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TL:
\(\frac{12}{100}\)= 0,12
\(\frac{5}{100}\)= 0,05
\(\frac{306}{1000}\)= 0,306
-HT-
\(9:\frac{3}{5}\cdot\frac{4}{15}=\frac{3}{5}\cdot\frac{4}{15}=\frac{4}{25}\)
\(\frac{156}{6}=26\)
a là :
(7525-903) : 2 = 3311
b là :
3311 + 903 = 4214
Vậy ; \(\frac{a}{b}=\frac{3311}{4214}=\frac{473}{602}\)
Ta có\(\frac{7}{42}=\frac{1}{6}\)
\(\frac{12}{18}=\frac{3x4}{6x3}=\frac{4}{6}=\frac{2}{3}\)
\(\frac{3}{18}=\frac{1}{6}\)
\(\frac{5}{30}=\frac{1}{6}\)
\(\frac{16}{24}=\frac{8x2}{8x3}=\frac{2}{3}\)
Ta có \(\frac{7}{42}=\frac{3}{18}=\frac{5}{30}=\frac{1}{6}\)
\(\frac{12}{18}=\frac{16}{24}=\frac{2}{3}\)
Vậy \(\frac{7}{20}\)và \(\frac{3}{5}\)là các phân số không bằng nhau
=13/12x14/13x15/14x16/15x...x2006/2005x2007/2006x2008/2007
=2008/12
=502/3
A = 1\(\dfrac{1}{12}\) \(\times\) 1\(\dfrac{1}{13}\) \(\times\) 1\(\dfrac{1}{14}\) \(\times\) 1\(\dfrac{1}{15}\) \(\times\) ... \(\times\) 1\(\dfrac{1}{2005}\) \(\times\) 1\(\dfrac{1}{2006}\) \(\times\) 1\(\dfrac{1}{2007}\)
A = ( 1 + \(\dfrac{1}{12}\)) \(\times\) ( 1 + \(\dfrac{1}{13}\)) \(\times\) ( 1 + \(\dfrac{1}{14}\)) \(\times\)...\(\times\) ( 1 + \(\dfrac{1}{2006}\))\(\times\)(1+\(\dfrac{1}{2007}\))
A = \(\dfrac{13}{12}\) \(\times\) \(\dfrac{14}{13}\) \(\times\) \(\dfrac{15}{14}\) \(\times\) ...\(\times\) \(\dfrac{2007}{2006}\) \(\times\) \(\dfrac{2008}{2007}\)
A = \(\dfrac{13\times14\times15\times...\times2007}{13\times14\times15\times...\times2007}\) \(\times\) \(\dfrac{2008}{12}\)
A = 1 \(\times\) \(\dfrac{502}{3}\)
A = \(\dfrac{502}{3}\)
Tổng của 9 số tự nhiên đầu tiên là:
1+2+3+4+5+6+7+8+9=45
Vậy ta có phân số: \(\frac{45}{10}\)= \(\frac{9}{2}\)
tk nhé
\(\frac{1}{10}+\frac{2}{10}+\frac{3}{10}+....+\frac{8}{10}+\frac{9}{10}\)
\(=\frac{1+2+3+4+5+6+7+8+9}{10}\)
\(=\frac{\left(1+9\right)+\left(2+8\right)+\left(+7\right)+\left(4+6\right)+5}{10}\)
\(=\frac{10+10+10+10+5}{10}\)
\(=\frac{45}{10}=\frac{9}{2}\)
k mk nha
`6/9=(6:3)/(9:3)=2/3`
`6/24=(6:6)/(24:6)=1/4`
`48/96=(48:48)/(96:48)=1/2`
`42/98 = (42:14)/(98:14)=3/7`
6/9 = 2/3 ; 6/24 = 1/4 ; 48/96 = 1/2 ; 42/98 = 3/7