\(x\)x\(x\)-\(\frac{1}{6}\)=
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21 tháng 7 2015

\(x.x-\frac{1}{6}=\frac{5}{18}\)

\(x.x=\frac{4}{9}\)

\(=>x=\frac{2}{9}\)

l-i-k-e nhé

21 tháng 7 2015

\(x\cdot x=\frac{5}{18}+\frac{1}{6}=\frac{4}{9}\)

Vì 2/3 . 2/3 = 4/9 => x = 2/3 

18 tháng 5 2020

 Heo ơi

Heo

\(\left(a\right)\frac{34-x}{30}=\frac{5}{6}\)

\(\frac{34-x}{30}=\frac{25}{30}\)

34 - x = 25

x = 34 - 25 = 9

\(\left(b\right)\frac{x+13}{34}=\frac{12}{17}\)

\(\frac{x+13}{34}=\frac{24}{34}\)

x + 13 = 24

x = 24 - 13 = 11

\(\left(c\right)\left(x+\frac{1}{3}\right)+\left(x+\frac{1}{9}\right)+\left(x+\frac{1}{27}\right)+\left(x+\frac{1}{81}\right)=\frac{56}{81}\)

\(4x+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}=\frac{56}{81}\)

Đặt \(A=\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\)

Ta có : \(3A=1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}\)

\(3A-A=1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}-\frac{1}{3}-\frac{1}{9}-\frac{1}{27}-\frac{1}{81}\)

\(2A=1-\frac{1}{81}=\frac{80}{81}\)

\(A=\frac{80}{81}\div2=\frac{40}{81}\)

\(\Rightarrow4x+\frac{40}{81}=\frac{56}{81}\)

\(4x=\frac{56}{81}-\frac{40}{81}\)

\(4x=\frac{16}{81}\)

\(x=\frac{16}{81}\div4=\frac{4}{81}\)

9 tháng 8 2020

a, \(\frac{34-x}{30}=\frac{5}{6}\Leftrightarrow\frac{34-x}{30}=\frac{25}{30}\)

\(\Leftrightarrow34-x=25\Leftrightarrow x=9\)

b, \(\frac{x+13}{34}=\frac{12}{17}\Leftrightarrow\frac{x+13}{34}=\frac{24}{34}\)

\(\Leftrightarrow x+13=24\Leftrightarrow x=11\)

8 tháng 4 2018

X x\(\frac{1}{2}\)+ X x\(\frac{3}{4}\)=\(\frac{6}{7}\)

=>X x(\(\frac{1}{2}\)+  \(\frac{3}{4}\)) =\(\frac{6}{7}\)

=>X x \(\frac{5}{4}\)=\(\frac{6}{7}\)

=>X=\(\frac{6}{7}\):      \(\frac{5}{4}\)

=>X=\(\frac{24}{35}\)

7 tháng 6 2018

  \(x(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{132}=\) \(5\frac{1}{2}\)        

 \(x\left(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{11\cdot12}\right)=\frac{11}{2}\)

 \(x\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{11}-\frac{1}{12}\right)=\frac{11}{2}\)

 \(x\left(1-\frac{1}{12}\right)=\frac{11}{2}\)

 \(x\cdot\frac{11}{12}=\frac{11}{2}\)

 \(x=\frac{11}{2}:\frac{11}{12}\)

\(x=6\)

Vậy x = 6

7 tháng 6 2018

\(\frac{x}{2}+\frac{x}{6}+\frac{x}{12}+\frac{x}{20}+...+\frac{x}{132}=5\frac{1}{2}\)

\(\Rightarrow x\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{132}\right)=\frac{11}{2}\)

\(\Rightarrow x\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{11.12}\right)=\frac{11}{2}\)

\(\Rightarrow x\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{11}-\frac{1}{12}=\frac{11}{2}\right)\)

\(\Rightarrow x\left(1-\frac{1}{12}\right)=\frac{11}{2}\)

\(\Rightarrow x.\frac{11}{12}=\frac{11}{12}\)

