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\(\frac{-9}{x}=\frac{-x}{\frac{4}{49}}\)
\(\Rightarrow x.x=\left(-9\right).\left(-\frac{4}{49}\right)\)
\(\Rightarrow x^2=\frac{36}{49}\)
\(\Rightarrow x^2=\hept{\begin{cases}\left(\frac{6}{7}\right)^2\\\left(-\frac{6}{7}\right)^2\end{cases}}\)
\(\Rightarrow x=\hept{\begin{cases}+\frac{6}{7}\\-\frac{6}{7}\end{cases}}\)
a) \(\frac{1}{4}+\frac{1}{3}:2x=-5\)
\(\frac{1}{3}:2x=\frac{-21}{4}\)
\(2x=\frac{-4}{63}\)
\(x=\frac{2}{63}\)
b) \(\left(3x-\frac{1}{4}\right)\left(x+\frac{1}{2}\right)=0\)
\(\Rightarrow\orbr{\begin{cases}3x-\frac{1}{4}=0\\x+\frac{1}{2}=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{1}{12}\\x=\frac{-1}{2}\end{cases}}\)
Vậy.........
a) x/-27=-3/x
suy ra: x.x=-3.(-27)
suy ra: x^2=81. Suy ra: x^2=9^2 hoặc (-9)^2
suy ra: x=9 hoặc x=-9
Vậy x=9 hoặc x=-9
\(\frac{-9}{x}=\frac{-x}{\frac{4}{49}}\)
=> \(x\left(-x\right)=\left(-9\right)\frac{4}{49}\)
=> \(-x^2\)\(=\frac{-36}{49}\)
=> \(x^2=\frac{36}{49}\)
=> \(x=\frac{6}{7}\)
\(\frac{-9}{x}=\frac{-x}{\frac{4}{49}}\)
\(\Rightarrow x^2=\left(-9\right)\left(\frac{-4}{49}\right)\)
\(\Rightarrow x^2=\frac{36}{49}\)
\(\Rightarrow x=\sqrt{\frac{36}{49}}\)
\(\Rightarrow x=\frac{\sqrt{36}}{\sqrt{49}}\)
\(\Rightarrow x=\frac{\sqrt{6^2}}{\sqrt{7^2}}\)
\(\Rightarrow x=\frac{6}{7}\)
vay \(x=\frac{6}{7}\)
a,\(\frac{x}{3}=\frac{2}{5}\)
\(\Rightarrow x=\frac{2.3}{5}=\frac{6}{5}\)
b,\(\frac{-9}{x}=\frac{\frac{\left(-x\right)}{4}}{49}\)
\(\Rightarrow x=-9.49.\frac{-4}{x}\)
\(\Rightarrow x=\frac{1764}{x}\)
\(\Rightarrow x^2=1764=42^2\)
\(\Rightarrow x=\pm2\)
\(\frac{-9}{x}=\frac{-x}{\frac{4}{49}}\Leftrightarrow-x.x=-9.\frac{4}{49}\Leftrightarrow-x^2=-\frac{36}{49}\)
\(\Leftrightarrow x^2=\frac{36}{49}\Leftrightarrow\sqrt{x}=\sqrt{\frac{36}{49}}\Leftrightarrow x=\hept{\begin{cases}\frac{6}{7}\\-\frac{6}{7}\end{cases}}\)
(Nhớ k cho mình với nhé!)
Bài 2:
a) \(\frac{x}{-27}=\frac{-3}{x}\Leftrightarrow-\frac{x}{27}=-\frac{3}{x}\Leftrightarrow-x.x=\left(-27\right).\left(-3\right)\Leftrightarrow-x^2=-81\Leftrightarrow\orbr{\begin{cases}x=9\\x=-9\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=9\\x=-9\end{cases}}\)
b) \(\frac{-9}{x}=\frac{-x}{\frac{4}{49}}\Leftrightarrow-\frac{9}{x}=-\frac{49x}{4}\Leftrightarrow-9.4=-x.49x\Leftrightarrow-36=-49x^2\Leftrightarrow\orbr{\begin{cases}x=\frac{6}{7}\\x=-\frac{6}{7}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{6}{7}\\x=-\frac{6}{7}\end{cases}}\)
\(a,\frac{2x}{3}=\frac{2y}{4}=\frac{4z}{5}\)và x + y + z = 49
Ta có : \(\frac{2x}{3}=\frac{2y}{4}=\frac{4z}{5}=\frac{x}{\frac{3}{2}}=\frac{y}{\frac{4}{2}}=\frac{z}{\frac{5}{4}}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có :
\(\frac{x}{\frac{3}{2}}=\frac{y}{\frac{4}{2}}=\frac{z}{\frac{5}{4}}=\frac{x+y+z}{\frac{3}{2}+\frac{4}{2}+\frac{5}{4}}=\frac{49}{\frac{19}{4}}=49\cdot\frac{4}{19}=\frac{196}{19}\)
Vậy : \(\hept{\begin{cases}\frac{x}{\frac{3}{2}}=\frac{196}{19}\\\frac{y}{\frac{4}{2}}=\frac{196}{19}\\\frac{z}{\frac{5}{4}}=\frac{169}{14}\end{cases}\Leftrightarrow}\hept{\begin{cases}x=\frac{294}{19}\\y=\frac{392}{19}\\z=\frac{245}{19}\end{cases}}\)
\(b,\frac{x}{y}=\frac{3}{4};\frac{y}{z}=\frac{5}{7}\)và 2x + 3y - z = 186
Ta có : \(\frac{x}{y}=\frac{3}{4};\frac{y}{z}=\frac{5}{7}\Leftrightarrow\frac{x}{3}=\frac{y}{4};\frac{y}{5}=\frac{z}{7}\)
\(\Leftrightarrow\frac{x}{15}=\frac{y}{20};\frac{y}{20}=\frac{z}{28}\)
\(\Leftrightarrow\frac{x}{15}=\frac{y}{20}=\frac{z}{28}\)
\(\Leftrightarrow\frac{2x}{30}=\frac{3y}{60}=\frac{z}{28}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có :
\(\frac{2x}{30}=\frac{3y}{60}=\frac{z}{28}=\frac{2x+3y-z}{30+60-28}=\frac{186}{62}=3\)
Vậy : \(\hept{\begin{cases}\frac{x}{15}=3\\\frac{y}{20}=3\\\frac{z}{28}=3\end{cases}}\Leftrightarrow\hept{\begin{cases}x=45\\y=60\\z=84\end{cases}}\)
\(\frac{-9}{x}=\frac{-x}{\frac{4}{49}}\)
\(\Rightarrow x^2=-9.\left(\frac{-4}{49}\right)\)
\(\Rightarrow x^2=\frac{36}{49}\)
\(\Rightarrow x=\sqrt{\frac{36}{49}}\)
\(\Rightarrow x=\sqrt{\frac{6^2}{7^2}}\)
\(\Rightarrow x=\sqrt{\left(\frac{6}{7}\right)^2}\)
\(\Rightarrow x=\frac{6}{7}\)
vay \(x=\frac{6}{7}\)
\(\frac{-9}{x}=\frac{-x}{\frac{4}{49}}\)
-9 x\(\frac{4}{49}\)=\(x\times\left(-x\right)\)
\(-\frac{36}{49}\)= -2x
\(\Rightarrow\)2x=\(\frac{36}{49}\)( cùng bớt dấu âm của 2 vế)
x=\(\frac{36}{49}:2\)
x=\(\frac{18}{49}\)
vậy x = \(\frac{18}{49}\)