Question

[nguyen quynh trang]

tìm x thuộc Z để: x+4/x-2 + 2x-5/x-2 là số nguyên

Answer 1

[Akai Haruma]

Lời giải:
$A = \frac{x+4}{x-2}+\frac{2x-5}{x-2}=\frac{x+4+2x-5}{x-2}=\frac{3x-1}{x-2}$

Với $x$ nguyên, để $A$ nguyên thì:

$3x-1\vdots x-2$

$\Rightarrow 3(x-2)+5\vdots x-2$

$\Rightarrow 5\vdots x-2$

$\Rightarrow x-2\in \left\{\pm 1; \pm 5\right\}$

$\Rightarrow x\in \left\{1; 3; 7; -3\right\}$

Answer 2

[Akai Haruma]

Lời giải:
$A = \frac{x+4}{x-2}+\frac{2x-5}{x-2}=\frac{x+4+2x-5}{x-2}=\frac{3x-1}{x-2}$

Với $x$ nguyên, để $A$ nguyên thì:

$3x-1\vdots x-2$

$\Rightarrow 3(x-2)+5\vdots x-2$

$\Rightarrow 5\vdots x-2$

$\Rightarrow x-2\in \left\{\pm 1; \pm 5\right\}$

$\Rightarrow x\in \left\{1; 3; 7; -3\right\}$