Question

[Cherry Sos]

1.Rút gọn phân thức:

a) \(\dfrac{18ab}{27bc}\) b) -21b²y² / -28by c) -49a³ / 14b³ d) 12x³y² / 18xy⁵

2.Rút gọn phân thức:

a) a³(a-5) / a-5 b)3(b+7)⁴ / 8(b+7)⁶ c) 15x(x+5)² / 20x²(x+5)

d) x^3-4x² / y(x-4) e) 5(a-2c)² / 2a²-4ac

3.Rút gọn phân thức:

a) \(\dfrac{ax-3x}{bx-3b}\) b) \(\dfrac{5x+20y}{15x+60y}\)

c) 3b-9c / 5b²-15bc d) 8a²+40ab / ab+5b²

4.Phân tích tử và mẫu thành nhân tử rồi rút gọn phân thức:

a) 3x²-12x+12 / x⁴-8x b)7x²+14x+7 / 3x²+3x

5.Áp dụng quy tắc đổi dấu rồi rút gọn phân thức:

a) 45x(3-x) / 159x-3)³ b) 36(x-2)³ / 32-16x

c)x²-xy / 5y²-5xy d) y2-x² / x³-3x²y+3xy²-y³

Giúp mình mới. Mình xin chân thành cảm ơn và có một điều bất

ngờ cho ai giúp mình nhoe...

Answer 1

[Hoàng Thị Ngọc Mai]

1)

a) \(\dfrac{18ab}{27bc}=\dfrac{2a}{3c}\)

b) \(\dfrac{-21b^2y^2}{-28by}=\dfrac{3by}{4}\)

c) \(\dfrac{-49a^3}{14b^3}=\dfrac{-7a^3}{2b^3}\)

d) \(\dfrac{12x^3y^2}{18xy^5}=\dfrac{2x^2}{3y^3}\)

2)

a) \(\dfrac{a^3\left(a-5\right)}{a-5}=a^3\)

b) \(\dfrac{3\left(b+7\right)^4}{8\left(b+7\right)^6}=\dfrac{3}{8\left(b+7\right)^2}\)

c) \(\dfrac{15x\left(x+5\right)^2}{20x^2\left(x+5\right)}=\dfrac{3\left(x+5\right)}{4x}\)

d) \(\dfrac{x^3-4x^2}{y\left(x-4\right)}=\dfrac{x^2\left(x-4\right)}{y\left(x-4\right)}=\dfrac{x^2}{y}\)

e) \(\dfrac{5\left(a-2c\right)^2}{2a^2-4ac}=\dfrac{5\left(a-2c\right)^2}{2a\left(a-2c\right)}=\dfrac{5\left(a-2c\right)}{2a}\)

3)

a) \(\dfrac{ax-3a}{bx-3b}=\dfrac{a\left(x-3\right)}{b\left(x-3\right)}=\dfrac{a}{b}\) (câu này mình sửa lại đề)

b) \(\dfrac{5x+20y}{15x+60y}=\dfrac{5\left(x+4y\right)}{15\left(x+4y\right)}=\dfrac{1}{3}\)

c) \(\dfrac{3b-9c}{5b^2-15bc}=\dfrac{3\left(b-3c\right)}{5b\left(b-3c\right)}=\dfrac{3}{5b}\)

d) \(\dfrac{8a^2+40ab}{ab+5b^2}=\dfrac{8a\left(a+5b\right)}{b\left(a+5b\right)}=\dfrac{8a}{b}\)

4)

a) \(\dfrac{3x^2-12x+12}{x^4-8x}=\dfrac{3\left(x^2-4x+4\right)}{x\left(x^3-8\right)}\)

\(=\dfrac{3\left(x-2\right)^2}{x\left(x-2\right)\left(x^2+2x+4\right)}=\dfrac{3\left(x-2\right)}{x\left(x^2+2x+4\right)}\)

b) \(\dfrac{7x^2+14x+7}{3x^2+3x}=\dfrac{7\left(x^2+2x+1\right)}{3x\left(x+1\right)}\)

\(=\dfrac{7\left(x+1\right)^2}{3x\left(x+1\right)}=\dfrac{7\left(x+1\right)}{3x}\)

5)

a) \(\dfrac{45x\left(3-x\right)}{15\left(x-3\right)^3}=\dfrac{-45x\left(x-3\right)}{15\left(x-3\right)^3}=\dfrac{-3x}{\left(x-3\right)^2}\)

b) \(\dfrac{36\left(x-2\right)^3}{32-16x}=\dfrac{36\left(x-2\right)^3}{-16\left(x-2\right)}=\dfrac{-9\left(x-2\right)^2}{4}\)

c) \(\dfrac{x^2-xy}{5y^2-5xy}=\dfrac{-x\left(y-x\right)}{5y\left(y-x\right)}=\dfrac{-x}{5y}\)

d) \(\dfrac{y^2-x^2}{x^3-3x^2y+3xy^2-y^3}=\dfrac{-\left(y+x\right)\left(x-y\right)}{\left(x-y\right)^3}=\dfrac{-x-y}{\left(x-y\right)^2}\)

