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\(\frac{2^{10}\cdot3^{10}-2^{10}\cdot3^9}{2^9\cdot3^{10}}=\frac{2^{10}\cdot3^9\left(3-1\right)}{2^9\cdot3^{10}}=\frac{2^{11}\cdot3^9}{2^9\cdot3^{10}}=\frac{2^2}{3}=\frac{4}{3}\)
\(\frac{5^{10}.7^{12}+5^{10}.7^{11}}{5^{12}.7^{11}+9.5^4.7^{11}}=\frac{5^{10}.7^{11}.\left(7+1\right)}{7^{11}.5^4\left(5^8+9\right)}=\frac{8.5^6}{\left(9+5^8\right)}=\frac{125000}{390634}=\frac{62500}{195317}\)
Bài làm
m) (x + 2).(3 - x) = 0;
=> x + 2 = 0 hoặc 3 - x = 0
=> x = -2 hoặc x = 3
Vậy x = -2 hoặc x = 3
d) 511.712 + 511.711
= 511 . ( 712 + 711 )
= 511 . [ 711 . ( 7 + 1 ) ]
= 511 . 711 . 8
= ( 5 . 7 )11 . 8
= 3511 . 8
512.712 + 9.511.711
= 511 ( 5 . 712 + 9 . 1 . 711 )
= 511 [ 711 ( 5 . 7 + 9 . 1 . 1 ) ]
= 511 ( 711 . 44 )
= 511 . 711 . 44
= 3511 . 44
m. \(\left(x+2\right)\left(3-x\right)=0\Leftrightarrow\orbr{\begin{cases}x+2=0\\3-x=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-2\\x=3\end{cases}}\)
d. \(\frac{5^{11}.7^{12}+5^{11}.7^{11}}{5^{12}.7^{12}+9.5^{11}.7^{11}}=\frac{5^{11}.\left(7^{12}+7^{11}\right)}{5^{11}.\left(5.7^{12}+9.7^{11}\right)}=\frac{7^{12}+7^{11}}{5.7^{12}+9.7^{11}}=\frac{1}{5.9}=\frac{1}{45}\)
q. \(\left(x-3\right)+\left(x-2\right)+\left(x-1\right)+...+10+11=11\)
\(\Rightarrow\left(x-3\right)+\left(x-2\right)+\left(x-1\right)+...+10=0\)
\(\Rightarrow\left[\left(x-3\right)+\left(x-2\right)+\left(x-1\right)\right]+(1+2+3+...+10)=0\)
\(\Rightarrow\left(x-3\right)+\left(x-2\right)+\left(x-1\right)+55=0\)
\(\Rightarrow x-3+x-2+x-1=-55\)
\(\Rightarrow3x-6=-55\)
\(\Rightarrow3x=-49\)
\(\Rightarrow x=-\frac{49}{3}\)
a) (111+112+113+.......+118)
=(11+112)+(113+114)+(115+116)+(117+118)
=(11+11.11)+(113+113.11)+(115+115.11)+(117+117.11)
=11.(1+11)+113.(11+1)+115.(1+11)+117.(1+11)
=11.12+113.12+115.12+117.12
=(11+113+115+117).12 chia hết cho 12
=>đpcm
b) =7+72+73+74
=(7+73)+(72+74)
=7.(1+72)+72.(1+72)
=7.50+72.50
=50.(7+72) chia hết cho 50
=> đpcm
a,\(\frac{3^{10}.\left(-5\right)^{21}}{\left(-5\right)^{20}.3^{12}}=\frac{3^{10}.\left(-5\right).\left(-5\right)^{20}}{\left(-5\right)^{20}.3^{10}.3^2}\)\(=\frac{-5}{3^2}\)
b,\(\frac{-11^5.13^7}{11^5.13^8}=\frac{-11^5.13^7}{\left(-11\right)^5.\left(-1\right)^5.13^7.13}\)\(=\frac{1}{-1^5.13}\)
\(\frac{3^{10}.\left(-5\right)^{21}}{\cdot\left(-5\right)^{20}.3^{12}}=\frac{\left(-5\right)}{3^2}=\frac{-5}{9}\)
\(\frac{\left(-11\right)^5.13^7}{11^5.13^8}=\frac{-1}{13}\)
\(\frac{5^{11}.7^{12}.5^{11}.7^{11}}{5^{12}.7^{12}.9.5^{11}.7^{11}}\)=\(\frac{1}{45}\)