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2x - 1 + 4x - 2 + 6x - 3 + ... + 400x - 200 = 5 + 10 + 15 + ... + 10000
=> (2x + 4x + 6x + ... + 400x) - (1 + 2 + 3 + ... + 200) = 5.(1 + 2 + 3 + ... + 200)
=> 2x.(1 + 2 + 3 + ... + 200) - (1 + 2 + 3 + ... + 200) = 5.(1 + 2 + 3 + ... + 200)
=> (1 + 2 + 3 + ... + 200).(2x - 1) = 5.(1 + 2 + 3 + ... + 200)
=> 2x - 1 = 5
=> 2x = 5 + 1
=> 2x = 6
=> x = 6 : 2
=> x = 3
Vậy x = 3
b) \(697:\frac{15x+364}{x}=17\)
\(\frac{15x+364}{x}=697:17\)
\(\frac{15x+364}{x}=41\)
\(15+\frac{364}{x}=41\)
\(\frac{364}{x}=41-15\)
\(\frac{364}{x}=26\)
\(\Rightarrow x=14\)
a,15-3./2x-1/=6
3./2x-1/=15-6
3./2x-1/=9
2x-1=9:3=3
TH1:2x-1=3
2x=3+1=4
\(\Rightarrow x=2\)
\(5,\left(x\cdot0,5-\frac{3}{7}\right):\frac{1}{2}=1\frac{1}{7}\)
\(\Leftrightarrow x\cdot0,5:\frac{1}{2}-\frac{3}{7}:\frac{1}{2}=1\frac{1}{7}\)
\(\Leftrightarrow x-\frac{6}{7}=\frac{8}{7}\)
\(\Leftrightarrow x=2\)
\(6,x\cdot1,75=1\frac{3}{10}+45\%\)
\(\Leftrightarrow x\cdot\frac{7}{4}=\frac{13}{10}+\frac{9}{20}\)
\(\Leftrightarrow x\cdot\frac{7}{4}=\frac{7}{4}\)
\(\Leftrightarrow x=1\)
\(7,\frac{5-x}{15}+\frac{5}{12}-\frac{1}{8}=\frac{3}{8}\)
\(\Leftrightarrow\frac{5-x}{15}=\frac{3}{8}-\frac{5}{12}+\frac{1}{8}\)
\(\Leftrightarrow\frac{5-x}{15}=\frac{1}{12}\)
\(\Leftrightarrow60-12x=15\)
\(\Leftrightarrow12x=45\)
\(\Leftrightarrow x=\frac{15}{4}\)
\(8,\left|x-\frac{25}{33}\right|-\frac{3}{11}=\frac{2}{3}\)
\(\Leftrightarrow\left|\frac{x-25}{33}\right|=\frac{31}{33}\)
\(\Rightarrow\orbr{\begin{cases}x-\frac{25}{33}=\frac{31}{33}\\x-\frac{25}{33}=-\frac{31}{33}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{56}{33}\\x=-\frac{2}{11}\end{cases}}\)
\(9,-\frac{9}{8}+\frac{-3}{8}\cdot x=-\frac{1}{8}\)
\(\Leftrightarrow\frac{-9}{8}+\frac{-3}{8}\cdot x+\frac{1}{8}=0\)
\(\Leftrightarrow-1-\frac{3}{8}x=0\)
\(\Leftrightarrow\frac{3}{8}x=-1\)
\(\Rightarrow x=-\frac{8}{3}\)
a) 31<=3x<=35
=>1<=x<=5
=>x=1,2,3,4,5
b)22x-5=32
=>22x-5=25
=>2x-5=5
=>2x=5+5
=>2x=10
=>x=5