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a) Ta có: ( x+5) + (2x+7)+(3x+9) = 57
=> (x+2x+3x)+(5+7+9) = 57
=> 6x + 21 = 57
=> 6x = 57 - 21
=> 6x = 36
=> x = 36 : 6
=> x = 6
b) x + 1245 = (3+7+11+...+95)
=> x + 1245 = [(95-3):4+1] x (95+3) : 2
=> x + 1245 = 1176
=> x = 1176 - 1245
=> x = -69
CHÚC BẠN HỌC TỐT
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Ta có \(x.\frac{7}{8}-x.\frac{3}{4}=\frac{2}{3}\)
\(\Rightarrow x.\left(\frac{7}{8}-\frac{3}{4}\right)=\frac{2}{3}\)
\(\Rightarrow x.\frac{1}{8}=\frac{2}{3}\)
\(\Rightarrow x=\frac{2}{3}.8\)
\(\Rightarrow x=\frac{16}{3}\)
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x/12 = 3/x
Ta có :
x*x = 12*3
x*x=36
Vậy :
x=6
x/5<12/25
ta có :
x/5*5<12/25
x/25<12/25
Vậy :
x=1,2,..,11
7/x>21/11
Ta có :
21/x < 21/11
Suy ra để 7/x>21/11 thì x < 11
x = 10,9,...,1
284,34<Xx2<285,1 (câu này mình nghĩ hơi nhiều vì 1 số thập phân nó có thể kéo dài như này : 0,99999999999..)
*Hộ câu cuối nè !!!
284,34 < x.2 < 285,1
Ta có :
142,17 . 2 < x.2 < 142,55 . 2
=> x = 142,18 ; 142,19 ; 142,20 ; 142,21 ; ... ; 142,54
#Tường Vy ( Ninh Nguyễn )
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x + 37,5 + x * 2 = 11.9
1/3 + x/3 * 1/6 = 7/18
4/7 : x * 3/2 + 1/7 = 13/7
Câu hỏi tương tự Đọc thêm![](https://rs.olm.vn/images/avt/0.png?1311)
bài2 \(x\times\dfrac{15}{16}-x\times\dfrac{4}{16}=2\)
\(x\times\dfrac{11}{16}=2\)
\(x=2:\dfrac{11}{16}\)
\(x=\dfrac{32}{11}\)
Bài 1 :
\(\dfrac{x}{16}\times\left(2017-1\right)=2\)
\(\dfrac{x}{16}\times2016=2\)
\(\dfrac{x}{16}=\dfrac{2}{2016}\)
\(x=\dfrac{2}{2016}\times16\)
\(x=\dfrac{1}{63}\)
\(\dfrac{3}{2}.x-\dfrac{2}{7}.x< x-\dfrac{7}{2}\ge18\)
\(\Rightarrow\left\{{}\begin{matrix}x-\dfrac{7}{2}>\dfrac{3}{2}.x-\dfrac{2}{7}.x\\x-\dfrac{7}{2}\ge18\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x-\dfrac{3}{2}.x+\dfrac{2}{7}.x>\dfrac{7}{2}\\x\ge18+\dfrac{7}{2}\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}\left(1-\dfrac{3}{2}+\dfrac{2}{7}\right).x>\dfrac{7}{2}\\x\ge\dfrac{36}{2}+\dfrac{7}{2}\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}\left(\dfrac{14}{14}-\dfrac{21}{14}+\dfrac{4}{14}\right).x>\dfrac{7}{2}\\x\ge\dfrac{43}{2}\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}\left(-\dfrac{3}{14}\right).x>\dfrac{7}{2}\\x\ge\dfrac{43}{2}\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x< \dfrac{7}{2}:\left(-\dfrac{3}{14}\right)\\x\ge\dfrac{43}{2}\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x< \dfrac{7}{2}.\left(-\dfrac{14}{3}\right)\\x\ge\dfrac{43}{2}\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x< -\dfrac{49}{3}\\x\ge\dfrac{43}{2}\end{matrix}\right.\) \(\Rightarrow x\in\varnothing\)
Bài toán này kiến thức vượt lớp 5 (dấu . là dấu nhân)
giiups tui nhanh nhanh