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\(a,2448:\left[119-\left(x-6\right)\right]=24\)
\(119-\left(x-6\right)=2448:24\)
\(119-\left(x-6\right)=102\)
\(x-6=119-102\)
\(x-6=17\)
\(x=17+6\)
\(\Rightarrow x=23\)
\(b,2016-100\times\left(x+11\right)=128:8\)
\(2016-100\times\left(x+11\right)=16\)
\(100\times\left(x+11\right)=2016-16\)
\(100\times\left(x+11\right)=2000\)
\(x+11=2000:100\)
\(x+11=20\)
\(x=20-11\)
\(\Rightarrow x=9\)
\(a,2448:\left[119-\left(x-6\right)\right]=24\\ 119-\left(x-6\right)=2448:24\\ 119-\left(x-6\right)=102\\ x-6=119-102\\ x-6=17\\ x=17+6\\ x=23\\ b,2016-100\times\left(x+11\right)=128:8\\ 2016-100\times\left(x+11\right)=16\\ 100\times\left(x+11\right)=2016-16\\ 100\times\left(x+11\right)=2000\\ x+11=2000:100\\ x+11=20\\ x=20-11\\ x=9\)
1/ Tính nhanh
1 - 4 + 7 - 10 + 13 - 16 + ... + 97 - 100
= ( - 3 ) + ( - 3 ) + ... + ( - 3 )
= ( - 3 ) x 17
= -51
2: \(=\dfrac{-2}{75}+\dfrac{5}{39}=\dfrac{33}{325}\)
3: \(=\dfrac{6}{11}\left(\dfrac{4}{9}+\dfrac{5}{9}\right)=\dfrac{6}{11}\)
4: \(=\dfrac{7}{19}\left(\dfrac{5}{13}+\dfrac{8}{13}-1\right)=-2\cdot\dfrac{7}{19}=-\dfrac{14}{19}\)
5: \(=\dfrac{2}{7}\left(\dfrac{4}{23}-\dfrac{27}{23}+1\right)=0\)
6: \(=\dfrac{3}{8}\left(\dfrac{3}{7}+\dfrac{4}{7}\right)+\dfrac{11}{8}=\dfrac{3}{8}+\dfrac{11}{8}=\dfrac{14}{8}=\dfrac{7}{4}\)
a) 2016 - 100.(x+31)=27:23
<=> 2016 - 100.(x+31) = 24 = 16
<=> 100.(x+31) = 2016 - 16 = 2000
<=> x+31 = 2000:100 = 20
<=> x = 20 - 31 = -11
b) (x+8)3 = 125
<=> (x+8)3 = 53
<=> x+8 = 5
<=> x = 5 - 8
<=> x = -3
Câu 1 :
a) 7x-8=713
7x=713+8
7x=721
x=721:7
x=103
Vậy x=103.
b)2448:[119-(x-6)]=24
119-(x-6)=2448:24
119-(x-6)=102
x-6=119-102
x-6=17
x=17+6
x=23
Vậy x=23.
c) 2016-100(x+11)=27:23
2016-100(x+11)=24=16
100(x+11)=2016-16
100(x+11)=2000
x+11=2000:100
x+11=20
x=20-11
x=9
Vậy x=9.
Câu 2 :
879.2+879.996+3.879=879(2+996+3)
=879.1001
=879879
12 tập hợp
\(2448:\left[119-\left(x-6\right)\right]=24\)
\(119-\left(x-6\right)=2448:24\)
\(119-\left(x-6\right)=102\)
\(x-6=119-102\)
\(x-6=17\)
\(x=17+6\)
\(x=23\)( thỏa mãn \(x\in N\) )
vậy x = 23
\(2016-100\cdot\left(x+11\right)=2^7:2^3\)
\(2016-100\cdot\left(x+11\right)=128:8\)
\(2016-100\cdot\left(x+11\right)=16\)
\(100\cdot\left(x+11\right)=2016-16\)
\(100\cdot\left(x+11\right)=2000\)
\(x+11=2000:100\)
\(x+11=20\)
\(x=20-11\)
\(x=9\)( thỏa mãn \(x\in N\))
vậy x = 9