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a, 13 \(\times\) 15 - 150 + 97 \(\times\)15
13 \(\times\) 15 - 15 \(\times\) 10 + 97 \(\times\) 15
= 15 \(\times\) ( 13 - 10 + 97)
= 15 \(\times\) ( 3 + 97)
= 15 \(\times\) 100
=1500
b, \(\dfrac{2016}{2015}\) \(\times\) \(\dfrac{4}{7}\) - \(\dfrac{4}{7}\) \(\times\) \(\dfrac{1}{2015}\) + \(\dfrac{3}{7}\)
= \(\dfrac{4}{7}\) \(\times\) ( \(\dfrac{2016}{2015}\) - \(\dfrac{1}{2015}\)) + \(\dfrac{3}{7}\)
= \(\dfrac{4}{7}\) \(\times\) \(\dfrac{2015}{2015}\) + \(\dfrac{3}{7}\)
= \(\dfrac{4}{7}\) + \(\dfrac{3}{7}\)
= \(\dfrac{7}{7}\)
= 1
a, \(13\) \(\times\) 15 - 150 + 97 \(\times\) 15
= 15 \(\times\) ( 13 - 10 + 97)
= 15 \(\times\) ( 3 + 97)
= 15 \(\times\) 100
= 1500
b, \(\dfrac{2016}{2015}\) \(\times\) \(\dfrac{4}{7}\) - \(\dfrac{4}{7}\) \(\times\) \(\dfrac{1}{2015}\) + \(\dfrac{3}{7}\)
= \(\dfrac{4}{7}\) \(\times\) ( \(\dfrac{2016}{2015}\) - \(\dfrac{1}{2015}\)) + \(\dfrac{3}{7}\)
= \(\dfrac{4}{7}\) \(\times\) \(\dfrac{2015}{2015}\) + \(\dfrac{3}{7}\)
= \(\dfrac{4}{7}\) + \(\dfrac{3}{7}\)
= \(\dfrac{7}{7}\)
= 1
\(=3.25+9.6-1.5+3+0.75-0.5+1.4\)
=3,25+0,75-2+3+11
=4+14-2
=2+14=16
`= 0,9 xx 95 + 0,9 xx 2 xx 2 + 0,9 xx 1 `
`= 0,9 xx ( 95 + 2 + 2 + 1 )`
`= 0,9 xx 100=90`
0,9 x 95 + 1,8 x 2 +0,9
=0,9 x 95 +0,9x2x2+0,9x1
= 0,9x(95+2+2+1)
= 0,9 x100
= 90
a) \(2,4:0,25+5,6:4+2\times\frac{1}{4}\)
\(=2,4\times\frac{1}{4}+5,6\times\frac{1}{4}+2\times\frac{1}{4}\)
\(=\left(2,4+5,6+2\right)\times\frac{1}{4}\)
\(=10\times\frac{1}{4}=\frac{5}{2}\)
b)\(3,47\times\frac{1}{2}-2,47:2+0,5\)
\(=3,47\times\frac{1}{2}-2,47\times\frac{1}{2}+\frac{1}{2}\times1\)
\(=\left(3,47-2,47+1\right)\times\frac{1}{2}\)
\(=2\times\frac{1}{2}=1\)
#Y/n
7/11+3/4+4/11+1/4= (7/11+4/11)+(3/4+1/4)
=11/11+4/4=1+1=2
Chúc bạn học tốt!
Lời giải:
$2,5\times 20,23\times 8\times 5=2,5\times 20,23\times 4\times 2\times 5$
$=(2,5\times 4)\times 20,23\times (2\times 5)$
$=10\times 20,23\times 10=20,23\times 100=2023$
`4/3 \times (3/2 + 3/4)`
`= 4/3 \times 3/2 + 4/3 \times 3/4`
`= 12/6 + 12/12`
`= 2 + 1`
`=3`