Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\frac{21^2.14.126}{35^5.6}\)
\(=\frac{21^2.14.21.6}{35^5.6}\)
\(=\frac{3^3.7^3.7.2}{35^5}\)
\(=\frac{3^3.7^4.2}{5^4.7^4.35}\)
\(=\frac{9.2}{5^4.35}=\frac{18}{21875}\)
\(C=\frac{21^2.14.126}{35^5.6}=\frac{3^2.7^2.2.7.2.3^2.7}{5^5.7^5.2.3}=\frac{3^4.7^4.2^2}{5^5.7^5.2.3}=\frac{3^3.1.2}{5^5.4.1.1}=\frac{54}{12500}=\frac{27}{6250}\)
Tính các tổng dưới đây sau khi đã rút gọn phân số :
a)\(\dfrac{7}{21}\) + \(\dfrac{9}{-36}\) = \(\dfrac{7}{21}\)+\(\dfrac{-9}{36}\)=\(\dfrac{1}{3}\)+\(\dfrac{-1}{4}\)=\(\dfrac{4}{12}\)+\(\dfrac{-3}{12}\)=\(\dfrac{1}{12}\)
b) \(\dfrac{-12}{18}\)+\(\dfrac{-21}{35}\)=\(\dfrac{-2}{3}\)+\(\dfrac{-3}{5}\)=\(\dfrac{-10}{15}\)+\(\dfrac{-9}{15}\)=\(\dfrac{-19}{15}\)
c) \(\dfrac{-3}{21}\)+\(\dfrac{6}{42}\)=\(\dfrac{-1}{7}\)+\(\dfrac{1}{7}\)=0
d) \(\dfrac{-18}{24}\)+\(\dfrac{15}{-21}\)=\(\dfrac{-18}{24}\)+\(\dfrac{-15}{21}\)=\(\dfrac{-3}{4}\)+\(\dfrac{-5}{7}\)=\(\dfrac{-21}{28}\)+\(\dfrac{-20}{28}\)=\(\dfrac{-41}{28}\)
\(A=\dfrac{21^2.14.125}{35^5.6}=\dfrac{3^2.7^2.2.7.5^3}{7^5.5^5.2.3}=\dfrac{3^2.7^3.2.5^3}{7^5.5^5.2.3}=\dfrac{3}{7^2.5^2}=\dfrac{3}{1225}\)
\(\dfrac{-8}{12}=\dfrac{-8:4}{12:4}=\dfrac{-2}{3}\\ \dfrac{15}{-60}=\dfrac{15:15}{-60:15}=\dfrac{1}{-4}\\ \dfrac{-16}{-72}=\dfrac{-16:\left(-8\right)}{-72:\left(-8\right)}=\dfrac{2}{9}\\ \dfrac{35}{14.15}=\dfrac{5.7}{7.2.5.3}=\dfrac{1}{2.3}=\dfrac{1}{6}\)
\(\dfrac{-12}{-4}=\dfrac{-3}{-1}\)
\(\dfrac{7}{-35}=\dfrac{1}{-5}\)
\(\dfrac{-9}{27}=\dfrac{-1}{3}\)
Rút gọn các phân số sau:
\(\dfrac{{ - 12}}{{ - 4}}\);\(\dfrac{7}{{ - 35}}\); \(\dfrac{{ - 9}}{{27}}\)
\(\dfrac{{ - 12}}{{ - 4}} = \dfrac{{ - 12:\left( { - 4} \right)}}{{\left( { - 4} \right):\left( { - 4} \right)}} = 3\)
\(\dfrac{7}{{ - 35}} = \dfrac{{7:\left( { - 7} \right)}}{{ - 35:\left( { - 7} \right)}} = \dfrac{{ - 1}}{5}\)
\(\dfrac{{ - 9}}{{27}} = \dfrac{{ - 9:9}}{{27:9}} = \dfrac{{ - 1}}{3}\)
\(\dfrac{14}{21}=\dfrac{7\cdot2}{7\cdot3}=\dfrac{2}{3}\)
\(\dfrac{-36}{48}=\dfrac{-12\cdot3}{12\cdot4}=-\dfrac{3}{4}\)
\(\dfrac{28}{-52}=\dfrac{7\cdot4}{-4\cdot13}=-\dfrac{7}{13}\)
\(\dfrac{-54}{-90}=\dfrac{-18\cdot3}{-18\cdot5}=\dfrac{3}{5}\)
\(\dfrac{14}{21}\) =\(\dfrac{2}{3}\)
\(\dfrac{-36}{48}\) =\(\dfrac{3}{4}\)
\(\dfrac{28}{-52}\)=\(\dfrac{7}{-13}\)
\(\dfrac{-54}{-90}\) =\(\dfrac{6}{9}=\dfrac{2}{3}\)
\(\frac{21^2.14.125}{35^5.6}=\frac{\left(3.7\right)^2.7.2.5^3}{\left(5.7\right)^5.2.3}=\frac{3^2.7^2.7.2.5^3}{5^5.7^5.2.3}\)
\(=\frac{3^2.7^3.2.5^3}{5^5.7^5.2.3}=\frac{3.1.1.1}{5^2.7^2.1.1}\)
\(=\frac{3}{35^2}=\frac{3}{1225}\)
\(\dfrac{21^2.14.126}{35^5.6}\)
= \(\dfrac{3^2.7^2.7.2.3.7.6}{5^5.7^5.6}\)
= \(\dfrac{3^3.7^4.2}{5^5.7^5}\)
= \(\dfrac{3^3.2}{5^5.7}\)