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a)
=>9x+1=937=>9x=936=>x=104
b)
=>199-(x-6)=24.2448=>-(x-6)=58752-199=>-x+6=58553=>-x=58547=>x=-58547
nhớ giúp nhaaaaa
a) (x+12)-20=0
x+12=20
x=8
b) 5.(x-7)=0
x-7=0
x=7
c) 12x-3x+1=937
12x-3x=936
9x=936
x=104
d) 2448 : [ 119 - ( x - 6 ) ] = 24
119-(x-6) = 102
x-6=17
x=23
a ) ( x + 12 ) - 20 = 0
x + 12 = 0 + 20
x +12 = 20
x = 20 - 12
x = 8
b ) 5 . ( x - 7 ) =0
x - 7 = 0 : 5
x - 7 = 0
x = 0 + 7
x = 7
a) x-(-25+x)=13-x
⇒ x+25-x=13-x
⇒ 13-x=25
⇒ x= -12
b) 15-(30+x)=x-(27-l-8l)
⇒ 15-30-x=x-(27-8)
⇒ -15-x=x-19
⇒ -x-x=-19+15
⇒ -2x+4=0
⇒ -2x=-4
⇒ x=2
c) (12x-43).83=4.84
⇒ 12x.83-43.83=4.84
⇒ 6144x-32768=16384
⇒ 6144x=49152
⇒ x=8
a: Ta có: \(x-\left(-25+x\right)=13-x\)
\(\Leftrightarrow13-x=25\)
hay x=-12
b: Ta có: \(15-\left(30+x\right)=x-\left(27-\left|-8\right|\right)\)
\(\Leftrightarrow-15-x=x-19\)
\(\Leftrightarrow-2x=-4\)
hay x=2
c: Ta có: \(\left(12x-4^3\right)\cdot8^3=4\cdot8^4\)
\(\Leftrightarrow\left(12x-64\right)\cdot512=16384\)
\(\Leftrightarrow12x-64=32\)
hay x=8
a,(6400+2600)-3x=1200
9000-3x=1200
3x=9000-1200
3x=7800
x=7800:3
x=2600
b,(4x-[(8000-3567)-(2031-1598)]=400
(4x-[4433-433]=400
4x-4000=400
4x=400+4000
4x=4400
x=4400:4
x=1100
C;2448:[(119-(x-6)]=24
119-(x-6)=2448:24
119-(x-6)=102
x-6=119-102
x-6=17
x=17+6
x=23
a. (6400+2600) -3x=1200
=> 9000-3x=1200
=> 3x=9000-1200
=> 3x=7800
=> x=7800:3
=> x=2600
b. {4x-[(8000-3567)-(2031-1598)]}=400
=> { 4x-(4433-433)}=400
=> 4x-4000=400
=> 4x=400+4000
=> 4x=4400
=> x=4400:4
=> x=1100
c. 2448:[(119-(x-6)]=24
=> 119-(x-6)=2448:24
=> 119-(x-6)=102
=> x-6=119-102
=> x-6=17
=> x=17+6
=> x=23
\(2448:\left[119-\left(x-6\right)\right]=24\)
\(119-\left(x-6\right)=2448:24\)
\(119-x+6=102\)
\(125-x=102\)
\(x=125-102\)
\(x=23\)
`2448:[119-(x-6)]=24`
`=>119-(x-6)= 2448 : 24`
`=>119-(x-6)= 102`
`=> x-6=119-102`
`=> x-6=17`
`=>x=17+6`
`=>x=23`
`2448:[119-(x-6)]=24`
`=>119-(x-6)= 2448 : 24`
`=>119-(x-6)= 102`
`=> x-6=119-102`
`=> x-6=17`
`=>x=17+6`
`=>x=23`
\(2448:\left[119-\left(x-6\right)\right]=24\)
\(119-\left(x-6\right)=2448:24\)
\(119-\left(x-6\right)=102\)
\(x-6=119-102\)
\(x-6=17\)
\(x=17+6\)
\(x=23\)( thỏa mãn \(x\in N\) )
vậy x = 23
\(2016-100\cdot\left(x+11\right)=2^7:2^3\)
\(2016-100\cdot\left(x+11\right)=128:8\)
\(2016-100\cdot\left(x+11\right)=16\)
\(100\cdot\left(x+11\right)=2016-16\)
\(100\cdot\left(x+11\right)=2000\)
\(x+11=2000:100\)
\(x+11=20\)
\(x=20-11\)
\(x=9\)( thỏa mãn \(x\in N\))
vậy x = 9
a <=>12x-4^3=32
<=>12x=96
<=>x=8
b, <=>3x-6=27
<=>3x=33
<=>x=11
c, <=>119-(x-6)=102
<=>x-6=17
<=>x=23
hok tot
a) ( 12x - 43 ) . 83 = 4.84
=> ( 12x - 43 ) : 4 = 84 : 83
=> ( 12x - 43 ) : 4 = 8
=> 12x - 43 = 8 . 4
=> 12x - 64 = 32
=> 12x = 96
=> x = 8
b) ( 3x - 6 ) . 3 = 34
=> ( 3x - 6 ) = 34 : 31
=> 3x - 6 = 33
=> 3x - 6 = 27
=> 3x = 33
=> x = 11
c) 2448 : [ 119 - ( x - 6 ) ] = 24
=> 119 - ( x - 6 ) = 102
=> x - 6 = 7
=> x = 13