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\(\frac{3^{10}.11+3^{10}.5}{3^9.2^4}+\frac{2^{13}+2^5}{2^{10}+2^2}=11\)
M=3^10.11+3^10.5 / 3^9.2^4
=3^10(11+5) / 3^9.2^4
=3^10.2^4 /3^9.2^4
=3^10/3^9
=3
\(\frac{3^{10}.11+3^{10}.5}{3^9.2^4}\)
\(=\frac{3^{10}.\left(11+5\right)}{3^9.2^4}\)
\(=\frac{3^{10}.16}{3^9.2^4}\)
\(=\frac{3^{10}.2^4}{3^9.2^4}=3\)
3^10.(11+5) =3.16
3^9 . 2^4 1.16 bỏ số 16 thì được kết quả bằng 3
\(=\frac{3^{10}\left(11+5\right)}{3^9.16}=\frac{3^{10}.16}{3^9.16}=3\)
\(A=\frac{3^{10}.11+3^{10}.5}{3^9.2^4}=\frac{3^{10}.16}{3^9.2^4}=\frac{3^9.2^4.3}{3^9.2^4}=3\)
Ta có : \(\frac{3^{10}.11+3^{10}.5}{3^9.2^4}=\frac{3^{10}.\left(11+5\right)}{3^9.16}=\frac{3^{10}.16}{3^9.16}=3\)3
\(\frac{3^{10}.11+3^{10}.5}{3^9.2^4}=\frac{3^{10}.\left(11+5\right)}{3^9.2^4}\) \(=\frac{3^{10}.16}{3^9.2^4}=\frac{3^{10}.2^4}{3^9.2^4}=3\)
a)\(A=\frac{3^{10}.11+3^{10}.5}{3^9.2^4}=\frac{3^{10}\left(11+5\right)}{3^9.2^4}=\frac{3.16}{2^4}=\frac{3.2^4}{2^4}=3\)
b)\(B=\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}\left(13+65\right)}{2^8.2^3.13}=\frac{2^{10}.78}{2^{11}.13}=3\)
c)\(C=\frac{4^9.36+64^4}{16^4.100}=\frac{2^{18}.2^2.3^2+2^{24}}{2^{16}.2^2.5^2}=\frac{2^{20}\left(3^2+2^4\right)}{2^{18}.5^2}=\frac{2^2.25}{25}=4\)
Bài làm
A = 3¹° . 11 + 3¹° . 5 / 39 . 2⁴
A = 3¹° . ( 11 + 5 ) / 39 . 16
A = 3¹° . 16 / 39 . 16
A = 3¹° / 39
A = 3
Vậy A = 3
Mk lm bằng đt nên k vt đc phân số nha.
A=3^10.11+3^10.5/3^9.2^4
A=3^10.(11+5)/3^9.2^4
A=3^10.16/3^9.16
A=3^10/3^9
A=3
\(\frac{7256.4375-725}{4375.7255+3650}=\frac{\left(7255+1\right).4375-725}{4375.7255+3650}=\frac{7255.4375+4375-725}{7255.4375+3650}=\frac{7255.4375+3650}{7255.4375+3650}=1\)
\(\frac{3^{10}.11+3^{10}.5}{3^9.2^4}=\frac{3^{10}\left(11+5\right)}{3^9.2^4}=\frac{3.16}{16}=3\)
\(\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}\left(13+65\right)}{2^8.104}=\frac{2^2.78}{26.2^2}=\frac{78}{26}=3\)
\(\left(125^3.7^5-175^5.5\right):2001^{2002}\) ( bạn xem lại đề xem sai đâu ko nhé )
Để Thiên giải câu 3 cho:
(1253.75 -1755;5):20012001
\(=\left[\left(5^3\right)^3.7^5-175^5:5\right]:2001^{2002}\)
\(=\left(5^9.7^5-175:5\right):2001^{2002}\)
\(=\left(5^5.5^4.7^4.7-175^4.175:5\right):2001^{2002}\)
\(=\left(5^5.35^4.7-175^4.35\right):2001^{2002}\)
\(=\left(5^4.35^4.5.7-175^4.35\right):2001^{2002}\)
\(=\left(175^4.35-175^4.35\right):2001^{2002}\)
\(=0:2001^{2002}\)
\(=0\)
a) \(\frac{72^3.54^2}{108^4}=\frac{\left(2^3.3^2\right)^3.\left(2.3^3\right)^2}{\left(2^2.3^3\right)^4}=\frac{2^9.3^6.2^2.3^6}{2^8.3^{12}}=\frac{2^{11}.3^{12}}{2^8.3^{12}}=2^3=8\)
b) \(\frac{3^{10}.11+3^{10}.5}{3^9.2^4}=\frac{3^{10}.\left(11+5\right)}{3^9.16}=\frac{3.16}{16}=3\)
Nhanh lên nào các bạn làm nhanh có l.i.k.e làm sau cũng có l.i.k.e miễn làm đúng
\(A=\frac{3^{10}\left(11+5\right)}{3^9.2^4}=\frac{3^{10}.2^4}{3^9.2^4}=3\)
\(3\)nha bạn
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