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* Trả lời:
\(\left(1\right)\) \(-3\left(1-2x\right)-4\left(1+3x\right)=-5x+5\)
\(\Leftrightarrow-3+6x-4-12x=-5x+5\)
\(\Leftrightarrow6x-12x+5x=3+4+5\)
\(\Leftrightarrow x=12\)
\(\left(2\right)\) \(3\left(2x-5\right)-6\left(1-4x\right)=-3x+7\)
\(\Leftrightarrow6x-15-6+24x=-3x+7\)
\(\Leftrightarrow6x+24x+3x=15+6+7\)
\(\Leftrightarrow33x=28\)
\(\Leftrightarrow x=\dfrac{28}{33}\)
\(\left(3\right)\) \(\left(1-3x\right)-2\left(3x-6\right)=-4x-5\)
\(\Leftrightarrow1-3x-6x+12=-4x-5\)
\(\Leftrightarrow-3x-6x+4x=-1-12-5\)
\(\Leftrightarrow-5x=-18\)
\(\Leftrightarrow x=\dfrac{18}{5}\)
\(\left(4\right)\) \(x\left(4x-3\right)-2x\left(2x-1\right)=5x-7\)
\(\Leftrightarrow4x^2-3x-4x^2+2x=5x-7\)
\(\Leftrightarrow-x-5x=-7\)
\(\Leftrightarrow-6x=-7\)
\(\Leftrightarrow x=\dfrac{7}{6}\)
\(\left(5\right)\) \(3x\left(2x-1\right)-6x\left(x+2\right)=-3x+4\)
\(\Leftrightarrow6x^2-3x-6x^2-12x=-3x+4\)
\(\Leftrightarrow-15x+3x=4\)
\(\Leftrightarrow-12x=4\)
\(\Leftrightarrow x=-\dfrac{1}{3}\)
a) \(2x\left(3x+1\right)+3x\left(4-2x\right)=7\)
\(\Rightarrow6x^2+2x+12x-6x^2=7\)
\(\Rightarrow14x=7\Rightarrow x=\frac{1}{2}\)
b) \(4\left(18-5x\right)-12\left(3x-7\right)=15\left(2x-16\right)-6\left(x+14\right)\)
\(72-20x-36x+84=30x-240-6x-84\)
\(\Rightarrow-20x-36x-30x+6x=-240-84-72-84\)
\(-80x=-480\)
x = 6
c) \(\left(3x+2\right).\left(2x+9\right)-\left(x+2\right).\left(6x+1\right)=\left(x+1\right)-\left(x-6\right)\)
\(\Rightarrow6x^2+4x+27x+18-6x^2-12x-x-2=x+1-x+6\) ( chỗ này bn tự phân tích ik nha, mk chỉ đưa ra kp sau khi phân tích thôi, ko thì viết ra dài lắm)
\(\Rightarrow18x+16=7\)
18x = -9
x = -2
18x =
a: \(\Leftrightarrow6x^2+2x+12x-6x^2=7\)
=>14x=7
hay x=1/2
b: \(\Leftrightarrow72-20x-36x+84=30x-240-6x-84\)
=>-56x+156=24x-324
=>-80x=-480
hay x=6
c: \(\Leftrightarrow6x^2+27x+4x+18-6x^2-x-12x-2=x+1-x+6=7\)
=>18x+16=7
=>18x=-9
hay x=-1/2
Bài 1:
- \(\dfrac{11}{2}x\) + 1 = \(\dfrac{1}{3}x-\dfrac{1}{4}\)
- \(\dfrac{11}{2}\)\(x\) - \(\dfrac{1}{3}\)\(x\) = - \(\dfrac{1}{4}\) - 1
-(\(\dfrac{33}{6}\) + \(\dfrac{2}{6}\))\(x\) = - \(\dfrac{5}{4}\)
- \(\dfrac{35}{6}\)\(x\) = - \(\dfrac{5}{4}\)
