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a, 7\(x\).(\(x\) - 10) = 0
\(\left[{}\begin{matrix}7x=0\\x-10=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=0\\x=10\end{matrix}\right.\)
Vậy \(x\in\) {0; 10}
b, 17.(3\(x\) - 6).(2\(x\) - 18) = 0
\(\left[{}\begin{matrix}3x-6=0\\2x-18=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}3x=6\\2x-18=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=6:3\\x=18:2\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=2\\x=9\end{matrix}\right.\)
Ta có : \(\left|5x-4\right|=\left|x+2\right|\)
\(\Leftrightarrow\orbr{\begin{cases}5x-4=x+2\\5x-4=-x-2\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}5x-x=2+4\\5x+x=-2+4\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}4x=6\\6x=2\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=\frac{1}{3}\end{cases}}\)
b) \(\left|2x-3\right|-\left|3x+2\right|=0\)
\(\Rightarrow\orbr{\begin{cases}2x-3=3x+2\\2x-3=-3x-2\end{cases}\Rightarrow\orbr{\begin{cases}2x-3x=2+3\\2x+3x=-2+3\end{cases}\Rightarrow}\orbr{\begin{cases}-x=5\\5x=1\end{cases}\Rightarrow}\orbr{\begin{cases}x=-5\\x=\frac{1}{5}\end{cases}}}\)
c)/2+3x/=/4x-3/
\(\Rightarrow\orbr{\begin{cases}2+3x=4x-3\\2+3x=-\left(4x-3\right)\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}3x-4x=-3-2\\3x+4x=3-2\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}-x=-5\\7x=1\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=\frac{1}{7}\end{cases}}}\)
d)/7x+1/-/5x+6|=0
\(\Rightarrow\left|7x+1\right|=\left|5x+6\right|\)
\(\Rightarrow\orbr{\begin{cases}7x+1=5x+6\\7x+1=-\left(5x+6\right)\end{cases}\Rightarrow\orbr{\begin{cases}7x-5x=6-1\\7x+1=-5x-6\end{cases}\Rightarrow}\orbr{\begin{cases}2x=5\\7x+5x=-6-1\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{5}{2}\\x=-\frac{7}{12}\end{cases}}}\)
\(a,x-4=11-2x\)
\(x+2x=11+4\)
\(3x=15\)
\(x=5\)
\(b.7x-10=x-28\)
\(7x-x=-28+10\)
\(6x=-18\)
\(x=-3\)
\(c.x-3.x-2=0\)
\(\left(1-3\right).x-2=0\)
\(-2.x-2=0\)
\(-2x=2\)
\(x=-1\)
\(d.|x-5|=10\)
\(\Rightarrow\orbr{\begin{cases}x-5=10\\x-5=-10\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=15\\x=-5\end{cases}}\)
\(e.9-25=\left[7-x\right]-\left[25+7\right]\)
\(-16=\left[7-x\right]-32\)
\(-16+32=7-x\)
\(16=7-x\)
\(x=7-16\)
\(x=-9\)
a, - 2 .( x + 6 ) + 6 . ( x - 10 ) = 8
- 2x - 12 + 6x - 60 = 8
4x - 72 = 8
4x = 8 + 72
4x = 80
x = 20
b, - 4 . ( 2x + 9 ) - ( - 8x + 3 ) - ( x + 13 ) = 0
- 8x - 36 + 8x - 3 - x - 13 = 0
- x - 52 = 0
x = - 52
c, 7x . ( 2 + x ) - 7x . ( x + 3 ) = 14
7x . ( 2 + x - x - 3 ) = 14
7x . ( - 1 ) = 14
7x = 14 : ( - 1 )
7x = - 14
x = - 2
d, 2 . ( 5 + 3x ) + x = 31
10 + 6x + x = 31
10 + 7x = 31
7x = 31 - 10
7x = 21
x = 3
a)-2(x+6)+6(x-10)=8
-2x+-12+6x+-60=8
4x+-72=8
4x=80
x=80:4
x=20
b)-4(2x+9)-(-8x+3)-(x+13)=0
-8x+-36+8x-3+x-13=0
(-8x+8x)+-36+-3+x-13=0
0+-52+x=0
x=0-(-52)
x=-52
c)7x(2+x)-7x(x+3)=14
14x+7x2
A )123 -5 ( x -4 ) = 38
=> x-4 = (123-38) :(-5)
=> x-4=-17
=> x= -17+4=-13
B ) ( 3x - 24 ) 73 = 2.74
=> 3x-16= 2.74 :73=14
=> 3x=14+16=30
=> x=30:3=10
C ) ( 2600 + 6400 ) - 3x = 1200
=> 9000-3x=1200
=> 3x=9000-1200=7800
=> x=7800:3=2600
D ) [( 6x - 72 ) : 2 - 84 ] 28 = 5628
=> (6x-72) :2-84= 5628:28=201
=> 6x-72 = (201+84) .2=570
=> 6x=570 +72=642
=> x= 642:6=107
( L-IKE )
A) 123 - 5(x-4) = 38
5(x-4) = 123 - 38
x-4 = 85 : 5
x = 17 + 4
x= 21
B) (3x - 24)73 = 2.74
(3x - 24) = 2.74:73
3x = 14 + 24
x = 30 : 3 = 10
C) (2600 + 6400) - 3x = 1200
9000 - 3x = 1200
3x = 9000 - 1200
x = 7800 : 3 = 2600
D) [(6x - 72) : 2 - 84].28 = 5628
(6x - 72) : 2 - 84 = 5628 : 28 = 201
(6x - 72) : 2 = 201 + 84 = 285
6x - 72 = 285 . 2 = 570
6x = 570 + 72 = 642
x = 642 : 6 = 107
Có thể thử lại đáp án
\(\left(12x-4^3\right).8^3=4.8^4\)
\(12x-4^3=4.8^4:8^3\)
\(12x-64=4.8\)
\(12x-64=32\)
\(12x=32+64=96\)
\(x=96:12=8\)
Vậy x=8
\(b.\left(\left(4x+28\right).3+55\right):5=35\)
\(\left(4x+28\right).3+55=35\times5\)
\(\left(4x+28\right).3+55=175\)
\(\left(4x+28\right).3=175-55\)
\(\left(4x+28\right).3=120\)
\(4x+28=120:3=40\)
\(4x=40-28=12\)
\(x=12:4=3\)
Vậy x=3
\(c.720:\left(41-\left(2x-5\right)\right)=2^3.5\)
\(720:\left(41-\left(2x-5\right)\right)=40\)
\(41-\left(2x-5\right)=720:40=18\)
\(2x-5=41-18=23\)
\(2x=23+5=28\)
\(x=28:2=14\)
Vậy x=14
\(d.\left(3x-2^4\right).7^3=2.7^4\)
\(\left(3x-16\right).7^3=2.7^4\)
\(3x-16=2.7^4:7^3\)
\(3x-16=2.7=14\)
\(3x=14+16=30\)
\(x=30:3=10\)
Vậy x=10
Nhớ k cho mình nhé! Thank you!!!
a)2x=0+10
2x=10
x=10:2
x=5
b)7x=0+28
7x=28
x=28:7
x=4
c)3x=7+14
3x=21
x=21:3
x=7
d)3(x+2)=44-14
3(x+2)=30
x+2=30:3
x-2=10
x=10+2
x=12