2/3x9/300=?
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\(\left(\dfrac{1}{3}\right)^2\cdot\dfrac{1}{3\cdot9^2}=\dfrac{1}{9\cdot3\cdot9^2}=\dfrac{1}{3^7}\)
Trl:
3 x 9 + 6 x 3 + 5 : 2 - 6 + 9 x 3 - 2
= 27 + 18 + 2,5 - 6 + 27 - 2
= 66,5
#HuyềnAnh#
Trl :
3 x 9 + 6 x 3 + 5 : 2 - 6 + 9 x 3 - 2
= 27 + 18 + 2,5 - 6 + 27 - 2
= 45 + 2,5 - 6 + 27 - 2
= 66,5
_ Jie _
a, 25 \(\times\)66 + 33 \(\times\) 25 + 25
= 25 \(\times\) 66 + 33 \(\times\) 25 + 25 \(\times\)1
= 25 \(\times\) ( 66 + 33 + 1)
= 25 \(\times\) ( 66 + 34)
= 25\(\times\) 100
2500
\(\dfrac{2}{3}\) \(\times\) \(\dfrac{9}{7}\) + \(\dfrac{4}{6}\) \(\times\) \(\dfrac{5}{7}\) - \(\dfrac{2}{3}\)
= \(\dfrac{2}{3}\) \(\times\) \(\dfrac{9}{7}\) + \(\dfrac{2}{3}\) \(\times\) \(\dfrac{5}{7}\) - \(\dfrac{2}{3}\) \(\times\) 1
= \(\dfrac{2}{3}\) \(\times\) ( \(\dfrac{9}{7}\) + \(\dfrac{5}{7}\) - 1)
= \(\dfrac{2}{3}\) \(\times\) ( 2 - 1)
= \(\dfrac{2}{3}\) \(\times\) 1
= \(\dfrac{2}{3}\)
\(2x^7=3x^9\\ \Rightarrow\dfrac{x^7}{x^9}=\dfrac{3}{2}\\ \Leftrightarrow\dfrac{1}{x^2}=\dfrac{3}{2}\\ \Leftrightarrow3x^2=2\\ \Rightarrow x^2=\dfrac{2}{3}\\ \Rightarrow x=\pm\sqrt{\dfrac{2}{3}}\)
`2x^7 =3x^9`
`2x^7 -3x^9 =0`
`x^7 (2-3x^2)=0`
`=>x^7=0` hoặc `2-3x^2 =0`
`=>x=0` hoặc `3x^2 =2`
`=>x=0` hoặc \(x=\sqrt{\dfrac{2}{3}}\) hoặc \(x=-\sqrt{\dfrac{2}{3}}\)
\(x-\dfrac{1}{3}=\dfrac{2}{3}.\dfrac{9}{14}+\dfrac{3}{7}\)
\(x-\dfrac{1}{3}=\dfrac{1}{7}+\dfrac{3}{7}\)
\(x-\dfrac{1}{3}=\dfrac{4}{7}\)
\(x=\dfrac{19}{21}\)
1/50 nhẽ
1/50 bạn nhé