A=\(\dfrac{3^{10}.11+3^{10}.5}{3^9.2^4}\)
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A=\(\dfrac{3^{10}.11+3^{10}.5}{3^9.2^4}=\dfrac{3^{10}.\left(11+5\right)}{3^9.2^4}=\dfrac{3^{10}.16}{3^9.16}=3\)
vậy A=3
chúc bạn học tốt
\(A=\dfrac{3^{10}.11+3^{10}.5}{3^9.2^4}=\dfrac{3^{10}\left(10+5\right)}{3^9.2^4}=\dfrac{3^{10}.15}{3^9.2^4}=\dfrac{3.15}{2^4}=\dfrac{45}{16}\)
a. \(A=\dfrac{0,75-0,6+\dfrac{3}{7}+\dfrac{3}{13}}{2,75-2,2+\dfrac{11}{7}+\dfrac{11}{13}}=\dfrac{3\left(0,25-0,2+\dfrac{1}{7}+\dfrac{1}{13}\right)}{11\left(0,25-0,2+\dfrac{1}{7}+\dfrac{1}{13}\right)}=\dfrac{3}{11}\)
Vậy \(A=\dfrac{3}{11}\)
b. \(B=\dfrac{2^{12}\cdot13+2^{12}\cdot65}{2^{10}\cdot104}+\dfrac{3^{10}\cdot11+3^{10}\cdot5}{3^9\cdot2^4}=\dfrac{2^{12}\left(13+65\right)}{2^{10}\cdot104}+\dfrac{3^{10}\left(11+5\right)}{3^9\cdot2^4}=\dfrac{2^{12}\cdot78}{2^{10}\cdot104}+\dfrac{3^{10}\cdot16}{3^9\cdot16}=\dfrac{2^2\cdot3}{1\cdot4}+3=\dfrac{12}{4}+3=3+3=6\)
Vậy \(B=6\)
\(A=\dfrac{3^{10}\cdot11+3^{10}\cdot5}{3^9\cdot2^4}=\dfrac{3^{10}\cdot\left(11+5\right)}{3^9\cdot16}=\dfrac{3^{10}\cdot16}{3^9\cdot16}=3\)
\(B=\dfrac{2^{10}\cdot13+2^{10}\cdot65}{2^8\cdot104}=\dfrac{2^{10}\cdot\left(13+65\right)}{2^8\cdot2^2\cdot26}=\dfrac{2^{10}\cdot78}{2^{10}\cdot26}=3\)
\(C=\dfrac{72^3\cdot54^2}{108^4}=\dfrac{\left(2^3\cdot3^2\right)^3\cdot\left(2\cdot3^3\right)^2}{\left(3^3\cdot2^2\right)^4}\\ =\dfrac{2^9\cdot3^6\cdot2^4\cdot3^6}{3^{12}\cdot2^8}=\dfrac{2^{13}\cdot3^{12}}{3^{12}\cdot2^8}=2^5=32\)
\(D=\dfrac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}=\dfrac{11\cdot3^{29}-\left(3^2\right)^{15}}{2^2\cdot3^{28}}=\dfrac{11\cdot3^{29}-3^{30}}{2^2\cdot3^{28}}\\ =\dfrac{3^{29}\cdot\left(11-3\right)}{2^2\cdot3^{28}}=\dfrac{3^{29}\cdot8}{4\cdot3^{28}}=3\cdot2=6\)
Bài làm
A = 3¹° . 11 + 3¹° . 5 / 39 . 2⁴
A = 3¹° . ( 11 + 5 ) / 39 . 16
A = 3¹° . 16 / 39 . 16
A = 3¹° / 39
A = 3
Vậy A = 3
Mk lm bằng đt nên k vt đc phân số nha.
A=3^10.11+3^10.5/3^9.2^4
A=3^10.(11+5)/3^9.2^4
A=3^10.16/3^9.16
A=3^10/3^9
A=3
a: Ta có: \(\left(2^2\cdot5\cdot3^3-5^2\cdot2^3+20\right)\cdot3^2-10\)
\(=\left(4\cdot5\cdot27-25\cdot8+20\right)\cdot9-10\)
\(=\left(540-200+20\right)\cdot9-10\)
\(=3240-10=3230\)
\(=\frac{3^{10}\left(11+5\right)}{3^9.16}=\frac{3^{10}.16}{3^9.16}=3\)
\(A=\frac{3^{10}.11+3^{10}.5}{3^9.2^4}=\frac{3^{10}.16}{3^9.2^4}=\frac{3^9.2^4.3}{3^9.2^4}=3\)
\(A=\frac{3^{10}\left(11+5\right)}{3^9.2^4}=\frac{3^{10}.2^4}{3^9.2^4}=3\)
M=3^10.11+3^10.5 / 3^9.2^4
=3^10(11+5) / 3^9.2^4
=3^10.2^4 /3^9.2^4
=3^10/3^9
=3
\(A=\dfrac{3^{10}.11+3^{10}+5}{3^9.2^4}\\ A=\dfrac{3^{10}.\left(11+5\right)}{3^9.16}\\ A=\dfrac{3^{10}.16}{3^9.16}\\ A=3\)
\(\dfrac{3^{10}}{3^9}\)