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17 tháng 4 2021
\(\frac{21^2.14.125}{35^5.6}=\frac{\left(3.7\right)^2.7.2.5^3}{\left(5.7\right)^5.2.3}=\frac{3^2.7^2.7.2.5^3}{5^5.7^5.2.3}\)
\(=\frac{3^2.7^3.2.5^3}{5^5.7^5.2.3}=\frac{3.1.1.1}{5^2.7^2.1.1}\)
\(=\frac{3}{35^2}=\frac{3}{1225}\)
HT
6
29 tháng 11 2017
G=(212.14.125):355.6
=\(\frac{\left(3.7\right)^2.7.2.5^{^3}}{\left(7.5\right)^5.2.3}\)=\(\frac{3^2.7^2.7.5^3}{7^5.5^5.3}\)=\(\frac{3}{7^2.5^2}\)=\(\frac{3}{49.25}\)=\(\frac{3}{1225}\)
29 tháng 11 2017
\(G=\frac{21^2.14.125}{35^5.6}\)
\(G=\frac{\left(3.7\right)^2.7.2.5^3}{\left(7.5\right)^5.2.3}=\frac{3}{7^2.5^2}=\frac{3}{49.25}=\frac{3}{1225}\)
Y
1
8 tháng 5 2019
=\(\frac{-20}{21}.\left(\frac{22}{35}+\frac{13}{35}\right)+\frac{-22}{21}\)
=\(\frac{-20}{21}.\left(\frac{35}{35}\right)+\frac{-22}{21}\)
=\(\frac{-20}{21}+\frac{-22}{21}\)
=\(\frac{-42}{21}\)=-2
AK
10 tháng 4 2018
\(A=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{5.6}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{5}-\frac{1}{6}\)
\(A=1-\frac{1}{6}\)
\(A=\frac{6}{6}-\frac{1}{6}\)
\(A=\frac{5}{6}\)
\(B=\frac{1}{10}+\frac{1}{15}+...+\frac{1}{120}\)
\(B=2.\left(\frac{1}{20}+\frac{1}{30}+...+\frac{1}{240}\right)\)
\(B=2.\left(\frac{1}{4.5}+\frac{1}{5.6}+..+\frac{1}{15.16}\right)\)
\(B=2.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{15}-\frac{1}{16}\right)\)
\(B=2.\left(\frac{1}{4}-\frac{1}{16}\right)\)
\(B=2.\left(\frac{4}{16}-\frac{1}{16}\right)\)
\(B=2.\frac{3}{16}\)
\(B=\frac{3}{8}\)
Chúc bạn học tốt !!!
10 tháng 4 2018
\(A=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{5.6}\)
\(A=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{5}-\frac{1}{6}\)
\(A=\frac{1}{1}-\frac{1}{6}\)
\(A=\frac{5}{6}\)
\(B=\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+...+\frac{1}{120}\)
\(B=\frac{2}{20}+\frac{2}{30}+\frac{2}{42}+...+\frac{2}{240}\)
\(B=\frac{2}{4.5}+\frac{2}{5.6}+\frac{2}{6.7}+...+\frac{2}{15.16}\)
\(B=2\left(\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+...+\frac{1}{15.16}\right)\)
\(B=2.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+...+\frac{1}{15}-\frac{1}{16}\right)\)
\(B=2.\left(\frac{1}{4}-\frac{1}{16}\right)\)
\(B=2.\frac{3}{16}\)
\(B=\frac{6}{16}=\frac{3}{13}\)
\(\frac{21^2.14.126}{35^5.6}\)
\(=\frac{21^2.14.21.6}{35^5.6}\)
\(=\frac{3^3.7^3.7.2}{35^5}\)
\(=\frac{3^3.7^4.2}{5^4.7^4.35}\)
\(=\frac{9.2}{5^4.35}=\frac{18}{21875}\)
\(C=\frac{21^2.14.126}{35^5.6}=\frac{3^2.7^2.2.7.2.3^2.7}{5^5.7^5.2.3}=\frac{3^4.7^4.2^2}{5^5.7^5.2.3}=\frac{3^3.1.2}{5^5.4.1.1}=\frac{54}{12500}=\frac{27}{6250}\)