x(x+1)=272 x=?
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(x+1)+(x+3)+(x+7)+......(x+24)+(x+31)=272
=>(x+x+...+x)+(1+3+...+31)=272
=>6x+76=272
=>6x=196
=>x=... đề sai
\(1,\sqrt{3}x-3=\sqrt{27}\)
\(\Leftrightarrow\sqrt{3}x-3=3\sqrt{3}\)
\(\Leftrightarrow\sqrt{3}\left(x-\sqrt{3}\right)=3\sqrt{3}\)
\(\Leftrightarrow x-\sqrt{3}=3\)
\(\Leftrightarrow x=3+\sqrt{3}\)
\(2,\sqrt{2}x-\sqrt{28}=\sqrt{32}\)
\(\Leftrightarrow\sqrt{2}x-2\sqrt{7}=4\sqrt{2}\)
\(\Leftrightarrow\sqrt{2}x=4\sqrt{2}+2\sqrt{7}\)
\(\Leftrightarrow x=\dfrac{\sqrt{2^2}\left(2\sqrt{2}+\sqrt{7}\right)}{\sqrt{2}}\)
\(\Leftrightarrow x=\sqrt{2}\left(2\sqrt{2}+\sqrt{7}\right)\)
\(\Leftrightarrow x=4+\sqrt{14}\)
\(3,\sqrt{6}x-2\sqrt{6}=\sqrt{54}\)
\(\Leftrightarrow\sqrt{6}\left(x-2\right)=3\sqrt{6}\)
\(\Leftrightarrow x-2=3\)
\(\Leftrightarrow x=5\)
\(4,\sqrt{3}x-\sqrt{2}x=\sqrt{3}+\sqrt{2}\)
\(\Leftrightarrow\left(\sqrt{3}-\sqrt{2}\right)x=\sqrt{3}+\sqrt{2}\)
\(\Leftrightarrow x=\dfrac{\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}}\)
a) \(\left(x+1\right)\left(x+2\right)=272\)
\(\Rightarrow x^2+3x+2=272\)
\(\Rightarrow x^2+3x-270=0\)
\(\Rightarrow x^2+18x-15x-270=0\)
\(\Rightarrow x\left(x+18\right)-15\left(x+18\right)=0\)
\(\Rightarrow\left(x+18\right)\left(x-15\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x+18=0\\x-15=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-18\\x=15\end{matrix}\right.\)
d) \(\left(x+4\right)\left(x+5\right)=552\)
\(\Rightarrow x^2+9x+20=552\)
\(\Rightarrow x^2+9x-532=0\)
\(\Rightarrow x^2+28x-19x-532=0\)
\(\Rightarrow x\left(x+28\right)-19\left(x+28\right)=0\)
\(\Rightarrow\left(x+28\right)\left(x-19\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x+28=0\\x-19=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-28\\x=19\end{matrix}\right.\)
\(\left(35+x\right)-12=27\\ 35+x=27+12=39\\ x=39-35=4\\ ---\\ 2x-5=3^3:3^2=3\\ 2x=3+5=8\\ x=\dfrac{8}{2}=4\)
1) (35 + x) -12 =27
=>35 + x = 39 => x = 4
2) 2x -5 = 33 : 32
=> 2x -5 =31 => 2x = 8
=> x = 4
`@` `\text {Ans}`
`\downarrow`
`a,`
\(\text{326 x 728 + 327 x 272}\)
`= 326 \times 728 + 326 \times 272 + 272`
`= 326 \times (728 + 272) + 272`
`= 326 \times 1000 + 272`
`= 362000 + 272`
`= 362272`
`b,`
\(\text{2008 x 867 + 2009 x 133}\)
`= 2008 \times 867 + 2008 \times 133 + 133`
`= 2008 \times (867 + 133) + 133`
`= 2008 \times 1000 + 133`
`= 2008000 + 133`
`= 2008133`
`c,`
\(\text{1235 x 6789 x (630 - 315 x 2 )}\)
`= 1235 \times 6789 \times (630 - 630)`
`= 1235 \times 6789 \times 0`
`= 0`
`d,`
\((m \div 1 - m \times 1 ) \div ( m \times 2008 + m + 2008)\)
`= (m - m) \div (m \times 2008 + m + 2008)`
`= 0 \div (m \times 2008 + m + 2008)`
`= 0`
a: =326*728+326*272+272
=326000+272
=326272
c: \(=1235\cdot6789\cdot\left(630-630\right)=0\)
d: \(=\left(m-m\right):\left(20009m+2008\right)=0\)
\(272+\left(146+x\right)=118\)
\(272+146+x=118\)
\(418+x=118\)
\(x=118-418\)
\(x=-300\)
\(a,\Rightarrow x=-8-3=-11\\ b,\Rightarrow35+x-12=27\\ \Rightarrow x=4\\ c,\Rightarrow2^x=16=2^4\Rightarrow x=4\)
\(x\left(x+1\right)\) = 272
\(x^2\) + \(x\) = 272
\(x^2\) + \(x\) - 272 = 0
\(x^2\) + 17\(x\) - 16\(x\) - 272 = 0
(\(x^2\) + 17\(x\)) - (16\(x\) + 272) = 0
\(x\left(x+17\right)\) - 16.(\(x\) + 17) = 0
\(\left(x+17\right)\)(\(x-16\)) = 0
\(\left[{}\begin{matrix}x+17=0\\x-16=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-17\\x=16\end{matrix}\right.\)
Vậy \(x\in\) {-17; 16}