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\(445-52+155+452\\ =\left(445+155\right)+\left(452-52\right)\\ =600+4000\\ =1000\\ 102\cdot55-102\cdot73+51\cdot36\\ =102\cdot\left(55-73\right)+51\cdot36\\ =102\cdot\left(-18\right)+102\cdot18\\ =0\\ 4\cdot5\cdot2\cdot25\cdot5-1000\\ =5000-1000\\ =4000\\ 8782-291\cdot13\\ =4999\\ 254+\left\{38\cdot\left[\left(42-16\right):2\right]\right\}\\ =254+\left[38\cdot\left(26:2\right)\right]\\ =254+\left(38\cdot13\right)\\ =748\\ \left(2791\cdot34+7882:14\right)\cdot0+1510-510:2\\ =1510-255\\ =1255\)
a. \(445-52+155+452=\left(445+155\right)+\left(452-52\right)=600+400=1000\)
b. \(102\cdot55-102\cdot73+51\cdot36=102\left(55-73+18\right)=102\cdot0=0\)
c.\(4\cdot5\cdot2\cdot25\cdot5-1000=4\cdot25\cdot5\cdot5\cdot2-1000=100\cdot50-1000=5000-1000=4000\)
d. \(8782-291\cdot13=8782-3783=4999\)
e. \(254+\left\{38\left[\left(42-16\right)\div2\right]\right\}=254+\left\{30\cdot13\right\}=254+494=748\)
f. \(\left(2791\cdot34+7882\div14\right)\cdot0+1510-510\div2=0+1510-255=1255\)\
\(2014.2013.2013.2012.x=2011.2012.2013.2014\)
\(\Rightarrow x=\dfrac{2011.2012.2013.2014}{2014.2013.2013.2012}\)
\(\Rightarrow x=\dfrac{2011}{2013}\)
Bạn xem lại đề
a) 0,5 + ( x - 15/2 ) : 1/2 = 9/2
<=> (x - 15/2 ): 1/2 = 9/2 - 0,5
<=> (x - 15/2) : 1/2 = 4
<=> (x - 15/2) = 4 . 1/2
<=> x - 15/2 = 2
<=> x = 2 + 15/2
<=> x = 19/2
b) 2012x - 2010x = 2014
( 2012 - 2010 ) .x = 2014
2x = 2014
x = 2014 :2
x = 1007
Tham khảo:
A=1.2+2.3+3.4+...+2013.2014
3A = 1.2.3 + 2.3.3 + 3.4.3 +...+ 2013.2014.3
Mà: 1.2.3 = 1.2.3
2.3.3 = 2.3.4 - 2.3.1
3.4.3 = 3.4.5 - 3.4.2
2012.2013.3 = 2012.2013.2014 - 2012.2013.2011
2013.2014.3 = 2013.2014.2015 - 2013.2014.2012
=> 3S = 2013.2014.2015
=> A = 2013.2014.2015 / 3 = 2723058910
\(\frac{2014.150+1000}{151.2014-1014}\)= \(\frac{150+1000}{\left(150+1\right).1014}\)
= \(\frac{1000}{1014}\)= \(\frac{500}{507}\)
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