So sánh : \(A=\dfrac{37^{20}}{37^{20}-6}\) và \(B=\dfrac{37^{20}+4}{37^{20}-2}\)
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Cách 1
\(A=\frac{37^{20}}{37^{20}-6}=\frac{37^{20}-6+6}{37^{20}-6}=1+\frac{6}{37^{20}-6}\)
\(B=\frac{37^{20}+4}{37^{20}-2}=\frac{37^{20}-2+6}{37^{20}-2}=1+\frac{6}{37^{20}-2}\)
Vì \(\frac{6}{37^{20}-6}>\frac{6}{37^{20}+2}\Rightarrow1+\frac{6}{37^{20}-6}>1+\frac{6}{37^{20}+2}\Rightarrow A>B\)
Ta có: \(A=\frac{37^{20}}{37^{20}:37^6}=\frac{1}{\frac{1}{37^6}}=37^6\left(1\right)\)
\(B=\frac{37^{20}.37^4}{37^{20}:37^2}=\frac{37^4}{\frac{1}{37^2}}=37^6\left(2\right)\)
Từ (1)(2) => A = B
\(\dfrac{4^5\cdot9^4}{8^3\cdot27^3}=\dfrac{\left(2^2\right)^5\cdot\left(3^2\right)^4}{\left(2^3\right)^3\cdot\left(3^3\right)^3}=\dfrac{2^{10}\cdot3^8}{2^9\cdot3^9}=\dfrac{2}{3}\)
\(\dfrac{4^{20}\cdot3^{35}}{2^{37}\cdot27^{12}}=\dfrac{\left(2^2\right)^{20}\cdot3^{35}}{2^{37}\cdot\left(3^3\right)^{12}}=\dfrac{2^{40}\cdot3^{35}}{2^{37}\cdot3^{36}}=\dfrac{2^3}{3}\)
\(\dfrac{5^4\cdot20^4}{25^5\cdot4^5}=\dfrac{5^4\cdot5^4\cdot4^4}{5^5\cdot5^5\cdot4^5}=\dfrac{1}{5^2\cdot4}=\dfrac{1}{100}\)
\(\dfrac{2^{15}\cdot9^4}{6^6\cdot8^3}=\dfrac{2^{15}\cdot\left(3^2\right)^4}{2^6\cdot3^6\cdot\left(2^3\right)^3}=\dfrac{2^{15}\cdot3^8}{2^6\cdot3^6\cdot2^9}=3^2\)
Câu 1 :
\(\dfrac{-25}{37}\&\dfrac{-20}{31}\)
Ta thấy \(\dfrac{-25}{37}< \dfrac{-20}{37}\)
mà \(\dfrac{-20}{37}< \dfrac{-20}{31}\)
\(\Rightarrow\dfrac{-25}{37}< \dfrac{-20}{31}\)
Câu 2 :
\(\dfrac{2}{3}\&\dfrac{5}{7}\)
\(\dfrac{2}{3}:\dfrac{5}{7}=\dfrac{2}{3}.\dfrac{7}{5}=\dfrac{14}{15}< 1\)
\(\Rightarrow\dfrac{5}{7}>\dfrac{2}{3}\) Câu 3 : \(\dfrac{8}{13}\&\dfrac{5}{7}\)Ta thấy \(\dfrac{8}{13}:\dfrac{5}{7}=\dfrac{8}{13}.\dfrac{7}{5}=\dfrac{56}{65}< 1\)
\(\Rightarrow\dfrac{8}{13}< \dfrac{5}{7}\)a) Vì 20 ° < 70 ° n ê n sin 20 ° < sin 70 ° (góc tăng, sin tăng)
b) Vì 25 ° < 63 ° 15 ' n ê n cos 25 ° > cos 63 ° 15 ' (góc tăng, cos giảm)
c) Vì 73 ° 20 ' > 45 ° n ê n t g 73 ° 20 ' > t g 45 ° (góc tăng, tg tăng)
d) Vì 2 ° < 37 ° 40 ' n ê n c o t g 2 ° > c o t g 37 ° 40 ' (góc tăng, cotg giảm )
ta thấy:
\(A=\dfrac{37^{20}}{37^{20}-6}< \dfrac{37^{20}+4}{37^{20}-6}< \dfrac{37^{20}+4}{37^{20}-2}\)
\(\Rightarrow A< \dfrac{37^{20}+4}{37^{20}-2}\)
vậy...