Question

[cong chua ichigo]

so sanh hai so

a=1x2+2x4+3xx6+4x8+5x10  /

3x4+6x8+9x12+12x16+15x20 

b=111111 /

666665

Answer 1

[Xyz OLM]

a) Ta có \(\frac{1.2+2.4+3.6+4.8+5.10}{3.4+6.8+9.12+12.16+15.20}\)

= \(\frac{1.2+1.2.2.2+1.3.2.3+1.4.2.4+1.5.2.5}{3.4+3.2.4.2+3.3.4.3+3.4.4.4+3.5.4.5}\)

= \(\frac{1.2+1.2.4+1.2.9+1.2.16+1.2.25}{3.4+3.4.4+3.4.9+3.4.16+3.4.25}\)

= \(\frac{1.2.\left(1+4+9+16+25\right)}{3.4.\left(1+4+9+16+25\right)}\)

= \(\frac{1.2.55}{3.4.55}\)

= \(\frac{1.2.55}{3.2.2.55}\)

= \(\frac{1}{3.2}\)

= \(\frac{1}{6}\)

b) \(\frac{111111}{666665}=\frac{111111}{666665}\)

(dấu "." là dấu "x")

Answer 2

[Xyz OLM]

mk làm tiếp 

Ta có : \(\frac{1}{6}=\frac{111111}{666666}\)

Vì \(\frac{111111}{666666}< \frac{111111}{666665}\)

=> \(\frac{1}{6}< \frac{111111}{666665}\)