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6 tháng 11 2017

\(3:2:\frac{1}{4}=\frac{3}{4}:6x\)

\(6=\frac{3}{4}:6x\)

\(6x=\frac{3}{4}:6\)

\(6x=\frac{1}{8}\)

\(x=\frac{1}{8}:6\)

\(x=\frac{1}{48}\)

vậy \(x=\frac{1}{48}\)

6 tháng 11 2017

\(3:2\frac{1}{4}=\frac{3}{4}:\left(6x\right)\)

\(\Leftrightarrow3:\frac{9}{4}=\frac{3}{4}:6x\)

\(\Leftrightarrow\frac{4}{3}=\frac{3}{4}:6x\)

\(\Leftrightarrow\frac{4}{3}x=\frac{3}{4}:6\)

\(\Leftrightarrow\frac{4}{3}x=\frac{1}{8}\)

\(\Leftrightarrow x=\frac{1}{8}:\frac{4}{3}\)

\(\Leftrightarrow x=\frac{3}{32}\)

6 tháng 11 2017

\(3:2\dfrac{1}{4}=\dfrac{3}{4}:\left(6x\right)\)

\(\Leftrightarrow\dfrac{3}{4}:\left(6x\right)=3:2\dfrac{1}{4}\)

\(\Rightarrow\dfrac{3}{4}:\left(6x\right)=\dfrac{4}{3}\)

\(\Rightarrow6x=\dfrac{3}{4}:\dfrac{4}{3}=\dfrac{9}{16}\)

\(\Rightarrow x=\dfrac{9}{16}:6=\dfrac{3}{32}\)

Vậy.............

6 tháng 11 2017

3 : 9/4 = 3/4 : 6x

3. 4/9 = 3/4 : 6 : x

4/3 = 1/8 : x

x = 1/8 : 4/3 = 3/32

20 tháng 12 2016

\(2\left(\frac{1}{4}x-3\right)-\frac{5}{6}\left(6x-\frac{3}{5}\right)=-2\)

\(\frac{1}{2}x-6-5x+\frac{1}{2}=-2\)

\(\frac{1}{2}x-5x-6+\frac{1}{2}=-2\)

\(-\frac{9}{2}x-\frac{11}{2}=-2\)

\(-\frac{9}{2}x=\frac{7}{2}\)

\(x=\frac{7}{2}:\left(-\frac{9}{2}\right)\)

\(x=-\frac{7}{9}\)

 

31 tháng 3 2017

\(2.\left(\frac{1}{4}.x-3\right)-\frac{5}{6}.\left(6.x-\frac{3}{5}\right)=-2\)

<=>\(\frac{2}{4}.x-6-\frac{30}{6}.x+\frac{15}{30}=-2\)

<=>\(\frac{1}{2}.x-6-5.x+\frac{1}{2}=-2\)

<=>\(-4,5.x=-2-\frac{1}{2}+6\)

<=>\(-4,5.x=\frac{7}{2}\)

bài này mới làm đúng nhé. bài trên mình tính sai ạ.

<=>\(x=\frac{-7}{9}\)

31 tháng 3 2017

Nhân phân phối -> rút gọn -> chuyển x 1 bên, số 1 bên

9 tháng 7 2016

có ai giúp mình không mình tích cho

9 tháng 7 2016

a) \(3:2\frac{1}{2}=\frac{3}{4}:\left(6x\right)\)

\(3:\frac{5}{2}=\frac{3}{24x}\)

\(\frac{6}{5}=\frac{3}{24x}\)

\(24x=3:\frac{6}{5}\)

\(24x=\frac{5}{2}\)

\(x=\frac{5}{2}:24\)

\(x=\frac{5}{48}\)

b) \(\frac{x}{3}:\frac{2}{3}=1\frac{3}{4}:\frac{2}{5}\)

\(\frac{3x}{6}=\frac{35}{8}\)

\(3x=\frac{35}{8}\cdot6\)

\(3x=\frac{105}{4}\)

\(x=\frac{105}{4}:3\)

\(x=\frac{35}{4}\)