Answer 2

[Đoàn Thị Van Anh]

1.

a, \(\dfrac{18ab}{27bc}=\dfrac{18ab:9b}{27bc:9b}=\dfrac{2a}{3c}\)

b, \(\dfrac{-21b^2y^2}{-28by}=\dfrac{-21b^2y^2:\left(-7\right)by}{-28by:\left(-7\right)by}=\dfrac{3by}{4}\)

c, \(\dfrac{-49a^3}{14b^3}=\dfrac{-49a^3:7}{14b^3:7}=\dfrac{-7a^3}{2b^3}\)

d, \(\dfrac{12x^3y^2}{18xy^5}=\dfrac{6xy^2\cdot2x^2}{6xy^2\cdot3y^3}=\dfrac{2x^2}{3y^3}\)

2.

a,\(\dfrac{a^3\cdot\left(a-5\right)}{a-5}=\dfrac{a^3}{1}=a^3\)

b,\(\dfrac{3\cdot\left(b+7\right)^4}{8\cdot\left(b+7\right)^6}=\dfrac{3}{8\cdot\left(b+7\right)^2}\)

c,\(\dfrac{15x\cdot\left(x+5\right)^2}{20x^2\cdot\left(x+5\right)}=\dfrac{3\cdot\left(x+5\right)}{4x}\)

d,\(\dfrac{x^3-4x^2}{y\cdot\left(x-4\right)}=\dfrac{x^2}{y}\)

e,\(\dfrac{5\cdot\left(a-2x\right)^2}{2a^2-4ac}=\dfrac{5\cdot\left(a-2x\right)}{2a}\)

3.

a,\(\dfrac{ax-3a}{bx-3b}=\dfrac{a\cdot\left(x-3\right)}{b\cdot\left(x-3\right)}=\dfrac{a}{b}\)

b, \(\dfrac{5x+20y}{15x+60y}=\dfrac{5\cdot\left(x+4y\right)}{15\cdot\left(x+4y\right)}=\dfrac{5}{15}=\dfrac{1}{3}\)

c, \(\dfrac{3b-9c}{5b^2-15bc}=\dfrac{3\cdot\left(b-3c\right)}{5b\cdot\left(b-3c\right)}=\dfrac{3}{5b}\)

d, \(\dfrac{8a^2+40ab}{ab+5b^2}=\dfrac{8a\cdot\left(a+5b\right)}{b\cdot\left(a+5b\right)}=\dfrac{8a}{b}\)

4.

a,\(\dfrac{3x^2-12x+12}{x^4-8x}=\dfrac{3\cdot\left(x^2-4x+4\right)}{x\cdot\left(x^3-8\right)}=\dfrac{3\cdot\left(x-2\right)^2}{x\cdot\left(x-2\right)\cdot\left(x^2+2x+4\right)}=\dfrac{3\cdot\left(x-2\right)}{x\cdot\left(x^2+2x+4\right)}=\dfrac{3\cdot\left(x-2\right)}{x\cdot\left(x+2\right)^2}\)

b, \(\dfrac{7x^2+14x+7}{3x^2+3x}=\dfrac{7\cdot\left(x^2+2x+1\right)}{3x\cdot\left(x+1\right)}=\dfrac{7\cdot\left(x+1\right)^2}{3x\cdot\left(x+1\right)}=\dfrac{7\cdot\left(x+1\right)}{3x}\)

5.

a, \(\dfrac{45x\cdot\left(3-x\right)}{15x\cdot\left(x-3\right)^3}=\dfrac{3\cdot\left(3-x\right)}{\left(x-3\right)^3}=\dfrac{-3\cdot\left(x-3\right)}{\left(x-3\right)^3}=\dfrac{-3}{\left(x-3\right)^2}\)

b, \(\dfrac{36\cdot\left(x-2\right)^3}{36-16x}=\dfrac{36\cdot\left(x-2\right)^3}{16\cdot\left(2-x\right)}=\dfrac{36\cdot\left(-\left(x-2\right)\right)^3}{16\cdot\left(2-x\right)}=\dfrac{-36\cdot\left(2-x\right)^3}{16\cdot\left(2-x\right)}=\dfrac{-9\cdot\left(2-x\right)^2}{4}\)

c, \(\dfrac{x^2-xy}{5y^2-5xy}=\dfrac{x\cdot\left(x-y\right)}{5y\cdot\left(y-x\right)}=\dfrac{-x\cdot\left(y-x\right)}{5y\cdot\left(y-x\right)}=\dfrac{-x}{5y}\)

d, \(\dfrac{y^2-x^2}{x^3-3x^2y+3xy^2+y^3}=\dfrac{\left(x+y\right)\cdot\left(x-y\right)}{\left(x-y\right)^3}=\dfrac{-\left(x+y\right)\cdot\left(y-x\right)}{\left(x-y\right)^3}=\dfrac{-\left(x+y\right)}{\left(x-y\right)^2}\)