2016.(-5)+5.1016-16.125
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`4^(x+2) .3^x = 16.12^5`
`4^(x+2) .3^x = 4^2 . (3.4)^5`
`4^(x+2) .3^x = 4^2 . 3^5. 4^5`
`4^(x+2) .3^x = 4^7 . 3^5`
`4^(x+2) .3^x = 4^(5+2) . 3^5`
`x=5`
Ta có:4x+2.3x=16.125
⇔ 4x+2.3x=417.315
⇔ 4x+2:417.3x:315=1
⇔ 4x-15.3x-15=1
⇔ 12x-15=120
⇔ x-15=0
⇔ x=15
Vừa ăn bánh sinh nhật lừa làm bài nên hơi lâu ==*
16 . 125 = 2 . 23 . 53 . = 2 . 103 = 2 . 1000 = 2000
9 . 24 . 25 = 9 . 6 . 4 . 25 = 54 . 100 = 5400
12 . 125 . 54 = 3 . 33 . 23 . 53 . 5 = 15 . 3000 = 45000
a) \(14.50=7.2.50=7.100=700\)
b) \(16.125=2.8.125=2.1000=2000\)
c) \(9.4.25\)
\(=9.6.4.25\)
\(=54.1000\)
\(=5400\)
d) \(12.125.54=3.4.125.2.27=3.27.4.2.125\)
\(=81.8.125\)
\(=81.1000\)
\(=81000\)
\(a,14.50=14.100:2=1400:2=700\\ b,16.125=\left(16:8\right).\left(125.8\right)=2.1000=2000\\ c,9.24.25=9.6.4.25=54.100=5400\\ d,12.125.54=\left(3.4\right).125.\left(27.2\right)=\left(3.27\right).\left(4.2.125\right)=81.1000=81000\)
17262 - 9998
= 17262 - 10 000 + 2
= 7262 + 2
= 7264
876 - 197
=876 - 200 + 3
= 676 + 3
= 679
16.125
= 2. 8. 125
= 2. (8.125)
= 2. 1000
= 2000
700 : 25
= 7 x 100 : 25
= 7 x ( 100 : 25)
= 7 x 4
= 28
( 260 - 13) : 13
= 260 : 13 - 13 : 13
= 20 - 1
= 19
a)
26.50 = 13. 2. 50 = 13 . 100 = 1300
36.25 = 9. 4 . 25 = 9. 100 = 900
16 . 125 = 2. 8. 125 = 2.1000 = 2000
b) 1200 : 25 = ( 1200. 4 ) : ( 25. 4 ) = 4800 : 100 = 48
2350 : 50 = ( 2350. 2 ) : ( 50 . 2 ) = 4700 : 100 = 47
8750 : 125 = ( 8750 . 8 ) : ( 125. 8 ) = 70 000 : 1000 = 70
\(P=\dfrac{3^{2016}-6^{2016}+9^{2016}-12^{2016}+15^{2016}-18^{2016}}{-1^{2016}+2^{2016}-3^{2016}+4^{2016}-5^{2016}+6^{2016}}\)
\(=\dfrac{\left(3^{2016}-6^{2016}\right)+\left(9^{2016}-12^{2016}\right)+\left(15^{2016}-18^{2016}\right)}{-1^{2016}+2^{2016}-3^{2016}+4^{2016}-5^{2016}+6^{2016}}\)
\(=\dfrac{3^{2016}\left(1-2^{2016}\right)+3^{2016}\left(3^{2016}-4^{2016}\right)+3^{2016}\left(5^{2016}-6^{2016}\right)}{-1^{2016}+2^{2016}-3^{2016}+4^{2016}-5^{2016}+6^{2016}}\)
\(=\dfrac{3^{2016}\left(1-2^{2016}+3^{2016}-4^{2016}+5^{2016}-6^{2016}\right)}{-\left(1^{2016}-2^{2016}+3^{2016}-4^{2016}+5^{2016}-6^{2016}\right)}\)
\(=-3^{2016}\).
Vậy \(P=-3^{2016}\)
\(P=\frac{3^{2016}-6^{2016}+9^{2016}-12^{2016}+15^{2016}-18^{2016}}{-1^{2016}+2^{2016}-3^{2016}+4^{2016}-5^{2016}+6^{2016}}\)
\(=\frac{\left(1.3\right)^{2016}-\left(2.3\right)^{2016}+\left(3.3\right)^{2016}-\left(4.3\right)^{2016}+\left(5.3\right)^{2016}-\left(6.3\right)^{2016}}{-1^{2016}+2^{2016}-3^{2016}+4^{2016}-5^{2016}+6^{2016}}\)
\(=\frac{1^{2016}.3^{2016}-2^{2016}.3^{2016}+3^{2016}.3^{2016}-4^{2016}.3^{2016}+5^{2016}.3^{2016}-6^{2016}.3^{2016}}{-1^{2016}+2^{2016}-3^{2016}+4^{2016}-5^{2016}+6^{2016}}\)
\(=\frac{-3^{2016}\left(-1^{2016}+2^{2016}-3^{2016}+4^{2016}-5^{2016}+6^{2016}\right)}{-1^{2016}+2^{2016}-3^{2016}+4^{2016}-5^{2016}+6^{2016}}\)
\(=-3^{2016}\)
kq là -7000