...
Đọc tiếp

\(\left(\frac{-5}{12}+\frac{7}{4}-\frac{3}{8}\right)-\left[4\frac{1}{2}-7\frac{1}{3}\right]-\left(\frac{1}{4}-\frac{5}{2}\right)\)

\(\left[2\frac{1}{4}-5\frac{3}{2}\right]-\left(\frac{3}{10}-1\right)-5\frac{1}{2}+\left(\frac{1}{3}-\frac{5}{6}\right)\)

\(\frac{4}{7}-\left(3\frac{2}{5}-1\frac{1}{2}\right)-\frac{5}{21}+\left[3\frac{1}{2}-4\frac{2}{3}\right]\)

\(\frac{1}{8}-1\frac{3}{4}+\left(\frac{7}{8}-3\frac{7}{2}+\frac{3}{4}\right)-\left[\frac{7}{4}-\frac{5}{8}\right]\)

\(\left(\frac{3}{5}-2\frac{1}{10}+\frac{11}{20}\right)-\left[\frac{-3}{4}+1\frac{7}{2}\right]\)

\(\left[-2\frac{1}{5}-2\frac{2}{3}\right]-\left(\frac{1}{15}-5\frac{1}{2}\right)+\left[\frac{-1}{6}+\frac{1}{3}\right]\)

\(1\frac{1}{8}-\left(\frac{1}{15}-\frac{1}{2}+\frac{-1}{6}\right)+\left[\frac{5}{4}+\frac{3}{2}\right]\)

\(\frac{5}{6}-\left(1\frac{1}{3}-1\frac{1}{2}\right)+\left[\frac{5}{12}-\frac{3}{4}-\frac{1}{6}\right]\)

\(1\frac{1}{4}-\left(\frac{7}{12}-\frac{2}{3}-1\frac{3}{8}\right)+\left[\frac{5}{24}-2\frac{1}{2}\right]-\frac{1}{6}-\left[\frac{-3}{4}\right]\)

\(-2\frac{1}{5}+2\frac{3}{10}-\left(\frac{6}{20}-\left[\frac{2}{8}-1\frac{1}{2}\right]\right)+\left[\frac{7}{20}-1\frac{1}{4}\right]\)

\(-\left[1\frac{2}{3}-3\frac{1}{2}+\frac{1}{4}\right]+\left(\frac{2}{6}-\frac{5}{12}\right)-\left(\frac{1}{3}-\left[\frac{1}{4}-\frac{1}{3}\right]\right)\)

\(-\frac{4}{5}-\left(1\frac{1}{10}-\frac{7}{10}\right)+\left[\frac{3}{4}-1\frac{1}{5}\right]+1\frac{1}{2}\)

\(\frac{3}{21}-\frac{5}{14}+\left[1\frac{1}{3}-5\frac{1}{2}+\frac{5}{14}\right]-\left(\frac{1}{6}-\frac{3}{7}+\frac{1}{3}\right)\)

\(-1\frac{2}{5}+\left[1\frac{3}{10}-\frac{7}{20}-1\frac{1}{4}\right]-\left(\frac{1}{5}-\left[\frac{3}{4}-1\frac{1}{2}\right]\right)\)

\(2\frac{1}{3}-\left(\frac{1}{2}-2\frac{1}{6}+\frac{3}{4}\right)+\left[\frac{5}{12}-1\frac{1}{3}\right]-\frac{7}{8}+3\frac{1}{2}\)

\(2\frac{1}{4}-1\frac{3}{5}-\left(\frac{9}{20}-\frac{7}{10}\right)+\left[1\frac{3}{5}-2\frac{1}{2}\right]+\frac{3}{4}\)

\(\left[\frac{8}{3}-5\frac{1}{4}+\frac{1}{6}\right]-\frac{7}{4}+\frac{-5}{12}-\left(1-1\frac{1}{2}+\frac{1}{3}\right)\)

\(\left(\frac{1}{4}-\left[1\frac{1}{4}-\frac{7}{10}\right]+\frac{1}{2}\right)-2\frac{1}{5}-1\frac{3}{10}+\left[1-\frac{1}{2}\right]\)

TRÌNH BÀY GIÚP MÌNH NHA 

0
26 tháng 7 2016

\(3:2\frac{1}{4}=\frac{3}{4}:\left(6x\right)\)

