[1-1/2]x[1-1/3] x[1-1/4]x.....x[1-1/...]=1/2020
K
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TG
7 tháng 2 2021
\(\dfrac{1}{\left(x+1\right)\left(x+2\right)}+\dfrac{1}{\left(x+2\right)\left(x+3\right)}+\dfrac{1}{\left(x+3\right)\left(x+4\right)}=\dfrac{2019}{2020}\)
\(\Leftrightarrow\dfrac{1}{x+1}-\dfrac{1}{x+2}+\dfrac{1}{x+2}-\dfrac{1}{x+3}+\dfrac{1}{x+3}-\dfrac{1}{x+4}=\dfrac{2019}{2020}\)
\(\Leftrightarrow\dfrac{1}{x+1}-\dfrac{1}{x+4}=\dfrac{2019}{2020}\)
\(\Leftrightarrow\dfrac{x+4-x-1}{\left(x+1\right)\left(x+4\right)}=\dfrac{2019}{2020}\)
\(\Leftrightarrow\dfrac{3}{\left(x+1\right)\left(x+4\right)}=\dfrac{2019}{2020}\)
\(\Leftrightarrow\left(x+1\right)\left(x+4\right).2019=6060\)
<=> x = - 0,208387929
P/s: Số lạ zậy?Đề sai ko
22 tháng 10 2021
a: \(\dfrac{7}{4}+\dfrac{-3}{5}=\dfrac{35-12}{20}=\dfrac{23}{20}\)
d: \(\left(-\dfrac{1}{4}\right)^2\cdot\dfrac{4}{11}+\dfrac{7}{11}\cdot\left(-\dfrac{1}{4}\right)^2=\dfrac{1}{16}\)
22 tháng 10 2021
\(\dfrac{7}{4}+\dfrac{-3}{5}=\dfrac{35}{20}+\dfrac{-12}{20}=\dfrac{23}{20}\)
PA
1
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
20 tháng 3 2023
A = (1+1) \(\times\) (1+\(\dfrac{1}{2}\)) \(\times\) (1+\(\dfrac{1}{3}\)) \(\times\)....\(\times\)(1+ \(\dfrac{1}{2020}\))
A = 2 \(\times\) \(\dfrac{3}{2}\) \(\times\) \(\dfrac{4}{3}\) \(\times\) \(\dfrac{5}{4}\) \(\times\).......\(\times\) \(\dfrac{2021}{2020}\)
A =\(\dfrac{2\times3\times4\times....\times2020}{2\times3\times4\times....\times2020}\) \(\times\) \(\dfrac{2021}{1}\)
A = 1 \(\times\) 2021
A = 2021
DT
Dang Tung
CTVHS
19 tháng 8 2023
\(\left(1-\dfrac{1}{2}\right)\times\left(1-\dfrac{1}{3}\right)\times\left(1-\dfrac{1}{4}\right)\times...\times\left(1-\dfrac{1}{2023}\right)\\ =\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times...\times\dfrac{2022}{2023}\\ =\dfrac{1}{2023}\)
R
24 tháng 8 2019
Hello bạn, mk cx tên Mai nek.
\(\frac{2}{5}.\left(x-1\right)+1=\frac{3}{5}\)
\(\Rightarrow\frac{2}{5}\left(x+1\right)=\frac{3}{5}-1\)
\(\Rightarrow\frac{2}{5}\left(x+1\right)=-\frac{2}{5}\)
\(\Rightarrow x+1=-\frac{2}{5}:\frac{2}{5}\)
\(\Rightarrow x+1=-1\)
\(\Rightarrow x=-1-1\)
\(\Rightarrow x=-2\)
24 tháng 8 2019
\(\left(\frac{2}{7}\times x+1\right)\times\left(3-\frac{1}{2}\times x\right)=0\)
\(TH1:\frac{2}{7}\times x+1=0\)
\(\frac{2}{7}\times x=-1\)
\(x=-\frac{2}{7}\)
\(TH2:3-\frac{1}{2}\times x=0\)
\(\frac{1}{2}\times x=3\)
\(x=\frac{3}{2}\)
Vậy \(x\in\left\{\frac{3}{2};-\frac{2}{7}\right\}\)
8 tháng 7 2023
\(\left(1+\dfrac{2}{3}\right).\left(1+\dfrac{2}{4}\right).\left(1+\dfrac{2}{5}\right)....\left(1+\dfrac{2}{2020}\right).\left(1+\dfrac{2}{2021}\right)\)
= \(\dfrac{5}{3}.\dfrac{6}{4}.\dfrac{7}{5}.\dfrac{8}{6}.\dfrac{9}{7}....\dfrac{2022}{2020}.\dfrac{2023}{2021}\)
= \(\dfrac{1}{3}.\dfrac{1}{4}.2022.2023\)
= \(\dfrac{337.2023}{2}\)
= \(\dfrac{\text{681751}}{2}\)
15 tháng 5 2022
\(F=1\dfrac{1}{5}\times1\dfrac{1}{6}\times1\dfrac{1}{7}\times\cdot\cdot\cdot\times1\dfrac{1}{2019}\times1\dfrac{1}{2020}\)
\(F=\dfrac{6}{5}\times\dfrac{7}{6}\times\dfrac{8}{7}\times\cdot\cdot\cdot\times\dfrac{2020}{2019}\times\dfrac{2021}{2020}\)
\(F=\dfrac{6\times7\times8\times\cdot\cdot\cdot\times2020\times2021}{5\times6\times7\times\cdot\cdot\cdot\times2019\times2020}\)
\(F=\dfrac{2021}{5}\)
| \(Huyền\) |
C
15 tháng 5 2022
\(f=1^1_5\times1^1_6\times1^1_7\times......\times1^1_{2019}\times1^1_{2022}\)
\(f=\dfrac{6}{5}\times\dfrac{7}{6}\times\dfrac{8}{7}\times....\times\dfrac{2020}{2019}\times\dfrac{2021}{2020}\)
\(f=\dfrac{6\times7\times8\times....\times2020\times2021}{5\times6\times7\times.....\times2019\times2020}\)
\(f=\dfrac{2021}{5}\)
\(#Tarus\)
B
1