\(x=-\dfrac{5}{4}\) : (- \(\dfrac{35}{6}\))
\(x\) = \(\dfrac{3}{14}\)
Vậy \(x=\dfrac{3}{14}\)
Bài 2: 2\(x\) - \(\dfrac{2}{3}\) - 7\(x\) = \(\dfrac{3}{2}\) - 1
2\(x\) - 7\(x\) = \(\dfrac{3}{2}\) - 1 + \(\dfrac{2}{3}\)
- 5\(x\) = \(\dfrac{9}{6}\) - \(\dfrac{6}{6}\) + \(\dfrac{4}{6}\)
- 5\(x\) = \(\dfrac{7}{6}\)
\(x\) = \(\dfrac{7}{6}\) : (- 5)
\(x\) = - \(\dfrac{7}{30}\)
Vậy \(x=-\dfrac{7}{30}\)
Noob ơi, bạn phải đưa vào máy tính ý solve cái là ra x luôn, chỉ tội là đợi hơi lâu
a, 4.(18 - 5x) - 12(3x - 7) = 15(2x - 16) - 6(x + 14)
=> 72 - 20x - 36x + 84 = 30x - 240 - 6x - 84
=> (72 + 84) + (-20x - 36x) = (30x - 6x) + (-240 - 84)
=> 156 - 56x = 24x - 324
=> 24x + 56x = 324 + 156
=> 80x = 480
=> x = 480 : 80 = 6
Vậy x = 6
\(\left|3x-5\right|-\left|x-1\right|\) \(=6\)
Nếu \(x\le1\)
\(\Rightarrow5-3x-1+x=6\)
\(\Rightarrow4-4x=6\)
\(\Rightarrow4x=-2\)
\(\Rightarrow x=\frac{-1}{2}\left(TM\right)\)
Nếu \(1< x< \frac{5}{3}\) thì :
\(\Rightarrow5-3x-x+1=6\)
\(\Rightarrow6-4x=6\)
\(\Rightarrow4x=0\)
\(\Rightarrow x=0\left(L\right)\)
Nếu \(x\ge\frac{5}{3}\)
\(3x-5-x+1=6\)
\(\Leftrightarrow2x-4=6\)
\(\Leftrightarrow x=5\left(TM\right)\)
Vậy có 2 giá trị TM phương trình : \(x=\frac{-1}{2};x=5\)
\(\left|x-6\right|-\left|3x-1\right|\) \(=4\)
Với \(x\le\frac{1}{3}\)
\(\Rightarrow-\left(x-6\right)-\left(3x-1\right)=4\)
\(\Rightarrow-x+6-3x+1=4\)
\(\Rightarrow-x.4x=9\)
\(\Rightarrow x=2,25\left(TM\right)\)
Với \(x\ge6\)
\(\Leftrightarrow\left(x-6\right)-\left(3x-1\right)=4\)
\(\Leftrightarrow x-6-3x+1=4\)
\(\Leftrightarrow-2x=9\)
\(\Leftrightarrow x=\frac{9}{2}\left(L\right)\) [ vì x < 6 ]
Với \(\frac{1}{3}< x< 6\)
\(\Leftrightarrow-\left(x-6\right)-\left(3x-1\right)=4\)
\(\Leftrightarrow2x=-3\)
\(\Leftrightarrow x=-1,5\left(L\right)\) [ Ko TM ]
4 ) \(\left|3-2x\right|=\frac{4}{3}\)
+) \(3-2x=\frac{4}{3}\)
\(2x=3-\frac{4}{3}\)
\(2x=\frac{5}{3}\)
\(x=\frac{5}{3}:2\)
\(x=\frac{5}{3}.\frac{1}{2}\)
\(x=\frac{10}{3}\)
+) \(3-2x=-\frac{4}{3}\)
\(2x=3--\frac{4}{3}\)
\(2x=\frac{13}{3}\)
\(x=\frac{13}{3}:2\)
\(x=\frac{13}{3}.\frac{1}{2}\)
\(x=\frac{26}{3}\)
Rồi tiếp tục giải đi mk cũng giống @Đinh Tuấn Việt
vì (3x-1)^6=(3x-1)^4
=>3x-1=0 hoặc 3x-1=+-1
bạn giải nốt nhé