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a) A = ( 11 + 19 ) + ( 12 + 18 ) + ( 13 + 17 ) + (14 + 16) + 15 + 20
= 30 + 30 + 30 + 30 + 15 + 20
= 155
b)B=11+13+15+17+...+25
B=(11+25)+(13+23)+(15+21)+(17+19)
B=36+36+36+36
B=36.4
B=144
c)C=12+14+16+18+...+26
C=(12+26)+(14+24)+(16+22)+(18+20)
C=38+38+38+38
C=38.4
C=152
a. 11 + 12 + 13 +14+15+16+17+18+19
= ( 11 + 19 ) + ( 12 + 18 ) + ( 13 + 17 ) + ( 14 + 16 ) + 15
= 30 + 30 + 30 + 30 + 15
= 120 + 15
= 132
b . 1+2+3+4+5+................+99+100
Dãy trên có tất cả số số hạng là :
( 100 - 1 ) : 1 + 1 = 100 ( số )
Tổng của dãy số trên là :
( 100 + 1 ) x 100 : 2 = 5050
Phần c và phần d bạn làm như phần b
Công thức tính số số hạng : ( số lớn - số bé ) : khoảng cách + 1
Công thức tính tổng : ( số lớn + số bé ) x số số hạng : 2
Hok tốt
Bài 1:
a; \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{7}{21}\) + (- \(\dfrac{10}{36}\) + \(\dfrac{11}{19}\) + \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)
= \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{1}{3}\) -\(\dfrac{10}{36}\) + \(\dfrac{11}{19}\) + \(\dfrac{1}{3}\) - \(\dfrac{5}{8}\)
= (\(\dfrac{5}{18}\) - \(\dfrac{10}{36}\)) + (\(\dfrac{8}{19}\) + \(\dfrac{11}{19}\)) - (\(\dfrac{1}{3}\) - \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)
= (\(\dfrac{5}{18}\) - \(\dfrac{5}{18}\)) + \(\dfrac{19}{19}\) - 0 - \(\dfrac{5}{8}\)
= 0 + 1 - \(\dfrac{5}{8}\)
= \(\dfrac{3}{8}\)
b; \(\dfrac{1}{13}\) + (\(\dfrac{-5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\)) - (\(\dfrac{12}{17}\) - \(\dfrac{5}{18}\) + \(\dfrac{7}{5}\))
= \(\dfrac{1}{13}\) - \(\dfrac{5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\) - \(\dfrac{12}{17}\) + \(\dfrac{5}{18}\) - \(\dfrac{7}{5}\)
= (\(\dfrac{1}{13}\) - \(\dfrac{1}{13}\)) + (\(\dfrac{12}{17}\) - \(\dfrac{12}{17}\)) + (-\(\dfrac{5}{18}\) + \(\dfrac{5}{18}\)) - \(\dfrac{7}{5}\)
= 0 + 0 + 0 - \(\dfrac{7}{5}\)
= - \(\dfrac{7}{5}\)
Bài 1 c;
\(\dfrac{15}{14}\) - (\(\dfrac{17}{23}\) - \(\dfrac{80}{87}\) + \(\dfrac{5}{4}\)) + (\(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\))
= \(\dfrac{15}{14}\) - \(\dfrac{17}{23}\) + \(\dfrac{80}{87}\) - \(\dfrac{5}{4}\) + \(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\)
= (\(\dfrac{15}{14}-\dfrac{15}{14}\)) + (\(-\dfrac{17}{23}+\dfrac{17}{23}\)) - (\(\dfrac{5}{4}\) - \(\dfrac{1}{4}\)) + \(\dfrac{80}{87}\)
= 0 + 0 - 1 + \(\dfrac{80}{87}\)
= - \(\dfrac{7}{87}\)
A = 1 - \(\dfrac{5}{6}\)+\(\dfrac{7}{12}\)-\(\dfrac{9}{20}\)+\(\dfrac{11}{30}\)-\(\dfrac{13}{42}\)+\(\dfrac{15}{56}\) - \(\dfrac{17}{72}\)+\(\dfrac{19}{90}\)+\(\dfrac{23}{132}\)-\(\dfrac{25}{156}\)
A = 1 - \(\dfrac{5}{2.3}\)+\(\dfrac{7}{3.4}\)-\(\dfrac{9}{4.5}\)+\(\dfrac{11}{5.6}\)-\(\dfrac{13}{6.7}\)+\(\dfrac{15}{7.8}\)-\(\dfrac{17}{8.9}\)+\(\dfrac{19}{9.10}\)+\(\dfrac{23}{11.12}\)-\(\dfrac{25}{12.13}\)
A = 1 - \(\dfrac{1}{2}-\dfrac{1}{3}\)+\(\dfrac{1}{3}+\dfrac{1}{4}\)-\(\dfrac{1}{4}-\dfrac{1}{5}\)+...+\(\dfrac{1}{11}+\dfrac{1}{12}\)- \(\dfrac{1}{12}-\dfrac{1}{13}\)
A = 1 - \(\dfrac{1}{2}\) - \(\dfrac{1}{13}\)
A = \(\dfrac{1}{2}\) - \(\dfrac{1}{13}\)
A = \(\dfrac{11}{26}\)
a) 35- {12 - [(-14)+(-2)] }
=35 - [12-(-14-2)]
=35-[12-16]
=35-(-4)
=35+4
=39
b) 49 - (- 54) - 23
=49 + 54 - 23
= 80
c) |31 - 17 | - |13 - 52|
= |14| - | -39|
=14-39
= -25
d) -|-5|+ (-19) + 18 +|11-4| - 57
=-5 - 19 + 18 + 7 - 57
= -5-1-50
=-56
e) 126 + (-20) + |124| - (- 320) - |- 150|
= 126 - 20 + 124 + 320 - 150
= 400
g) (- 17) + 5 +8 +17 + (-3)
=(-17+17)+(5+8-3)=10
h) [( -15) + ( - 21 )] - ( 25 -15 - 35- 21)
=-15-21-25+15+35+21
=(-15+15)+(21-21)+(35+15-25)
=25
=-4 - 46
= -50 Tick cho mik nha
1+2+3+4+5+6+7+8+9+10=55
11+12+13+14+15+16+17+18+19+20=155
1+2+3+4+5+6+7+8+9+10+11+12+13+14 +15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30-50-53=362
a) A = 1 + 2 + 3 + .......... + 1999
A = \(\frac{\left(1+1999\right)\cdot\left(\left(1999-1\right):1+1\right)}{2}\)
A = 1999000
b) B= 11 + 13 + 15 + 17 + 19 + 21 + 23 + 25
B = ( 21 + 19 ) + ( 23 + 17 ) + ( 15 + 25 ) + 11 + 13
B = 40 + 40 + 40 + 24
B = 40 x 3 + 24
B = 120 + 24
B = 144
c) C = 11 + 12 + 13 + .......... + 20
C = (11 + 19) + (12 + 18) + (13 + 17) + (14 + 16) + 15 +20
C = 30 + 30 + 30 + 30 +35
C = 30 x 4 +35
C = 120 + 35
C = 155