\(\frac{64\times50\times44\times100}{27\times38\times146\times19}\)
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\(\frac{1}{40\times41}+\frac{1}{41\times42}+\frac{1}{42\times43}+\frac{1}{43\times44}\)
\(=\frac{1}{40}-\frac{1}{41}+\frac{1}{41}-\frac{1}{42}+\frac{1}{42}-\frac{1}{43}+\frac{1}{43}-\frac{1}{44}\)
\(=\frac{1}{40}-\frac{1}{44}=\frac{1}{440}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{49}-\frac{1}{50}\)
\(A=1-\frac{1}{50}\)
\(A=\frac{49}{50}\)
\(\)\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{49}-\frac{1}{50}\)
\(=1-\frac{1}{50}\)
\(=\frac{49}{50}\)
Đặt \(A=\frac{1}{1x3}+\frac{1}{3x5}+\frac{1}{5x7}+...+\frac{1}{17x19}\)
=>\(2xA=2x\left(\frac{1}{1x3}+\frac{1}{3x5}+\frac{1}{5x7}+...+\frac{1}{17x19}\right)\)
=>\(2xA=\frac{2}{1x3}+\frac{2}{3x5}+\frac{2}{5x7}+...+\frac{2}{17x19}\)
=>\(2xA=\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{17}-\frac{1}{19}\)
=>\(2xA=1-\frac{1}{19}=\frac{18}{19}\)
=>\(A=\frac{18}{19}:2=\frac{9}{19}\)
(\(\frac{1}{1}-\frac{1}{3}\left(\right)+\left(\right)\frac{1}{3}-\frac{1}{5}\left(\right)+\left(\right)\frac{1}{5}-\frac{1}{7}\left(\right)+....+\left(\right)\frac{1}{17}-\frac{1}{19}\left(\right)\)\(\frac{1}{19}\)
\(\frac{1}{1}+\left(\frac{1}{3}-\frac{1}{3}\right)+\left(\frac{1}{5}-\frac{1}{5}\right)+....+\left(\frac{1}{17}-\frac{1}{17}\right)-\frac{1}{19}\)
\(\frac{1}{1}-\frac{1}{19}=\frac{18}{19}\)
nhìu dợ chi bằng bấm máy hay hơn đó