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\(\Leftrightarrow164-4\left(x-5\right)=80\\ \Leftrightarrow4\left(x-5\right)=84\\ \Leftrightarrow x-5=21\Leftrightarrow x=26\)
\(\dfrac{-2}{3}\left(x-\dfrac{1}{4}\right)=\dfrac{1}{3}\left(2x-1\right)\)
\(\Leftrightarrow\dfrac{-2}{3}x+\dfrac{1}{6}=\dfrac{2}{3}x-\dfrac{1}{3}\)
\(\Leftrightarrow\dfrac{-2}{3}x-\dfrac{2}{3}x=\dfrac{-1}{3}-\dfrac{1}{6}\)
\(\Leftrightarrow\dfrac{-4}{3}x=\dfrac{-1}{2}\)
\(\Leftrightarrow x=\dfrac{3}{8}\)
Vậy \(x=\dfrac{3}{8}\)
\(2^{14}:2^{10}-3x+3^2=4^3-\left(-5\right)\\ 2^2-3x+9=64-\left(-5\right)\\ 4-3x+9=69\\ 4-3x=69-9\\ 4-3x=60\\ 3x=4-60\\ 3x=-56\\ x=-56;3\\ x=\dfrac{-56}{3}\)
tìm x \(\in\) Z biết :
214 : 210 - 3x + 32 = 43 -(-5)
24 - 3x + 9 = 64 + 5
16 + 9 - 3x = 69
25 - 3x = 69
3x = 25 - 69
3x = - 44
x = - \(\dfrac{44}{3}\) (loại vì x \(\in\) Z)
Kết luận : x \(\in\) \(\varnothing\)
( x - 1 )3 = 125
( x - 1 )3 = 53
x - 1 = 5
x = 5 + 1
x = 6
\(a,50\%x-0,2+x=\dfrac{4}{5}\)
\(\Leftrightarrow\dfrac{1}{2}x-0,2+x=\dfrac{4}{5}\)
\(\Leftrightarrow\dfrac{1}{2}x+x=\dfrac{4}{5}+0,2\)
\(\Leftrightarrow\dfrac{3}{2}x=\dfrac{4}{5}+\dfrac{1}{5}\)
\(\Leftrightarrow\dfrac{3}{2}x=1\)
\(\Leftrightarrow x=\dfrac{2}{3}\)
\(b,\left(x-\dfrac{3}{4}\right):\dfrac{1}{2}+\dfrac{3}{2}=\dfrac{25}{2}\)
\(\Leftrightarrow\left(x-\dfrac{3}{4}\right).2=\dfrac{25}{2}-\dfrac{3}{2}\)
\(\Leftrightarrow\left(x-\dfrac{3}{4}\right).2=\dfrac{22}{2}\)
\(\Leftrightarrow x-\dfrac{3}{4}=11:2\)
\(\Leftrightarrow x=\dfrac{11}{2}+\dfrac{3}{4}\)
\(\Leftrightarrow x=\dfrac{25}{4}\)
\(3^{x+4}=9^{2x-1}\)
\(\Rightarrow3^{x+4}=3^{4x-2}\)
\(\Rightarrow x+4=4x-2\)
\(\Rightarrow3x=6\Rightarrow x=2\)
Ta có
20x5 chia hết cho 3
=> 2 + 0 + x + 5 chia hết cho 3
=> 7 + x chia hết cho 3
mà x là chữ số
=> x thuộc { 2 ; 5 ; 8 }
Giải :
\(m,x-25\%x=-\dfrac{1}{8}\\ \Leftrightarrow x-\dfrac{1}{4}x=-\dfrac{1}{8}\\ \Leftrightarrow x\left(1-\dfrac{1}{4}\right)=-\dfrac{1}{8}\\ \Leftrightarrow\left(\dfrac{4-1}{4}\right)x=-\dfrac{1}{8}\\ \Leftrightarrow\dfrac{3}{4}x=-\dfrac{1}{8}\\ \Leftrightarrow x=\left(-\dfrac{1}{8}\right):\dfrac{3}{4}\\ \Leftrightarrow x=-\dfrac{1}{6}\)
Vậy \(x=-\dfrac{1}{6}\)
\(h,\dfrac{x+1}{2}=\dfrac{-3}{-8}\\ \Leftrightarrow\dfrac{x+1}{2}=\dfrac{3}{8}\\ \Leftrightarrow8\left(x+1\right)=3.2\\ \Leftrightarrow8x+8=6\\ \Leftrightarrow8x=6-8\\ \Leftrightarrow8x=-2\\ \Leftrightarrow x=-\dfrac{2}{8}=-\dfrac{1}{4}\)
Vậy \(x=-\dfrac{1}{4}\)
\(d,\left(\dfrac{3}{15}x-x\right).\dfrac{1}{-3}=\dfrac{-2}{5}\\ \Leftrightarrow\left(\dfrac{3}{15}-1\right)x=\dfrac{-2}{5}:\dfrac{1}{-3}\\ \Leftrightarrow\dfrac{-4}{5}x=\dfrac{6}{5}\\ \Leftrightarrow x=\dfrac{6}{5}:\left(-\dfrac{4}{5}\right)\\ \Leftrightarrow x=-\dfrac{3}{2}\)
Vậy \(x=-\dfrac{3}{2}\)
m) \(x-25\%x=-\dfrac{1}{8}\)
\(\Leftrightarrow x-\dfrac{1}{4}x=-\dfrac{1}{8}\)
\(\Leftrightarrow\dfrac{3}{4}x=-\dfrac{1}{8}\)
\(\Leftrightarrow x=-\dfrac{1}{8}:\dfrac{3}{4}\)
\(\Leftrightarrow x=-\dfrac{1}{8}.\dfrac{4}{3}\)
\(\Leftrightarrow x=-\dfrac{4}{24}=-\dfrac{1}{6}\)