\(\Rightarrow x=\frac{11}{12}:\frac{11}{12}=1\)

Vậy x = 1

13 tháng 7 2018

a) (1,5 . 1,9 - x - 0,5) : 0,25 = 7,5 : 0,125

=> (2,85 - x - 0,5) : 0,25 = 60

=> (2,85 - 0,5) - x = 60 . 0,25

=> 2,35 - x = 15

=> x = 2,35 - 15

=> x = -12,65

Vậy x = -12,65

b) \(1-\left(5\frac{2}{9}+x-7\frac{7}{18}\right)\div2\frac{1}{6}=0\)

\(\Rightarrow\left(5\frac{2}{9}-7\frac{7}{18}+x\right)\div2\frac{1}{6}=1-0\)

\(\Rightarrow\left(\frac{47}{9}-\frac{133}{18}+x\right)\div2\frac{1}{6}=1\)

\(\Rightarrow\frac{-13}{6}+x=2\frac{1}{6}\)

\(\Rightarrow x=2\frac{1}{6}-\frac{-13}{6}\)

\(\Rightarrow x=\frac{13}{6}+\frac{13}{6}\)

\(\Rightarrow x=\frac{26}{6}\)

\(\Rightarrow x=\frac{13}{3}\)

Vậy \(x=\frac{13}{3}\)

c) \(35\left(2\frac{1}{5}-x\right)=32\)

\(\Rightarrow2\frac{1}{5}-x=32\div35\)

\(\Rightarrow\frac{11}{5}-x=\frac{32}{35}\)

\(\Rightarrow x=\frac{11}{5}-\frac{32}{35}\)

\(\Rightarrow x=\frac{9}{7}\)

Vậy \(x=\frac{9}{7}\)

d) \(\frac{4}{3}+\left(x\div2\frac{2}{3}-0,5\right).1\frac{35}{55}=0,6\)

\(\Rightarrow\left(x\div\frac{8}{3}-\frac{1}{2}\right).\frac{18}{11}=\frac{3}{5}-\frac{4}{3}\)

\(\Rightarrow\left(x\div\frac{8}{3}-\frac{1}{2}\right).\frac{18}{11}=\frac{-11}{15}\)

\(\Rightarrow x\div\frac{8}{3}-\frac{1}{2}=\frac{-11}{15}\div\frac{18}{11}\)

\(\Rightarrow x\div\frac{8}{3}-\frac{1}{2}=\frac{-121}{270}\)

\(\Rightarrow x\div\frac{8}{3}=\frac{-121}{270}+\frac{1}{2}\)

\(\Rightarrow x\div\frac{8}{3}=\frac{7}{135}\)

\(\Rightarrow x=\frac{7}{135}.\frac{8}{3}\)

\(\Rightarrow x=\frac{56}{405}\)

Vậy \(x=\frac{56}{405}\)

e) \(1\frac{1}{3}.2\frac{2}{4}\div\frac{5}{6}.1\frac{1}{11}=11-5\div x\)

\(\Rightarrow\frac{4}{3}.\frac{5}{2}\div\frac{5}{6}.\frac{12}{11}=11-5\div x\)

\(\Rightarrow\frac{10}{3}\div\frac{5}{6}.\frac{12}{11}=11-5\div x\)

\(\Rightarrow4.\frac{12}{11}=11-5\div x\)

\(\Rightarrow11-5\div x=\frac{48}{11}\)

\(\Rightarrow5\div x=11-\frac{48}{11}\)

\(\Rightarrow5\div x=\frac{73}{11}\)

\(\Rightarrow x=5\div\frac{73}{11}\)

\(\Rightarrow x=\frac{55}{73}\)

Vậy \(x=\frac{55}{73}\)

a) (1,5 * 1,9 - x - 0,5) : 0,25 = 7,5 : 0,125

(2,85 - x - 0,5) : 0,25 = 60

(2,85 - x - 0,5) = 60 x 0,25

(2,85 - x - 0,5) = 15

2,35 - x = 15

x = 2,35 - 15

x = -12,65