Question

[M r . V ô D a n h]

giải chi tiết luôn

Answer 1

[hnamyuh]

2.

\(\dfrac{1}{3}-\dfrac{2}{5}+3x=\dfrac{3}{4}\\ \text{⇔}-\dfrac{1}{15}+3x=\dfrac{3}{4}\\ \text{⇔}3x=\dfrac{3}{4}+\dfrac{1}{15}=\dfrac{49}{60}\\ \text{⇔}x=\dfrac{49}{180}\)

4.

\(\dfrac{3}{2}-4\left(\dfrac{1}{4}-x\right)=\dfrac{2}{3}-7x\\ \text{⇔}\dfrac{3}{2}-1+4x=\dfrac{2}{3}\\ \text{⇔}4x+\dfrac{1}{2}=\dfrac{2}{3}\\ \text{⇔}4x=\dfrac{1}{6}\\ \text{⇔}x=\dfrac{1}{24}\)

6.

\(4\left(\dfrac{1}{2}-x\right)-5\left(x-\dfrac{3}{10}\right)=\dfrac{7}{4}\\ \text{⇔}2-4x-5x+\dfrac{15}{10}=\dfrac{7}{4}\\ \text{⇔}\dfrac{7}{2}-9x=\dfrac{7}{4}\\ \text{⇔}9x=\dfrac{7}{4}\\ \text{⇔}x=\dfrac{7}{36}\)

8.

\(3-2x-\dfrac{1}{3}=7x-\dfrac{1}{4}\\ \text{⇔}9x-\dfrac{35}{12}=0\\ \text{⇔}x=\dfrac{35}{108}\)

10.

\(-\dfrac{15}{2}+\dfrac{1}{4}+4x-2=1\\ \text{⇔}4x=\dfrac{41}{4}\\ \text{⇔}x=\dfrac{41}{16}\)

12.

\(\dfrac{2}{5}-\dfrac{1}{3}x+\dfrac{1}{6}=\dfrac{1}{4}\\ \text{⇔}\dfrac{17}{30}-\dfrac{1}{3}x=\dfrac{1}{3}\\ \text{⇔}\dfrac{1}{3}x=\dfrac{7}{30}\\ \text{⇔}x=\dfrac{7}{10}\)

14.

\(-1+\dfrac{2}{3}x=\dfrac{1}{8}-\dfrac{1}{6}\\ \text{⇔}\dfrac{2}{3}x=\dfrac{23}{24}\\ \text{⇔}x=\dfrac{23}{16}\)

Answer 2

[M r . V ô D a n h]

giúp với :(((