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8 tháng 7

\(\dfrac{1}{2}-\dfrac{43}{101}+\left(-\dfrac{1}{3}\right)-\dfrac{1}{6}\)

\(=\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}+\left(-\dfrac{43}{101}\right)\)

\(=0+\left(-\dfrac{43}{101}\right)\)

\(=-\dfrac{43}{101}\)

8 tháng 7

\(\dfrac{1}{2}-\dfrac{43}{101}+\left(-\dfrac{1}{3}\right)-\dfrac{1}{6}\\ =\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)-\dfrac{43}{101}\\ =\left(\dfrac{3}{6}-\dfrac{2}{6}-\dfrac{1}{6}\right)-\dfrac{43}{101}\\ =\dfrac{0}{6}-\dfrac{43}{101}\\ =-\dfrac{43}{101}\)

155,9:4,5=34 dư 29

87,5:1,75=50

52:1,6=32,5

45,6:32=1,425

15 tháng 7 2017

26 tháng 6 2018

Giải:

\(\dfrac{1}{2}-\dfrac{43}{100}+\left(-\dfrac{1}{3}\right)-\dfrac{1}{6}\)

\(=-\dfrac{43}{100}+\dfrac{1}{2}+\left(-\dfrac{1}{3}\right)-\dfrac{1}{6}\)

\(=-\dfrac{43}{100}+\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\)

\(=-\dfrac{43}{100}+\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)\)

\(=-\dfrac{43}{100}+\left(\dfrac{3}{6}-\dfrac{2}{6}-\dfrac{1}{6}\right)\)

\(=-\dfrac{43}{100}+0=-\dfrac{43}{100}\)

Vậy ...

11 tháng 7 2016

\(\frac{1}{2}-\frac{43}{101}+\frac{-1}{3}-\frac{1}{6}\)

\(=\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)+\left(-\frac{43}{101}\right)\)

\(=\frac{3-2-1}{6}+\frac{-43}{101}\)

\(=0+\frac{-43}{101}\)

\(=-\frac{43}{101}\)

11 tháng 7 2016

1/2-1/3=1/6 suy ra tổng trên = -43/101

9 tháng 9 2021

\(\dfrac{1}{2}-\dfrac{43}{101}+\dfrac{-1}{3}-\dfrac{1}{6}\\ =\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)-\dfrac{43}{101}=0-\dfrac{43}{101}=-\dfrac{43}{101}\)

28 tháng 7 2023

\(\left(1-\dfrac{1}{2}\right).\left(1-\dfrac{1}{3}\right).\left(1-\dfrac{1}{4}\right).....\left(1-\dfrac{1}{2004}\right)\)

\(=\dfrac{1}{2}.\dfrac{2}{3}.\dfrac{3}{4}....\dfrac{2002}{2003}.\dfrac{2003}{2004}\)

\(=\dfrac{1}{2004}\)

28 tháng 4 2018

\(11\div\left\{\frac{7}{8}-3\cdot\left[0,25\div\left(1\frac{1}{3}+2\cdot\frac{1}{3}\right)\right]\right\}\)

\(=11\div\left\{\frac{7}{8}-3\cdot\left[\frac{1}{4}\div\left(\frac{4}{3}+2\cdot\frac{1}{3}\right)\right]\right\}\)

\(=11\div\left\{\frac{7}{8}-3\cdot\left[\frac{1}{4}\div\left(\frac{4}{3}+\frac{2}{3}\right)\right]\right\}\)

\(=11\div\left\{\frac{7}{8}-3\cdot\left[\frac{1}{4}\div2\right]\right\}\)

\(=11\div\left\{\frac{7}{8}-3\cdot\frac{1}{8}\right\}\)

\(=11\div\left\{\frac{7}{8}-\frac{3}{8}\right\}\)

\(=11\div\frac{1}{2}\)

\(=22\)

28 tháng 4 2018

b) 101*789 + 456*128 - 789 + 912*436

= 789*100 + 456*128 + 912*436

= 789*100 + 912*64 + 912*436

= 789*100 + 912*500

= 100*(789 + 912*5)

= 100*5349

= 534900

αi nhanh mình sẽ Tick ạ.

9 tháng 4 2023

A = \(\dfrac{3^{100}.\left(-2\right)+3^{101}}{\left(-3\right)^{101}-3^{100}}\) 

A = \(\dfrac{3^{100}.\left(-2\right)+3^{100}.3}{\left(-3\right)^{100}.\left(-3\right)-3^{100}}\)

A = \(\dfrac{3^{100}.\left(-2+3\right)}{3^{100}.\left(-3\right)-3^{100}}\)

A = \(\dfrac{3^{100}.1}{3^{100}.\left(-3-1\right)}\)

A = \(\dfrac{3^{100}}{3^{100}}\) . \(\dfrac{1}{-4}\)

A = - \(\dfrac{1}{4}\)