dfrac{-17}{286}\)
\(=>x=\dfrac{89}{17}:\dfrac{-17}{286}\)
\(=>x=\dfrac{-25454}{289}=-88\dfrac{22}{289}\)
(93/17+-4/17) : x + 33/182=4/11
89/17 : x = 4/11 + 33/182
89/17 : x = Sia đề
a: \(\left|x\right|-\dfrac{38}{7}\left|x\right|-\dfrac{3}{4}=2\left|x\right|-\dfrac{8}{7}\)
\(\Leftrightarrow\left|x\right|\cdot\dfrac{-45}{7}=-\dfrac{8}{7}+\dfrac{3}{4}=\dfrac{-32+21}{28}=\dfrac{-11}{28}\)
=>|x|=11/180
=>x=11/180 hoặc x=-11/180
b: \(\Leftrightarrow x\cdot\dfrac{13}{4}-\dfrac{7}{6}x=\dfrac{5}{12}+\dfrac{5}{3}\)
=>25/12x=25/12
hay x=1
a) \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{1}{10}\)
\(\dfrac{2}{3}x=\dfrac{1}{10}+\dfrac{1}{2}=\dfrac{3}{5}\)
\(x=\dfrac{3}{5}:\dfrac{2}{3}=\dfrac{9}{10}\)
b) \(\dfrac{39}{7}:x=13\)
\(x=\dfrac{\dfrac{39}{7}}{13}=\dfrac{3}{7}\)
c) \(\left(\dfrac{14}{5}x-50\right):\dfrac{2}{3}=51\)
\(\dfrac{14}{5}x-50=51\cdot\dfrac{2}{3}=34\)
\(\dfrac{14}{5}x=34+50=84\)
\(x=\dfrac{84}{\dfrac{14}{5}}=30\)
d) \(\left(x+\dfrac{1}{2}\right)\left(\dfrac{2}{3}-2x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=0\\\dfrac{2}{3}-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)
e) \(\dfrac{2}{3}x-\dfrac{1}{2}x=\dfrac{5}{12}\)
\(\dfrac{1}{6}x=\dfrac{5}{12}\)
\(x=\dfrac{5}{12}:\dfrac{1}{6}=\dfrac{5}{2}\)
g) \(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\dfrac{11}{5}-\dfrac{3}{7}=-2\)
\(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\cdot\dfrac{11}{5}=-2+\dfrac{3}{7}=-\dfrac{11}{7}\)
\(x\cdot\dfrac{44}{7}+\dfrac{3}{7}=-\dfrac{11}{7}:\dfrac{11}{5}=-\dfrac{5}{7}\)
\(\dfrac{44}{7}x=-\dfrac{5}{7}-\dfrac{3}{7}=-\dfrac{8}{7}\)
\(x=-\dfrac{8}{7}:\dfrac{44}{7}=-\dfrac{2}{11}\)
h) \(\dfrac{13}{4}x+\left(-\dfrac{7}{6}\right)x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x=\dfrac{5}{12}+\dfrac{5}{3}=\dfrac{25}{12}\)
\(x=1\)
Mỏi tay woa bn làm nốt nha!!
\(\dfrac{93}{17}:x+\dfrac{-4}{17}:x+\dfrac{22}{3}:\dfrac{52}{3}=\dfrac{4}{11}\)
\(\Rightarrow\)\((\dfrac{93}{17}+\dfrac{-4}{17}):x+\dfrac{11}{26}=\dfrac{4}{11}\)
\(\Rightarrow\)\(\dfrac{89}{17}:x+\dfrac{11}{26}=\dfrac{4}{11}\)
\(\Rightarrow\)\(\dfrac{89}{17}:x=\dfrac{4}{11}-\dfrac{11}{26}\)
\(\Rightarrow\)\(\dfrac{89}{17}:x=\dfrac{-17}{286}\)
\(\Rightarrow\)\(x=\dfrac{89}{17}:\dfrac{-17}{286}\)
\(\Rightarrow\)\(x=\dfrac{-25454}{289}=-88\dfrac{22}{289}\)