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\(\frac{1313}{1717}=\frac{1313:101}{1717:101}=\frac{13}{17}\)
\(\frac{131313}{171717}=\frac{131313:10101}{171717:10101}=\frac{13}{17}\)
\(\dfrac{1313}{1717}=\dfrac{101x13}{101x17}=\dfrac{13}{17}\)
\(\dfrac{131313}{171717}=\dfrac{10101x13}{10101x17}=\dfrac{13}{17}\)
Vậy \(\dfrac{1313}{1717}=\dfrac{131317}{171717}\)
\(\dfrac{1313}{1717}và\dfrac{131313}{171717}\\ \dfrac{1313}{1717}=\dfrac{13}{17}\\ \dfrac{131313}{171717}=\dfrac{13}{17}\\ \Rightarrow\dfrac{1313}{1717}=\dfrac{131313}{171717}\)
\(\dfrac{121212}{131313}=\dfrac{121212:10101}{131313:10101}=\dfrac{12}{13}=1-\dfrac{1}{13}\)
\(\dfrac{1313}{1414}=\dfrac{1313:101}{1414:101}=\dfrac{13}{14}=1-\dfrac{1}{14}\)
Vì \(\dfrac{1}{13}>\dfrac{1}{14}\) nên \(\dfrac{12}{13}< \dfrac{13}{14}\) hay \(\dfrac{1212}{1313}< \dfrac{1313}{1414}\)
b) \(\dfrac{1717}{2525}=\dfrac{1717:101}{2525:101}=\dfrac{17}{25}=\dfrac{51}{75}\)
\(\dfrac{515151}{727272}=\dfrac{515151:10101}{727272:10101}=\dfrac{51}{72}\)
Vì \(\dfrac{51}{75}< \dfrac{51}{72}\) nên \(\dfrac{17}{25}< \dfrac{51}{72}\) hay \(\dfrac{1717}{2525}< \dfrac{515151}{727272}\)
a) \(\dfrac{1212}{1313}=\dfrac{101x12}{101x13}=\dfrac{12}{13}< \dfrac{12+1}{13+1}=\dfrac{13}{14}\)
\(\dfrac{1313}{1414}=\dfrac{101x13}{101x14}=\dfrac{13}{14}\)
Vậy \(\dfrac{1212}{1313}< \dfrac{1313}{1414}\)
Làm tương tự câu b
A)1212/1313<1313/1414.B)1717/2525<515151/727272.23/28,7/9,5/7,11/18
A = \(\dfrac{1414+1515+1616+1717+1818+1919}{2020+2121+2022+2323+2424+2525}\)
A = \(\dfrac{101\times\left(14+15+16+17+18+19\right)}{101\times\left(20+21+22+23+24+25\right)}\)
A = \(\dfrac{99}{135}\)
A = \(\dfrac{11}{15}\)
Gọi số cần tìm là x, theo đề bài, ta có:
2017 x 101 - 201,7 - x = 201,7 x 500 x 2
= 203 717 - 201,7 - x = 201,7 x (500 x 2)
= 203 515,3 - x = 201,7 x 1000
= 203 515,3 - x = 201700
= x = 203 515,3 - 201700
= x = 1815,3
⇒ x = 201,7 x 9
⇒ Vậy số cần tìm là 1815,3 hoặc 201,7 x 9.
a, 20 x 5 - 20/20
= 100 - 1 =99
b, 1717 - 101/2525 + 707
= 2424 - 1/25
= 60599/25
vì 13x101=1313; 17x101=1717