\(3:\frac{9}{4}=\frac{3}{4}.6x\)

\(3.\frac{4}{9}=\frac{9}{2}x\)

\(\frac{4}{3}=\frac{9}{2}x\)

\(x=\frac{4}{3}:\frac{9}{2}=\frac{4}{3}.\frac{2}{9}=\frac{8}{27}\)

26 tháng 7 2016

Ta có : 6x = \(2\frac{1}{4}.\frac{3}{4}:3=\frac{9}{16}\)

\(\Rightarrow x=\frac{9}{16}:6=\frac{3}{32}\)

...
Đọc tiếp

\(3\frac{1}{2}-4\frac{2}{3}+\left[\frac{3}{4}-2\frac{1}{3}\right]-\left(\frac{5}{6}-\frac{7}{4}\right)+5\frac{1}{2}-3\)

\(2\frac{2}{3}-1\frac{2}{5}+1\frac{3}{10}-\left(\frac{2}{5}-\frac{5}{6}\right)+\frac{4}{15}-1\frac{1}{3}\)

\(\left[2\frac{1}{3}-1\frac{4}{3}\right]-\left(\frac{5}{4}-\frac{7}{12}+\frac{-11}{6}\right)+\frac{4}{3}-\frac{3}{4}\)

\(-3\frac{3}{2}+5\frac{4}{3}-\left(\frac{7}{6}-1\frac{3}{4}\right)+\left[\frac{2}{3}-2\frac{1}{4}\right]\)

\(2\frac{2}{3}-\frac{5}{12}-\left(1\frac{3}{4}-2\frac{1}{4}\right)-\left[1-1\frac{1}{6}\right]+\left[\frac{-5}{3}\right]\)

\(1\frac{1}{3}-5\frac{1}{2}-\left[\frac{5}{6}-2\frac{2}{3}\right]+\left[\frac{7}{12}-\frac{5}{6}\right]\)

\(\frac{8}{15}-\left(\frac{2}{5}-3\frac{1}{3}+\left[\frac{-5}{6}\right]\right)+\left[\frac{1}{2}-\frac{4}{5}\right]-\left(\frac{1}{6}-1\frac{1}{3}\right)\)

\(-2\frac{3}{2}+\left[\frac{5}{6}-1\frac{1}{3}\right]-\left(\frac{5}{12}-\frac{7}{6}\right)+\left[\frac{4}{3}-3\frac{1}{4}\right]\)

\(\frac{9}{10}-1\frac{2}{5}-\left(\frac{5}{6}-3\frac{1}{2}\right)-\left[2\frac{1}{4}-5\frac{2}{36}\right]-\left[1-2\frac{1}{15}\right]\)

\(\frac{5}{7}-\frac{5}{21}+1\frac{2}{3}-\left(1\frac{1}{2}-\frac{5}{14}-\frac{1}{3}\right)+\left[\frac{1}{6}-\frac{4}{3}\right]\)

\(\frac{5}{7}-\frac{5}{21}+1\frac{2}{3}-\left(1\frac{1}{2}-\frac{5}{14}-\frac{1}{3}\right)+\left[\frac{1}{6}-\frac{4}{3}\right]\)

\(1\frac{1}{5}-\left(\frac{-9}{10}-2\frac{1}{2}+\frac{3}{4}\right)+\left[\frac{1}{5}-2\frac{1}{2}\right]+\frac{7}{10}-\left(\frac{1}{2}-\frac{1}{4}\right)\)

\(2\frac{1}{3}-\left(5\frac{1}{2}-2\frac{2}{3}\right)+\left[1\frac{1}{6}-2\frac{1}{2}\right]-\frac{5}{12}+\left(\frac{1}{4}-\frac{1}{8}\right)\)

 

 

 

 

 

 

 

 

2
19 tháng 6 2018
  1. ​29/15
  2. 23
  3. 23/12
  4. 5/6
  5. 5/4
  6. -31/12
  7. 31/6
  8. -13/3
  9. 1087/180
  10. 1/6
  11. 1/6
  12. 2
  13. -67/24
11 tháng 4 2022
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