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VN
Võ Ngọc Phương
VIP
24 tháng 7 2023
\(\dfrac{15}{16}:\dfrac{5}{8}\times\dfrac{3}{4}\)
\(=\dfrac{15}{16}\times\dfrac{8}{5}\times\dfrac{3}{4}\)
\(=\dfrac{3}{2}\times\dfrac{3}{4}\)
\(=\dfrac{9}{8}\)
_________________
\(\dfrac{21}{4}\times\dfrac{16}{14}\times\dfrac{1}{2}\times\dfrac{8}{3}\)
\(=6\times\dfrac{4}{3}\)
\(=8\)
HK
2
NH
24 tháng 9 2023
`x xx4/5 :2=6/7`
`x xx 4/5xx1/2=6/7`
`x xx2/5=6/7`
`x=6/7:2/5`
`x=6/7xx5/2`
`x=15/7`
b)
`6/5:x:5/4=10/15`
`6/5:x xx4/5=2/3`
`6/5:x=2/3:4/5`
`6/5:x=2/3xx5/4`
`6/5:x=5/6`
`x=6/5:5/6`
`x=6/5xx6/5`
`x=36/25`
KV
24 tháng 9 2023
a) x × 4/5 : 2 = 6/7
x × 4/5 = 6/7 × 2
x × 4/5 = 12/7
x = 12/7 : 4/5
x = 15/7
b) 6/5 : x : 5/4 = 10/15
6/5 : x : 5/4 = 2/3
6/5 : x = 2/3 × 5/4
6/5 : x = 5/6
x = 6/5 : 5/6
x = 36/25
MN
24 tháng 4 2021
a, 1. \(\dfrac{2}{17}\)
2. \(22\)
3. 4
b,
1. \(\dfrac{8}{5}\)
2. \(\dfrac{176}{5}\)
3. \(\dfrac{28}{5}\)
4. \(\dfrac{3}{10}\)
5. \(\dfrac{163}{5}\)
6. \(\dfrac{9}{20}\)
24 tháng 4 2021
a) \(\dfrac{12}{17}:6=\dfrac{12}{17}\cdot\dfrac{1}{6}=\dfrac{2}{17}\)
DT
2
15 tháng 4 2023
\(\dfrac{5}{3}\times\dfrac{15}{8}-\dfrac{9}{8}\times\dfrac{5}{8}-\dfrac{5}{3}\)
\(=\dfrac{5}{3}\times\left(\dfrac{15}{8}-\dfrac{9}{8}-1\right)\)
\(=\dfrac{5}{3}\times\left(\dfrac{15}{8}-\dfrac{9}{8}-\dfrac{8}{8}\right)\)
\(=\dfrac{5}{3}\times\dfrac{-1}{4}\)
\(=-\dfrac{5}{12}\)
18 tháng 3 2023
a: \(\Leftrightarrow\dfrac{32}{x}=\dfrac{2}{15}+\dfrac{2}{35}+...+\dfrac{2}{99}\)
=>32/x=1/3-1/5+1/5-1/7+...+1/9-1/11
=>32/x=1/3-1/11=8/33
=>x=32:8/33=132
b: \(\Leftrightarrow1-\dfrac{1}{6}+1-\dfrac{1}{12}+...+1-\dfrac{1}{56}=\dfrac{x}{16}\)
\(\Leftrightarrow6-\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{7}-\dfrac{1}{8}\right)=\dfrac{x}{16}\)
=>x/16=6-1/2+1/8=11/2+1/8=45/8=90/16
=>x=90
c: \(\Leftrightarrow\dfrac{22}{x}=\left(1-\dfrac{1}{2}\right)\left(1+\dfrac{1}{2}\right)\cdot\left(1-\dfrac{1}{3}\right)\left(1+\dfrac{1}{3}\right)\cdot...\cdot\left(1-\dfrac{1}{10}\right)\left(1+\dfrac{1}{10}\right)\)
=>22/x=1/2*2/3*...*9/10*3/2*4/3*...*11/10
=>22/x=1/10*11/2=11/20=22/40
=>x=40
23 tháng 12 2023
a: \(1-\left(5\dfrac{4}{9}+a-7\dfrac{7}{18}\right):15\dfrac{3}{4}=0\)
=>\(\left(5+\dfrac{4}{9}+a-7-\dfrac{7}{18}\right):\dfrac{63}{4}=1\)
=>\(\left(a-2+\dfrac{1}{18}\right)=\dfrac{63}{4}\)
=>\(a-\dfrac{35}{18}=\dfrac{63}{4}\)
=>\(a=\dfrac{63}{4}+\dfrac{35}{18}=\dfrac{637}{36}\)
b: \(B=\left(\dfrac{2}{15}+\dfrac{5}{3}-\dfrac{3}{5}\right):\left(4\dfrac{2}{3}-2\dfrac{1}{2}\right)\)
\(=\dfrac{2+5\cdot5-3^2}{15}:\left(4+\dfrac{2}{3}-2-\dfrac{1}{2}\right)\)
\(=\dfrac{2+4^2}{15}:\left(2+\dfrac{2}{3}-\dfrac{1}{2}\right)\)
\(=\dfrac{18}{15}:\dfrac{13}{6}=\dfrac{6}{5}\cdot\dfrac{6}{13}=\dfrac{36}{65}\)
BU
6 tháng 4 2022
\(\dfrac{\left(\dfrac{5}{30}+\dfrac{3}{30}+\dfrac{2}{30}\right):\left(\dfrac{5}{30}+\dfrac{3}{30}-\dfrac{2}{30}\right)}{\left(\dfrac{30}{60}-\dfrac{20}{60}+\dfrac{15}{60}-\dfrac{12}{60}\right):\left(\dfrac{3}{12}-\dfrac{2}{12}\right)}=\dfrac{\dfrac{1}{3}:\dfrac{1}{5}}{\dfrac{13}{60}:\dfrac{1}{12}}=\dfrac{\dfrac{1}{3}\times5}{\dfrac{13}{60}\times12}=\dfrac{\dfrac{5}{3}}{\dfrac{13}{5}}=\dfrac{25}{39}\)
VH
2
AH
Akai Haruma
Giáo viên
11 tháng 6 2021
\(\frac{3}{4}+\frac{1}{2}+\frac{3}{2}=\frac{3}{4}+\frac{2}{4}+\frac{6}{4}=\frac{3+2+6}{4}=\frac{11}{4}\) em nhé.
11 tháng 6 2021
\(\dfrac{3}{4}+\dfrac{1}{6}\times3+\dfrac{2}{5}:\dfrac{4}{15}\)
\(=\dfrac{3}{4}+\dfrac{1}{2}+\dfrac{2}{5}\times\dfrac{15}{4}\)
\(=\dfrac{3}{4}+\dfrac{1}{2}+\dfrac{3}{2}\) \(=\dfrac{3+2+3}{4}=\dfrac{8}{4}=2\)
\(\dfrac{4}{15}.\dfrac{15}{2}=\dfrac{4.15}{15.2}=\dfrac{60}{30}=2\)
\(\dfrac{4}{15}\)\(\times\) \(\dfrac{15}{2}\) \(=\) \(\dfrac{4\times15}{15\times2}\) \(=\) \(\dfrac{60}{30}\) \(=\) \(2\)