3/2 x x - 2/7 x < x -7/2> = 18
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a) 8697-(37:35+2(13-3)
=8697-(32+2.13-2.3)
=8697-(9+26-6)
=8697-29
=8668
b) 2010-2000:(486-2(72-6))
=2010-2000:(486-(2.49-2.6))
=2010-2000:(486-(98-12)
=2010-2000:400
=2010-5
=2005
c)718:716+22.33.32.5-22.7+83
=(718:716)+(22.33.32)-(22.7)+83
=49+972-28+83
=1076
nhớ tích nha bạn ^-^
x + 37,5 + x * 2 = 11.9
1/3 + x/3 * 1/6 = 7/18
4/7 : x * 3/2 + 1/7 = 13/7
Câu hỏi tương tự Đọc thêmToán lớp 5a, \(\dfrac{7}{18}x-\dfrac{2}{3}=\dfrac{5}{18}\)
\(\dfrac{7}{18}x=\dfrac{5}{18}+\dfrac{2}{3}\)
\(\dfrac{7}{18}x=\dfrac{17}{18}\)
\(x=\dfrac{17}{18}\div\dfrac{7}{18}\)
\(x=\dfrac{17}{7}\)
a) \(\dfrac{7}{18}\).x-\(\dfrac{2}{3}\)=\(\dfrac{5}{18}\)
\(\dfrac{7}{18}\).x =\(\dfrac{5}{18}\)+\(\dfrac{2}{3}\)
\(\dfrac{7}{18}\).x = \(\dfrac{17}{18}\)
x = \(\dfrac{17}{18}\) :\(\dfrac{7}{18}\)
x =\(\dfrac{17}{7}\)
b)\(\dfrac{4}{9}\) - \(\dfrac{7}{8}\).x =\(\dfrac{-2}{3}\)
\(\dfrac{7}{8}\).x =\(\dfrac{4}{9}\)-\(\dfrac{-2}{3}\)
\(\dfrac{7}{8}\).x =\(\dfrac{10}{9}\)
x =\(\dfrac{10}{9}\) : \(\dfrac{7}{8}\)
x =\(\dfrac{80}{63}\)
c)\(\dfrac{1}{6}\)+\(\dfrac{-5}{7}\): \(\dfrac{-7}{18}\)
\(\dfrac{1}{6}\)+\(\dfrac{90}{49}\)
\(\dfrac{589}{294}\)
a) x= 1/4
b) x= -7/144
c) x= 25/6
d) x=17/7
e) x= 80/63
f) x= -45/14
Lời giải:
$=\frac{16}{21}+\frac{2}{9}-\frac{2}{21}+\frac{3}{9}$
$=(\frac{16}{21}-\frac{2}{21})+(\frac{2}{9}+\frac{3}{9})$
$=\frac{14}{21}+\frac{5}{9}=\frac{2}{3}+\frac{5}{9}=\frac{11}{9}$
a)2(x - 2) + 7.(3 - x) = -2.(3x - 18)
=> 2x - 4 + 21 - 7x = -6x - 36
=> 2x - 7x + 6x = 36 - 21 + 4
=> x = 19
a) 3 . (x + 7) + 2 . (x - 5) = 26
3x + 21 + 2x - 10 = 26
5x = 26 - 21 + 10
5x = 15
x = 3
b) 15 . (x - 3) - 7 = 10 . (x -2) + 3
15x - 45 - 7 = 10x - 20 + 3
15x - 10x = -17 + 45 + 7
5x = 35
x = 7
c) 3 . (x + 5) - 2 . (x -7) = 18
3x + 15 - 2x + 14 = 18
x = 18 - 15 - 14
x = -11
\(\dfrac{3}{2}.x-\dfrac{2}{7}.x< x-\dfrac{7}{2}\ge18\)
\(\Rightarrow\left\{{}\begin{matrix}x-\dfrac{7}{2}>\dfrac{3}{2}.x-\dfrac{2}{7}.x\\x-\dfrac{7}{2}\ge18\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x-\dfrac{3}{2}.x+\dfrac{2}{7}.x>\dfrac{7}{2}\\x\ge18+\dfrac{7}{2}\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}\left(1-\dfrac{3}{2}+\dfrac{2}{7}\right).x>\dfrac{7}{2}\\x\ge\dfrac{36}{2}+\dfrac{7}{2}\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}\left(\dfrac{14}{14}-\dfrac{21}{14}+\dfrac{4}{14}\right).x>\dfrac{7}{2}\\x\ge\dfrac{43}{2}\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}\left(-\dfrac{3}{14}\right).x>\dfrac{7}{2}\\x\ge\dfrac{43}{2}\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x< \dfrac{7}{2}:\left(-\dfrac{3}{14}\right)\\x\ge\dfrac{43}{2}\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x< \dfrac{7}{2}.\left(-\dfrac{14}{3}\right)\\x\ge\dfrac{43}{2}\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x< -\dfrac{49}{3}\\x\ge\dfrac{43}{2}\end{matrix}\right.\) \(\Rightarrow x\in\varnothing\)
Bài toán này kiến thức vượt lớp 5 (dấu . là dấu nhân)
giiups tui nhanh nhanh