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![](https://rs.olm.vn/images/avt/0.png?1311)
\(\sqrt{484}-\dfrac{1}{\sqrt{5}}< \sqrt{529}-\dfrac{1}{19}< \sqrt{576}-\dfrac{1}{\sqrt{7}}< \sqrt{625}-\dfrac{1}{\sqrt{8}}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(\frac{1}{\sqrt{625}}+\frac{1}{5}+1\right):\left(\frac{1}{25}-\frac{1}{\sqrt{25}}-1\right)\)
\(=\left(\frac{1}{25}+\frac{1}{5}+1\right):\left(\frac{1}{25}-\frac{1}{5}-1\right)\)
\(=\frac{31}{25}:\frac{-29}{25}\)
\(=\frac{-31}{29}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\sqrt{9765+\sqrt{1296}}+\sqrt{15+\sqrt{95481}}+\sqrt{1271+\sqrt{625}}\)
\(=\sqrt{9765+\sqrt{36^2}}+\sqrt{15+\sqrt{309^2}}+\sqrt{1271+\sqrt{25^2}}\)
\(=\sqrt{9765+36}+\sqrt{15+309}+\sqrt{1271+25}\)
\(=\sqrt{9801}+\sqrt{324}+\sqrt{1296}\)
\(=\sqrt{99^2}+\sqrt{18^2}+\sqrt{36^2}\)
\(=99+18+36\)
\(=117+36\)
\(=153\)
![](https://rs.olm.vn/images/avt/0.png?1311)
ta có\(\sqrt{625}\)=25
\(\sqrt{576}\)=24
\(\Rightarrow\)24-1/\(\sqrt{6}\)+1
\(\Rightarrow\)24+-1/\(\sqrt{6}\)
\(\Rightarrow\)25-1/\(\sqrt{6}\)
\(\Rightarrow\)A<B
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\sqrt{625}-\frac{1}{\sqrt{5}}=25-\frac{1}{\sqrt{5}}\)
\(B=\sqrt{576}-\frac{1}{\sqrt{6}}+1=24-\frac{1}{\sqrt{6}}+1=25-\frac{1}{\sqrt{6}}\)
\(A< B\)
25
đáp án bằng 25