Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
mk viết đáp án, ko biết biến đổi ib mk
a) \(x^3+3x^2y-9xy^2+5y^3=\left(x+5y\right)\left(x-y\right)^2\)
b) \(x^4+x^3+6x^2+5x+5=\left(x^2+5\right)\left(x^2+x+1\right)\)
c) \(x^4-2x^3-12x^2+12x+36=\left(x^2-6\right)\left(x^2-2x-6\right)\)
d) \(x^8y^8+x^4y^4+1=\left(x^2y^2-xy+1\right)\left(x^2y^2+xy+1\right)\left(x^4y^4-x^2y^2+1\right)\)
câu a đặt chung x ra là xong
câu b
x^3 + 3x^2 - 7x^2 - 21x + 9x+ 27 còn lại tự làm nhé
a) x3 - 2x2 + x - xy2
= x (x2 - 2x + 1 - y2)
= x [(x2 - 2x + 1) - y2]
= x [(x - 1)2 - y2]
= x [(x - 1) + y] [(x - 1) - y]
= x (x - 1 + y) (x - 1 - y)
b) x3 - 4x2 - 12x + 27
= (x3 + 27) - (4x2 + 12x)
= (x3 + 33) - 4x (x + 3)
= (x + 3) (x2 - 3x + 32) - 4x (x + 3)
= (x + 3) [(x2 - 3x + 9) - 4x]
= (x + 3) (x2 - 3x + 9 - 4x)
= (x + 3) (x2 - 7x + 9)
#Học tôt!!!
~NTTH~
a) = (x3 +33) -4x(x+3)
= (x+3)(x2 -3x+9-4x)
= (x+3)(x2 - 7x +9)
a) \(x^2-2x-15\)
\(\Leftrightarrow x^2-2x+1-16\)
\(\Leftrightarrow\left(x-1\right)^2-4^2\)
\(\Leftrightarrow\left(x-5\right)\left(x-3\right)\)
\(a,x^2-2x-15=\left(x^2-2x+1\right)-16.\)
\(=\left(x-1\right)^2-4^2\)
\(=\left(x-5\right)\left(x+3\right)\)
a, \(x^4+6x^3+7x^2-6x+1\)
\(=x^4-2x^2+1+6x^3+9x^2+6x\)
\(=\left(x^2-1\right)^2+6x\left(x^2-1\right)+9x^2\)
\(=\left(x^2-1+3x\right)^2\)
b, \(x^4-7x^3+14x^2-7x+1\)
\(=x^4+2x^2+1+7x^3+12x^2-7x\)
\(=\left(x^2+1\right)^2-7x\left(x^2+1\right)+12^2\)
\(=\left(x^2-1+3x\right)^2\)
c, \(12x^2-11x-36\)
\(=12x^2-27x+16x-36\)
\(=3x\left(4x-9\right)+4\left(4x-9\right)\)
\(=\left(4x-9\right)\left(3x+4\right)\)
a) 12x3 + 4x2 + 9x + 3 = 4x2(3x + 1) + 3(3x + 1) = (4x2 + 3)(3x + 1)
b) x3 + 2x2 - x - 2 = x2(x + 2) - (x + 2) = (x2 - 1(x + 2) = (x - 1)(x + 1)(x + 2)
c) a3 + (a - b)3 = (a + a - b)[a2 - a(a - b) + (a - b)2] = (2a - b)(a2 - a2 + ab + a2 - 2ab + b2)
= (2a - b)(a2 - ab + b2)
a) 12x3 + 4x2 + 9x + 3
= 4x2(3x + 1) + 3(3x + 1)
= (4x2 + 3)(3x + 1)
b) x3 + 2x2 - x - 2
= x2(x + 2) - (x + 2)
= (x2 - 1)(x + 2)
c) a3 + (a - b)3
= a3 - a2(a - b) + a(a - b)2 + (a - b)a2 - (a - b)2a + (a - b)3
= a[(a2 - a(a - b) + (a - b)2] + (a - b)[a2 - a(a - b) + (a - b)2]
= (a + a - b)[(a2 - a(a - b) + (a - b)2]
a) \(A=x^2-2xy+y^2+3x-3y-4\)
\(=\left(x-y\right)^2-1+3x-3y-3\)
\(=\left(x-y-1\right)\left(x-y+1\right)+3\left(x-y-1\right)\)
\(=\left(x-y-1\right)\left(x-y+1+3\right)\)
\(=\left(x-y-1\right)\left(x-y+4\right)\)
\(x^4-2x^3-12x^2+12x+36=x^4+x^2+36-2x^3+12x-12x^2-x^2\)
\(=\left(x^2-x-6\right)^2-x^2=\left(x^2-6\right)\left(x^2-2x-6\right)\)
Phân tích đa thức thành nhân tử:
\(36-12x+x^2\)
\(=36-6x-6x+x^2\)
\(=\left(36-6x\right)-\left(6x-x^2\right)\)
\(=6\left(6-x\right)-x\left(6-x\right)\)
\(=\left(6-x\right)\left(6-x\right)=\left(6-x\right)^2\)
\(b,\left(x-6\right)^2\)
xin lỗi p a mk ko hiểu ý lắm